HexEdit | Catch22 HexEdit - Visit the Catch22 homepage

 by   strobejb C++ Version: Current License: MIT

kandi X-RAY | HexEdit Summary

kandi X-RAY | HexEdit Summary

HexEdit is a C++ library. HexEdit has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Visit the Catch22 homepage at. HexEdit program and sourcecode is released under the MIT open source licence. Please refer to LICENCE.TXT for licencing terms and conditions.
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              HexEdit has a low active ecosystem.
              It has 236 star(s) with 84 fork(s). There are 26 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 11 open issues and 0 have been closed. There are 4 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of HexEdit is current.

            kandi-Quality Quality

              HexEdit has no bugs reported.

            kandi-Security Security

              HexEdit has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              HexEdit is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              HexEdit releases are not available. You will need to build from source code and install.

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            HexEdit Key Features

            No Key Features are available at this moment for HexEdit.

            HexEdit Examples and Code Snippets

            No Code Snippets are available at this moment for HexEdit.

            Community Discussions

            QUESTION

            reading hexadecimal data from file in fortran
            Asked 2020-Jul-26 at 10:48

            In Fortran, I'm trying to read a file with data in 8-bit (hexadecimal) bytes, on Linux.

            In 'hexedit' the first line looks as it should, for the tiff-file it is.

            ...

            ANSWER

            Answered 2020-Jul-11 at 12:01

            Your read statement will simply read 2 characters for tifhead(1), the next 2 characters for tifhead(2), etc, including spaces. Therefore you end up with tifhead(1)="49", tifhead(2)=" 4", tifhead(3)="9 ", and so on. You think you read the first 2 bytes correctly only because you print the strings "49", " 4", "9 ",... one after the other, so it looks like "49 49 " in the output. The compiler has no way to know there is a single blank space separating strings and 2 spaces every four data.

            To read your data properly you must use formatted reading which implies you must also declare your stream as 'formatted' in the open statement. The following example shows how this can be done:

            Source https://stackoverflow.com/questions/62838105

            QUESTION

            Where in object file does the code of function "main" starts?
            Asked 2020-May-30 at 09:28

            I have an object file of a C program which prints hello world, just for the question. I am trying to understand using readelf utility or gdb or hexedit(I can't figure which tool is a correct one) where in the file does the code of function "main" starts.

            I know using readelf that symbol _start & main occurs and the address where it is mapped in a virtual memory. Moreover, I also know what the size of .text section and the of coruse where entry point specified, i.e the address which the same of text section.

            The question is - Where in the file does the code of function "main" starts? I tought that is the entry point and the offset of the text section but how I understand it the sections data, bss, rodata should be ran before main and it appears after section text in readelf.

            Also I tought we should sum the size all the lines till main in symbol table, but I am not sure at all if it is correct.

            Additional question which follow up this one is if I want to replace main function with NOP instrcutres or plant one ret instruction in my object file. how can I know the offset where I can do it using hexedit.

            ...

            ANSWER

            Answered 2020-May-30 at 09:28

            So, let's go through it step by step.

            Start with this C file:

            Source https://stackoverflow.com/questions/62088056

            QUESTION

            C# searching for extended ascii characters in string
            Asked 2020-May-09 at 23:28

            I have a file that I am searching for specific ascii characters.

            I ran the following code after getting the text from a file:

            var t = text.IndexOf((char)128);

            Hexedit shows I have characters of HEX 80 which is ascii character 128, but t ends up with a value of -1.

            Is there another way I should be searching for this character?

            ...

            ANSWER

            Answered 2020-May-09 at 23:28

            I found I had to my encoding appropriately like the following in order be able to search the string as I expect to. In my case it was the following:

            Source https://stackoverflow.com/questions/61671112

            QUESTION

            codesign an old Director projector on OS X 10.13 - perhaps manipulate __LINKEDIT segment value
            Asked 2019-Aug-05 at 09:10

            (See Updates at end of this post)

            For $reasons, I need to codesign an old Director projector that we can no longer re-publish (no access to original source code or to Director).

            I'm doing this because when run without being signed, the app now opens a Finder window with a prompt saying "Where is..." asking for a file that's one of the embedded projector resources.

            But... If I cd into the Projector.app contents (it's not really called that, but you get the idea) and find the projector binary inside Contents/MacOS/ and run this binary from terminal, the app launches and runs fine, once it's decompressed the (presumably) attached archive at the end of the binary...

            ...

            ANSWER

            Answered 2018-Feb-28 at 11:00

            DIrector uses a scheme widely used on Windows called "Overload". I attaches some data at the end of the physical file, but beyond the size of the executable image. This approach is not supported with Mach-O files. The physical image has to end with the last byte covered by the LINKEDIT segment, and even the order of items inside the LINKEDIT segment is well defined. Reason for this was prebinding in the past, now it is codesigning.

            The appended data is the initial DIR/DXR Directory wants to load first. I guess this has been fixed later by adding the DIR/DXR into the application bundle. But I am not anymore into Director, so I am not sure about this.

            Source https://stackoverflow.com/questions/48324224

            QUESTION

            Insert bytes into file using shell
            Asked 2019-Apr-24 at 02:44

            I would like to use a linux shell (bash, zsh, etc.) to insert a set of known bytes into a file at a certain position. Similar questions have been asked, but they modify in-place the bytes of a file. These questions don't address inserting new bytes at particular positions.

            For example, if my file has a sequence of bytes like \x32\x33\x35 I might want to insert \x34 at position 2 so that this byte sequence in the file becomes \x32\x33\x34\x35.

            ...

            ANSWER

            Answered 2019-Apr-24 at 02:44

            You can achieve this using head, tail and printf together. For example; to insert \x34 at position 2 in file:

            Source https://stackoverflow.com/questions/55821106

            QUESTION

            modify a byte in a binary file using standard linux command line tools
            Asked 2018-Nov-16 at 17:31

            I need to modify a byte in a binary file at a certain offset.

            Example:

            • Input file: A.bin
            • Output file: B.bin

            I need to read a byte at the offset 0x40c from A.bin, clear to 0 least significant 2 bits of this byte, and then write file B.bin equal to A.bin, but with the calculated byte at offset 0x40c.

            ...

            ANSWER

            Answered 2017-Jan-23 at 17:50
            # read 1 byte at offset 40C
            b_hex=$(xxd -seek $((16#40C)) -l 1 -ps A.bin -)
            # delete 3 least significant bits
            b_dec=$(($((16#$b_hex)) & $((2#11111000))))
            cp A.bin B.bin
            # write 1 byte back at offset 40C
            printf "00040c: %02x" $b_dec | xxd -r - B.bin
            

            Source https://stackoverflow.com/questions/41806280

            QUESTION

            is a jpeg with a bogus huffman table recoverable?
            Asked 2018-Oct-25 at 16:05

            I have a JPEG that is un-openable in any program:

            Opening in Ubuntu Image Viewer yields:

            Passing the photo through convert yields similar results:

            ...

            ANSWER

            Answered 2018-Oct-25 at 16:05

            The approach used to get this back was more luck than judgement. I think I can explain, though be aware it involves a hex editor...

            The Wikipedia page for the syntax of a JPEG file explains that it is made up of a series of segments each started by a two byte marker - 0xFF and another byte to indicate the type of segment.

            The hope was that it was just the Huffman table segment of the file that was wrong - as suggested by the error message. Without needing to understand what a Huffman table is, it was enough to see that the same section on Wikipedia explains it is a 0xFF 0xC4 marker for a Huffman table segment.

            Further down the page, it mentions:

            The JPEG standard provides general-purpose Huffman tables; encoders may also choose to generate Huffman tables...

            Opening up a few other JPEG files found what looks like a standard set of 4 consecutive Huffman table segments - each starting with that 0xFF 0xC4 marker. The sample corrupt.jpg however just had one Huffman table - from position 0x00c8 to 0x02bc below.

            (Both contain that &'()*56789:CDEFGHIJSTUVWXYZcdefghijstuvwxyz sequence you mentioned in their Huffman tables. In the corrupt file it appears twice in that single Huffman table, in the 'more conventional' JPEGs it appears in the second and fourth Huffman tables.)

            From there, the fixed image is a copy and paste of the standard 4 Huffman tables, in place of that range of bytes in corrupt.jpg - now from 0x00c8 to 0x0278 in the fixed file.

            Because the JPEG format is based around scanning for segments between those 0xff markers, you can just swap out the Huffman segments - there are no other pointers in the file to worry about. As you said, the rest of the file looked like a plausible JPEG.

            Summary of the steps taken:

            • Hex search the corrupt.jpg for FF C4 and note the offset
            • Hex search for the next FF. If it's another FF C4 (so a second Huffman table) keep going
            • Delete the content from the first FF C4 (included) up to but not including the next FF
            • Instead replace it with the 'standard 4 Huffman tables'. These are the bytes in the last sample below, or can be copied from 0x00c8 to 0x0278 in the fixed file

            Corrupt Huffman table:

            Source https://stackoverflow.com/questions/50181005

            QUESTION

            Read binary data from QProcess in Windows
            Asked 2018-Jul-29 at 05:15

            I have some .exe file (say some.exe) that writes to the standard output binary data. I have no sources of this program. I need to run some.exe from my C++/Qt application and read standard output of the process I created. When I'm trying to do this with QProcess::readAll someone replaces byte \n (0x0d) to \r\n (0x0a 0x0d).

            Here is a code:

            ...

            ANSWER

            Answered 2018-Jul-27 at 15:28

            Unfortunately it has nothing to do with QProcess or Windows or console. It's all about CRT. Functions like printf or fwrite are taking into account _O_TEXT flag to add an additional 0x0D (true only for Windows). So the only solution is to modify stdout's fields of your some.exe with WriteProcessMemory or call the _setmode inside an address space of your some.exe with DLL Injection technique or patch the lib. But it's a tricky job.

            Source https://stackoverflow.com/questions/51519654

            QUESTION

            Loading shaders in Monogame is impossible
            Asked 2018-Jun-06 at 17:11

            So I have this .fx file with HLSL code. The next step is to compile using 2MGFX.exe and this is where things go crazy. I can't run it on my computer at all.

            So then I tried fxc.exe - installing this alone was a little too hard - but it generates a header. So I started following along with this post. I started trying to remove the headers byte-by-byte with HexEdit, again to no avail. What further bothers me is that there might also be extra footers, not just headers. No matter what I do, my project absolutely refuses to load my .mgfxo file.

            I'm getting pretty fed-up with this process. Are there any other tools or methods I can employ? How about loading the file myself and feeding into the CPU myself?

            ...

            ANSWER

            Answered 2018-Jun-06 at 17:11

            You can actually use the Content Pipeline tool to use your shader directly. Open the tool and either add you .fx directly or create a new one (to ensure everything is good) and then copy paste yours on top of it.

            Source https://stackoverflow.com/questions/50538889

            QUESTION

            Elf representation in HEX
            Asked 2017-Sep-06 at 09:13

            I am working on understanding some ground concepts in embedded Systems. My question is similar to understand hexedit of an elf . In order to burn compiler output to ROM, the .out file is converted to HEX (say intel-hex). I wonder how the following informations are preserved in HEX format:

            1. Section header
            2. Symbol tables, debug symbols, linker symbols etc.
            3. Elf header.
            4. If these are preserved in HEX file, how they can be read from hex file?
            5. A bit out question but how the microcontroller on boot knows where .data .bss etc. exists in HEX and to be coppied to RAM?
            ...

            ANSWER

            Answered 2017-Sep-06 at 07:02

            None of that is preserved. A HEX file only contains the raw program and data. https://en.wikipedia.org/wiki/Intel_HEX

            The microcontroller does not know where .data and .bss are located - it doesn't even know that they exist. The start-up code which is executed before main() is called contains the start addresses of those sections - the addresses are hard-coded into the program. This start-up code will be in the HEX file like everything else.

            Source https://stackoverflow.com/questions/46067162

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