LintCode

by wisdompeak C++ Version: Current License: No License

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kandi X-RAY | LintCode Summary

LintCode is a C++ library. LintCode has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

LintCode

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LintCode has a low active ecosystem.

It has 5 star(s) with 3 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

LintCode has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of LintCode is current.

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LintCode has no bugs reported.

Security

LintCode has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

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Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

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LintCode releases are not available. You will need to build from source code and install.

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Community Discussions

Trending Discussions on LintCode

Number of ways to form an amount with certain coins

Error in `/tmp/Main': free(): invalid next size (fast): No dynamic allocation

Function returned negative 1. Might be segfault

python recursive function and global variable error

Check subtree using post order

Could someone help to analyse the time complexity of my code?

Two sum data structure problems

JAVA: Why do I need to create a new list object in this function?

Why does killing JVM also terminates its child process if waitFor has been used?

QUESTION

Number of ways to form an amount with certain coins

Asked 2020-May-05 at 18:16

I am trying to solve this problem. http://www.lintcode.com/en/problem/coin-change-ii/#

This is the standard coin change problem solvable with dynamic programming. The goal is to find the number of ways to create an amount using an infinite set of coins, where each has a certain value. I have created the following solution :

...

ANSWER

Answered 2017-Dec-28 at 20:08

Let's consider the loop that works first:

Source https://stackoverflow.com/questions/48012833

QUESTION

Error in `/tmp/Main': free(): invalid next size (fast): No dynamic allocation

Asked 2019-Nov-16 at 04:16

So, I'm doing a problem called "Unique Paths II" in lintcode. However, I encountered a runtime error during a testcase:

...

ANSWER

Answered 2019-Sep-12 at 16:13

Regardless of the error you should read Why is “using namespace std;” considered bad practice? and enable compiler warnings. In your code are many

Source https://stackoverflow.com/questions/57908559

QUESTION

Function returned negative 1. Might be segfault

Asked 2019-Jul-17 at 09:16

So, I was coding a problem on lintcode (number 69). I decided to use dfs using a traditional array as a queue. However, it returned -1 at the commented line, which lintcode says is a segmentation fault with the given input. Here is my code.

...

ANSWER

Answered 2019-Jul-17 at 09:16

These two lines are a likely culprit:

Source https://stackoverflow.com/questions/57071574

QUESTION

python recursive function and global variable error

Asked 2018-Jun-02 at 11:08

I am simulating code to erase all zero at the beginning of a string.

...

ANSWER

Answered 2018-Jun-02 at 11:08

As eraseZero is a part of class Solution and not globally defined, you should use the instance, self in this case, of that class to call it, whether you call it inside or outside the class.

Source https://stackoverflow.com/questions/50656270

QUESTION

Check subtree using post order

Asked 2017-Dec-10 at 17:31

I'm trying to write a program to check if a Tree T2 is a subtree present in Tree T1. I'm using a traversal by storing the state of the tree into a string and checking if T2's substring is a substring present in T1's substring. For some reason, my code fails if I do an in-order in the traverse method to generate a string to hold the representation for the binary tree. Why does this happen? It works fine doing a Post-Order. This is the input case my program fails on:

{9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9} {9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9,9}

The binary tree representation format can be found http://www.lintcode.com/help/binary-tree-representation/

...

ANSWER

Answered 2017-Dec-10 at 17:31

The recursive algorithm you implemented does not provide the serialization of a tree in the desired order. Imagine how it works. All the items of the left subtree will always precede any of the items of the right subtree, since the right subtree will always be processed after the left subtree is finished. In the form that is described at the page you mentioned, al the items of a certain level should follow each other, and the items of the next level should be processed after all the items of the given level are done. To write trees in the described order you need a more complicated algorithm.

And furtermore, the described way to represent a tree as a string does not allow to search for subtrees by simply searching substrings. Consider the follwing tree:

Source https://stackoverflow.com/questions/47736214

QUESTION

Could someone help to analyse the time complexity of my code?

Asked 2017-Mar-06 at 10:44

Scenario:

I'm trying to solve one question on LintCode, "Longest Consecutive Sequence", where given an unsorted array of integers, find the length of the longest consecutive elements sequence.

Link to the original question: https://www.lintcode.com/en/problem/longest-consecutive-sequence/

So here is my intuitive solution:

...

ANSWER

Answered 2017-Feb-06 at 20:21

The Time complexity is worst case complexity. So it looks like O(n^2), with n= num of elements in the set.

In fact:

Source https://stackoverflow.com/questions/42075912

QUESTION

Two sum data structure problems

Asked 2017-Feb-22 at 22:51

I built a data structure for two sum question. In this data structure I built add and find method.
add - Add the number to an internal data structure.
find - Find if there exists any pair of numbers which sum is equal to the value. For example:

...

ANSWER

Answered 2017-Feb-22 at 22:51

There does not seem to be anything wrong with your code.

However a coding challenge could possibly require a more performant solution. (You check every item against every item, which would take O(N^2)).

The best solution to implement find, is using a HashMap, which would take O(N). It's explained more in detail here.

Source https://stackoverflow.com/questions/42403669

QUESTION

JAVA: Why do I need to create a new list object in this function?

Asked 2017-Feb-15 at 21:34

Edit:

The function is part of an answer to lintcode question "combination sum", if I use the second version, the output is "[[],...,[]], where all inner list is empty, even when they are passed in with values. When I just switch to the first version without changing anything else, it would work.

So I assume it has something to with the Java parameter-passing process that I don't understand. Could you please explain why only the first version can work?

Code:

...

ANSWER

Answered 2017-Feb-15 at 21:04

Eventually, they're doing the same thing, however, the only difference I can notice is the first one uses more memory and there is no need to actually construct a new ArrayList of an already existing one.

Source https://stackoverflow.com/questions/42259857

QUESTION

Why does killing JVM also terminates its child process if waitFor has been used?

Asked 2017-Feb-10 at 10:42

If waitFor is not used, killing JVM has no effect on its child process. Here is an example.

Bash script:

...

ANSWER

Answered 2017-Feb-10 at 10:42

There's nothing special about waitPid(), other than the fact that you keep the parent process in the foreground.

If you fork and then wait for the child to finish, you have a (simplified) process tree like this:

Source https://stackoverflow.com/questions/42153486

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