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kandi X-RAY | Memory Summary
kandi X-RAY | Memory Summary
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QUESTION
I have newly installed
...ANSWER
Answered 2021-Jul-28 at 07:22You are running the project via Java 1.8 and add the --add-opens
option to the runner. However Java 1.8 does not support it.
So, the first option is to use Java 11 to run the project, as Java 11 can recognize this VM option.
Another solution is to find a place where --add-opens
is added and remove it.
Check Run configuration in IntelliJ IDEA (VM options field) and Maven/Gradle configuration files for argLine
(Maven) and jvmArgs
(Gradle)
QUESTION
I was using pyspark on AWS EMR (4 r5.xlarge as 4 workers, each has one executor and 4 cores), and I got AttributeError: Can't get attribute 'new_block' on . Below is a snippet of the code that threw this error:
...
ANSWER
Answered 2021-Aug-26 at 14:53I had the same error using pandas 1.3.2 in the server while 1.2 in my client. Downgrading pandas to 1.2 solved the problem.
QUESTION
ANSWER
Answered 2022-Feb-17 at 10:47File->Settings->Tools->Emulator, and uncheck Launch in a tool window Then they will open in their own stand alone windows again.
QUESTION
When I open Android Studio I receive a notification saying that an update is available:
...ANSWER
Answered 2022-Feb-10 at 11:09This issue was fixed by Google (10 February 2022).
You can now update Android Studio normally.
Thank you all for helping to bring this problem to Google's attention.
QUESTION
When I use .Internal(inspect())
to NA_real_
and NaN
, it returns,
ANSWER
Answered 2021-Dec-24 at 10:45NA
is a statistical or data integrity concept: the idea of a "missing value". Eg if your data comes from people filling in forms, a bad entry or missing entry would be treated as NA
.
NaN
is a numerical or computational concept: something that is "not a number". Eg 0/0 is NAN
, because the result of this computation is undefined (but note that 1/0 is Inf
, or infinity, and similarly -1/0 is -Inf
).
The way that R handles these concepts internally isn't something that you should ever be concerned about.
QUESTION
I'm learning about different memory orders.
I have this code, which works and passes GCC's and Clang's thread sanitizers:
...ANSWER
Answered 2022-Jan-04 at 16:06The thread sanitizer currently doesn't support std::atomic_thread_fence
. (GCC and Clang use the same thread sanitizer, so it applies to both.)
GCC 12 (currently trunk) warns about it:
QUESTION
I'm studying for the final exam for my introduction to C++ class. Our professor gave us this problem for practice:
...Explain why the code produces the following output:
120 200 16 0
ANSWER
Answered 2021-Dec-13 at 20:55It does not default to zero. The sample answer is wrong. Undefined behaviour is undefined; the value may be 0, it may be 100. Accessing it may cause a seg fault, or cause your computer to be formatted.
As to why it's not an error, it's because C++ is not required to do bounds checking on arrays. You could use a vector and use the at
function, which throws exceptions if you go outside the bounds, but arrays do not.
QUESTION
Following a previous question of mine, most comments say "just don't, you are in a limbo state, you have to kill everything and start over". There is also a "safeish" workaround.
What I fail to understand is why a segmentation fault is inherently nonrecoverable.
The moment in which writing to protected memory is caught - otherwise, the SIGSEGV
would not be sent.
If the moment of writing to protected memory can be caught, I don't see why - in theory - it can't be reverted, at some low level, and have the SIGSEGV converted to a standard software exception.
Please explain why after a segmentation fault the program is in an undetermined state, as very obviously, the fault is thrown before memory was actually changed (I am probably wrong and don't see why). Had it been thrown after, one could create a program that changes protected memory, one byte at a time, getting segmentation faults, and eventually reprogramming the kernel - a security risk that is not present, as we can see the world still stands.
- When exactly does a segmentation fault happen (= when is
SIGSEGV
sent)? - Why is the process in an undefined behavior state after that point?
- Why is it not recoverable?
- Why does this solution avoid that unrecoverable state? Does it even?
ANSWER
Answered 2021-Dec-10 at 15:05When exactly does segmentation fault happen (=when is SIGSEGV sent)?
When you attempt to access memory you don’t have access to, such as accessing an array out of bounds or dereferencing an invalid pointer. The signal SIGSEGV
is standardized but different OS might implement it differently. "Segmentation fault" is mainly a term used in *nix systems, Windows calls it "access violation".
Why is the process in undefined behavior state after that point?
Because one or several of the variables in the program didn’t behave as expected. Let’s say you have some array that is supposed to store a number of values, but you didn’t allocate enough room for all them. So only those you allocated room for get written correctly, and the rest written out of bounds of the array can hold any values. How exactly is the OS to know how critical those out of bounds values are for your application to function? It knows nothing of their purpose.
Furthermore, writing outside allowed memory can often corrupt other unrelated variables, which is obviously dangerous and can cause any random behavior. Such bugs are often hard to track down. Stack overflows for example are such segmentation faults prone to overwrite adjacent variables, unless the error was caught by protection mechanisms.
If we look at the behavior of "bare metal" microcontroller systems without any OS and no virtual memory features, just raw physical memory - they will just silently do exactly as told - for example, overwriting unrelated variables and keep on going. Which in turn could cause disastrous behavior in case the application is mission-critical.
Why is it not recoverable?
Because the OS doesn’t know what your program is supposed to be doing.
Though in the "bare metal" scenario above, the system might be smart enough to place itself in a safe mode and keep going. Critical applications such as automotive and med-tech aren’t allowed to just stop or reset, as that in itself might be dangerous. They will rather try to "limp home" with limited functionality.
Why does this solution avoid that unrecoverable state? Does it even?
That solution is just ignoring the error and keeps on going. It doesn’t fix the problem that caused it. It’s a very dirty patch and setjmp/longjmp in general are very dangerous functions that should be avoided for any purpose.
We have to realize that a segmentation fault is a symptom of a bug, not the cause.
QUESTION
I am working on a "heartbeat" application that pings hundreds of IP addresses every minute via a loop. The IP addresses are stored in a list of a class Machines
. I have a loop that creates a Task
(where MachinePingResults
is basically a Tuple of an IP and online status) for each IP and calls a ping function using System.Net.NetworkInformation
.
The issue I'm having is that after hours (or days) of running, one of the loops of the main program fails to finish the Tasks
which is leading to a memory leak. I cannot determine why my Tasks are not finishing (if I look in the Task list during runtime after a few days of running, there are hundreds of tasks that appear as "awaiting"). Most of the time all the tasks finish and are disposed; it is just randomly that they don't finish. For example, the past 24 hours had one issue at about 12 hours in with 148 awaiting tasks that never finished. Due to the nature of not being able to see why the Ping
is hanging (since it's internal to .NET), I haven't been able to replicate the issue to debug.
(It appears that the Ping
call in .NET can hang and the built-in timeout fail if there is a DNS issue, which is why I built an additional timeout in)
I have a way to cancel the main loop if the pings don't return within 15 seconds using Task.Delay
and a CancellationToken
. Then in each Ping function I have a Delay
in case the Ping call itself hangs that forces the function to complete. Also note I am only pinging IPv4; there is no IPv6 or URL.
Main Loop
...ANSWER
Answered 2021-Nov-26 at 08:37There are quite a few gaps in the code posted, but I attempted to replicate and in doing so ended up refactoring a bit.
This version seems pretty robust, with the actual call to SendAsync
wrapped in an adapter class.
I accept this doesn't necessarily answer the question directly, but in the absence of being able to replicate your problem exactly, offers an alternative way of structuring the code that may eliminate the problem.
QUESTION
In short:
I have implemented a simple (multi-key) hash table with buckets (containing several elements) that exactly fit a cacheline. Inserting into a cacheline bucket is very simple, and the critical part of the main loop.
I have implemented three versions that produce the same outcome and should behave the same.
The mystery
However, I'm seeing wild performance differences by a surprisingly large factor 3, despite all versions having the exact same cacheline access pattern and resulting in identical hash table data.
The best implementation insert_ok
suffers around a factor 3 slow down compared to insert_bad
& insert_alt
on my CPU (i7-7700HQ).
One variant insert_bad is a simple modification of insert_ok
that adds an extra unnecessary linear search within the cacheline to find the position to write to (which it already knows) and does not suffer this x3 slow down.
The exact same executable shows insert_ok
a factor 1.6 faster compared to insert_bad
& insert_alt
on other CPUs (AMD 5950X (Zen 3), Intel i7-11800H (Tiger Lake)).
ANSWER
Answered 2021-Oct-25 at 22:53The TLDR is that loads which miss all levels of the TLB (and so require a page walk) and which are separated by address unknown stores can't execute in parallel, i.e., the loads are serialized and the memory level parallelism (MLP) factor is capped at 1. Effectively, the stores fence the loads, much as lfence
would.
The slow version of your insert function results in this scenario, while the other two don't (the store address is known). For large region sizes the memory access pattern dominates, and the performance is almost directly related to the MLP: the fast versions can overlap load misses and get an MLP of about 3, resulting in a 3x speedup (and the narrower reproduction case we discuss below can show more than a 10x difference on Skylake).
The underlying reason seems to be that the Skylake processor tries to maintain page-table coherence, which is not required by the specification but can work around bugs in software.
The DetailsFor those who are interested, we'll dig into the details of what's going on.
I could reproduce the problem immediately on my Skylake i7-6700HQ machine, and by stripping out extraneous parts we can reduce the original hash insert benchmark to this simple loop, which exhibits the same issue:
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