EMST | Solving Euclidean Minimal Spanning Tree | Dataset library

 by   qinyao-he C++ Version: Current License: No License

kandi X-RAY | EMST Summary

kandi X-RAY | EMST Summary

EMST is a C++ library typically used in Artificial Intelligence, Dataset, Example Codes applications. EMST has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Solving Euclidean Minimal Spanning Tree.
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              EMST has a low active ecosystem.
              It has 6 star(s) with 0 fork(s). There are 1 watchers for this library.
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              It had no major release in the last 6 months.
              There are 1 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of EMST is current.

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              EMST has no bugs reported.

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              EMST has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              EMST does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

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              EMST releases are not available. You will need to build from source code and install.

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            EMST Key Features

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            EMST Examples and Code Snippets

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            Community Discussions

            QUESTION

            What is the simplest, easiest algorithm for finding EMST of a complete graph of order 10^5
            Asked 2019-Mar-16 at 21:12

            I just want to be clear that EMST stands for Euclidean Minimum Spanning Tree.

            Essentially, I have been given a file with 100k 4D vertices (one vertex on each line). The goal is to visit every vertex in the file while minimizing the total distance traveled. The distance from a point to another point is simply the Euclidean Distance (Distance if you draw a Straight Line between two points".

            I already know that this is pretty much the Traveling Salesman Problem, which is NP Complete, so I am looking to approximate the solution.

            The first approximation algorithm that came to my mind is by finding the MST from a graph constructed from the file... But that would take O(N^2) to even just construct all the edges from the file given the fact that it's a complete graph ( I can go from any point to another ). And given that my input is N = 10^5, my algorithm will have a huge running time, which is too slow...

            Any ideas on how I can plan on approximating the solution? Thank you very much..

            ...

            ANSWER

            Answered 2019-Mar-16 at 21:12

            I am going to assume that you actually want a EMST as your title suggests, and the TSP is just a means to that end, and not the actual goal itself. The two have very different restrictions (the TSP being far more restrictive), and thus very different optimal solutions.

            Overview

            The idea is that we want to run a modified kruskal's algorithm, which will make use of a k-d tree to find the closest pairs without evaluating every potential edge. We can find the shortest edge to each vertex in a connected component, take the shortest overall, and connect our connected components via that edge. As you'll see, this connects at least half of our connected components each iteration, so it takes at most logn iterations to complete.

            Nearest Neighbor Search

            For constructing an EMST, you'll want to use a data structure for querying for nearest neighbors in 4D space. You could extend octrees to work in a higher dimension, but I'd personally go with a k-d tree. You can construct a k-d tree in O(nlogn) time using the median of medians algorithm to find the median at each level, and you can insert / remove from a balanced k-d tree in O(logn) time.

            Once you've built a k-d tree, you'll want to query for the nearest neighbor to each point. We'll then construct the edge between these two vertices. Many of these edges will be duplicated, as for some vertices A and B, A's nearest neighbor may be B, and B's nearest neighbor may be A. We'll handle this by storing which connected component each vertex belongs to, and after two vertices are joined by an edge, the duplicate edge will clearly connect two vertices of the same connected component, and so we'll discard it. To accomplish this, we'll use a disjoint-set (just like in many implementations of kruskal's algorithm) to assign a connected component to each vertex. This will also prevent us from creating cycles in our graph, which would introduce unnecessary edges in the MST.

            Merging

            However, as we construct each edge, we'll want to insert it into a min-heap priority queue before checking which edges to keep and which edges connect already-connected vertices. This will not affect the outcome of this first iteration, but later on we will need to handle edges by increasing distance. Then dequeue all the edges, check for unnecessary / redundant edges via the disjoint-set, insert valid edges into the MST, and merge the respective disjoint-sets. All of this of course introduces a nlogn factor for constructing and dequeuing elements from the min-heap (we could also just sort them in a plain array, if we wished).

            After this first iteration of adding edges, we'll have connected at least half of the MST, maybe more. This is because for each vertex we added one edge, and we can have at most one duplicate per edge, so we've added a few as vertices / 2 edges, but as many as vertices - 1. Now at least 1/2 of our MST has been built. We'll continue the process as described in the following paragraphs, until we've added vertices - 1 edges in total.

            Generalizing NN-Search

            To continue, we'll want to construct lists of the vertices in each connected component, so that we can iterate over them by groups. This can be done in nearly linear time, as searching (also merging) a disjoint-set takes O(α(n)) time (α being the inverse ackermann function) and we repeat exactly n times. Once we have our lists of vertices per connected component, the rest is fairly straightforward. We'll take our existing k-d tree, and remove all the vertices in our current connected component. We'll then query for the nearest neighbor to each vertex to each vertex in our connected component, and add these edges to our min-heap. We'll then add these vertices back into the k-d tree, and repeat on the next connected component. Since we insert/remove a total of n elements, this amounts to an average case O(nlogn) time complexity.

            Now that we have a queue of the shortest potential edges connecting our connected components, we'll dequeue these in order, and just as before insert valid edges and merge the disjoint sets. For the same reasons as before, this is guaranteed to connect at least half of our components, maybe even all of them. We'll repeat this process until we have connected all vertices into a single connected component, which will be our MST. Note that because we halve the number of disconnected components each iteration, it'll take at most O(logn) iterations to connect every vertex in our MST (most likely far less).

            Remarks

            Overall, this will take O(nlog^2(n)) time. There will likely be far less than log(n) iterations however, so expect a speedup there in practice. Also note that R-tree might be a good alternative to the k-d tree- I don't know how they compare in practice however.

            Source https://stackoverflow.com/questions/55192325

            QUESTION

            PHP Symfony DQL - Too few parameters: the query defines 1 parameters but you only bound 0
            Asked 2018-Aug-24 at 13:37

            i am trying to put together a SELECT in symfony repository project but for some reason getting error message in the subject. Been working on it for a few days but cannot find a solution with different variations of the code. This is the code

            ...

            ANSWER

            Answered 2018-Aug-24 at 13:37

            The short answer is that you need to actually call:

            Source https://stackoverflow.com/questions/52003733

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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