succinct | A collection of succinct data structures | Build Tool library
kandi X-RAY | succinct Summary
kandi X-RAY | succinct Summary
This library contains the implementation of some succinct data structures. It is rather undocumented now, but better documentation is under way. On the other hand, the code is quite extensively unit-tested. The library is meant to be imported as a git submodule in other projects and then included as a CMake subdirectory. See the unit tests, and the [semi_index] and [path_decomposed_tries] projects for examples.
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Trending Discussions on succinct
QUESTION
I have a dataset with many columns and I'd like to locate the columns that have fewer than n unique responses and change just those columns into factors.
Here is one way I was able to do that:
...ANSWER
Answered 2021-Jun-15 at 20:29Here is a way using tidyverse
.
We can make use of where
within across
to select the columns with logical short-circuit expression where we check
- the columns are
numeric
- (is.numeric
) - if the 1 is TRUE, check whether number of distinct elements less than the user defined n
- if 2 is TRUE, then check
all
theunique
elements in the column are 0 and 1 - loop over those selected column and convert to
factor
class
QUESTION
I have an if statement in Ruby that combines the == and || operators, and it's quite verbose. What would be a more succinct way to write this:
...ANSWER
Answered 2021-Apr-08 at 23:22hierarchy = "Chapter" if ["1.0", "2.0", "3.0", "4.0", "5.0"].include?(number)
QUESTION
So, I have a function f that takes a string as input. I want to create a function g that maps f to a vector of strings. I.e.
g 'Hello' 'world'
should yield
(f 'Hello')(f 'world')
Here's what I did:
...ANSWER
Answered 2021-Jun-10 at 21:26You're looking for ⊆
QUESTION
I'm trying to find a way of checking if I am on the last element of an iterator in a for loop without using .clone(); currently I'm doing this:
...ANSWER
Answered 2021-Jun-07 at 13:56For the general case of finite iterators, if you want to get the last item, you can, as suggests @Masklinn (see their answer), convert to a Peekable
which will buffer so it always knows the next element.
In your precise case, when you just want to print the last word and don't care about the other ones, there is a much cheaper solution because splitting on a character implements DoubleEndedIterator
.
So it's easy to get the last word, you don't have to collect the whole split nor to enumerate. It's also fast as the string will be searched from the end and nothing will be copied.
So you can do
QUESTION
I have a set of field names as follows:
...ANSWER
Answered 2021-Jun-01 at 15:12is it possible to use wildcards for field names in mongodb?
No.
If your data is in this structure, refactor it to use lists. That's exactly what lists are desgined for.
Taking the refactored example below, Use $elemMatch
to project only the array elements needed:
QUESTION
I'm trying to conditionally add a few classes in React like this....
...ANSWER
Answered 2021-May-31 at 01:03Use multiple ${}
s to interpolate. Make sure to put a space between the }
and the ${
next to it.
QUESTION
I have structures defined as:
...ANSWER
Answered 2021-May-27 at 13:13In Julia 1.6 and later you can use sum(vec; init = val)
.
In older versions you can use reduce(+, vec; init = val)
or foldl(+, vec; init = val)
if +
is non associative.
If you want to keep enumeration, then you can do something like foldl((acc, i) -> vec[i] + acc, 1:length(vec); init = val)
or equivalently
QUESTION
We have a bunch of .bat
build scripts which are invoked by a PowerShell based GitLab runner that were recently refactored from:
ANSWER
Answered 2021-Feb-17 at 21:06Let's look at the three possible scenarios:
QUESTION
I have a dataframe containing some values where I would like to check for each column, count the number of times a logical condition is met. I can manage this in base R, however I am struggling with the dplyr package.
An example dataframe:
...ANSWER
Answered 2021-May-25 at 15:48I'm going to use 2 * A:D + X
, since - X
produces nothing. Your expected output better matches +
anyway ...
QUESTION
Wasn't quite sure how to word the question succinctly, so I hope the above image helps to illustrate what I'm trying to accomplish.
I'm developing sites using Bootstrap and our designer keeps throwing curveballs at us. At first, the absolute element in the example used to just be a solid color extending to the edge of the viewport--ezpz, just use overflow:hidden somewhere and make the element 9999px wide, no problem. But now we're beginning to use pictures and gradients inside of these suckers, where I will need to know where the edge of the screen is, or otherwise cut off some of the image or only see a portion of the gradient.
I am fully aware that I am able to accomplish this with JS and some simple math, but I would like to know if there are any solutions using styles that can get the job done. I tend to develop sites using a very black and white approach wherever possible and view using JS to handle "styling" as a hack, rather than a solution. It feels like I'm brute forcing something that should have a way to finesse it. So I'm more or less just curious if there is a solution that will make my brain a little happier, rather than "how do I do this plz?"
Here's a fiddle, specifically showing the issue with a gradient. Example 1 with solid black works great. Example 2 with a gradient is too wide and basically just looks red (but would look great on a monitor with 20k pixel width!). I'm wondering if there's maybe some clever use of the vw unit that would solve this?
...ANSWER
Answered 2021-May-20 at 22:35If your "rail" has a fixed width, this is as simple as a 3-part calc.
0.5 * viewport width - 0.5 * rail width + parent container width
E.g.
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