streamFlow | light weight stream operator for arduino
kandi X-RAY | streamFlow Summary
kandi X-RAY | streamFlow Summary
Simple and light-weight stream operator for Arduino framework.
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streamFlow Examples and Code Snippets
Community Discussions
Trending Discussions on streamFlow
QUESTION
ANSWER
Answered 2021-May-23 at 19:04We could use a couple of options i.e. get the names
of the data with the corresponding index, convert to sym
bol and evaluate (!!
)
QUESTION
I have a nested list with dates and river streamflow data (Flow) in different river reaches (910, 950, 1012, 1087):
...ANSWER
Answered 2021-May-21 at 19:26Flowtest1
isn't a dataframe, just a list of two vectors, so you can't use bracket notation to subset both vectors at once. Also, dates_FF
is created with two arguments instead of a vector, so it doesn't work. as.Date
is vectorized, so if you just make the two input dates a vector it will work. This returns what you want with no need for Flowtest1
QUESTION
I am trying to run a function to download data from the USGS website using dataRetrieval
package of R and a function I have created called getstreamflow
. The code is the following:
ANSWER
Answered 2021-May-17 at 20:34Based on the image showed in the new data, each element in the list
is nested as a list. We can extract the list
element (of length 1) with [[1]]
and then apply the Filter
QUESTION
I am trying to download data from the USGS website using the dataRetrieval
package of R.
For that purpose, I have generated a function called getstreamflow
in R that works fine when I ran for example.
ANSWER
Answered 2021-May-17 at 14:37Answer
You wrote the tryCatch
outside of getstreamflow
. Hence, if one site fails, then getstreamflow
will return an error and nothing else. You should either supply 1 site at a time, or put the tryCatch
inside getstreamflow
.
Example
QUESTION
I'm working on hydrological data in nested tables. Besides streamflow (Q) I have dates split into 3 columns (one for days, second for months and third for year).
...ANSWER
Answered 2021-Apr-26 at 15:16Since it's a nested list use nested lapply
:
QUESTION
How to count the number of values per column above a sequence of thresholds ?
i.e.: calculate for each column, the number of values above 100, then above 150, then above ... and store the results in a data frame ?
...ANSWER
Answered 2021-Feb-10 at 02:42myseq <- seq(75, 400, by=25)
as.data.frame(do.call(rbind, lapply(data, function(z) table(findInterval(z, myseq)))))
# 0 1 2 3 4 5 6 7 8 9 10 11 12 13
# X1915 17 19 26 27 41 23 26 33 27 22 30 25 21 28
# X1916 14 26 20 28 25 26 22 23 35 28 26 30 22 40
# X1917 20 30 24 31 24 28 22 25 28 34 18 21 26 34
QUESTION
I’m analyzing river streamflow data with R language and I have a list of data frames. Each data frame represents a subbasin (910, 950, 1012 and 1087) and has the exact same structure and number of variables and contains a value of IHA indicators (IHA1, IHA2) per Year (2004:2007)
...ANSWER
Answered 2020-Nov-10 at 21:04Hi Joanna a possible solution would be this:
QUESTION
This seems really simple, yet I can't find an easy solution. I'm working with future streamflow projections for every day of a 25 year period (2024-2050). I'm only interested in streamflow during the 61 day period between 11th of April and 10th of June each year. I want to extract the data from the seq and Data column that are within this period for each year and have it in a data frame together.
Example data:
...ANSWER
Answered 2020-Nov-08 at 22:50Here is an option. Do a group by year
of the 'seq_x', then summarise
to create a list
column by subsetting 'Data' based on the first
and last
elements of 'seq_x' and select
the column
QUESTION
I’m analyzing river streamflow data with R language and I have two nested lists. First holds data (Flowtest) from different river reaches called numbers such as 910, 950, 1012 and 1087. I have hundreds of daily streamflow measurements (Flow), but as I’m preparing yearly statistics the exact day and month doesn’t matter. Each measurement (Flow) is referenced to a year (Year) in the Flowtest table.
...ANSWER
Answered 2020-Oct-29 at 01:20You can use combination of Map
with aggregate
:
QUESTION
I am doing a time-series analysis where I need to calculate the change in several attributes over time. Pandas makes a simple version of this easy; the .diff(periods=n) function will calculate the difference between a row and the preceding n rows, however, that is not quite what I need...
...ANSWER
Answered 2020-Oct-26 at 03:52sum of the single day differences over a span of n days
First, diff
consecutive rows then do a rolling sum. Since the series after diff
already has difference for 2 consecutive rows, for rolling sum we only provide period-1
(in our case 3-1 = 2
).
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