zapcc | zapcc is a caching C++ compiler based on clang | Compiler library

by yrnkrn C++ Version: Current License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | zapcc Summary

zapcc is a C++ library typically used in Utilities, Compiler applications. zapcc has no bugs, it has no vulnerabilities and it has medium support. However zapcc has a Non-SPDX License. You can download it from GitHub.

zapcc is a caching C++ compiler based on clang, designed to perform faster compilations. zapcc uses in-memory compilation cache in client-server architecture, remembering all compilation information between runs. zapcc is the client while zapccs is the server. Each zapcc run will reuse an existing server or if none was available will start a new one.

Support

Quality

Security

License

Reuse

Support

zapcc has a medium active ecosystem.

It has 1211 star(s) with 63 fork(s). There are 59 watchers for this library.

It had no major release in the last 6 months.

There are 7 open issues and 34 have been closed. On average issues are closed in 23 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of zapcc is current.

Quality

zapcc has 0 bugs and 0 code smells.

Security

zapcc has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

zapcc code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

zapcc has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

zapcc releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

It has 59516 lines of code, 2622 functions and 400 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

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zapcc Key Features

No Key Features are available at this moment for zapcc.

zapcc Examples and Code Snippets

No Code Snippets are available at this moment for zapcc.

Community Discussions

Trending Discussions on zapcc

Different compilers behavior for template specialization

error: `type` in `class std::result_of` does not name a type

Understanding overload resolution ranking involving user defined conversion

QUESTION

Different compilers behavior for template specialization

Asked 2019-Apr-04 at 19:22

I discovered different compilers behavior when trying to specialize a template. Here is the minimum code that illustrates the problem:

...

ANSWER

Answered 2019-Apr-04 at 19:22

I am not a language lawyer, but this should not compile. You're trying to initialize a value with itself at compile-time. I would guess this is a clang bug. Actually, I don't see why GCC should be following a recursion path like that if it hits a cycle.

By the way, MSVC tells you (GodBolt):

Source https://stackoverflow.com/questions/55505257

QUESTION

error: `type` in `class std::result_of` does not name a type

Asked 2018-Nov-08 at 18:31

Example below fails with all compilers I've tried: gcc-8.2, clang-8.0 (both options --std=c++17 and std=c++2a were tried) and zapcc-2017.08.

From my point of view the code sample is valid and should be compiled. Or, at least, there should be a more comprehensive error. It does look like a bug in the std library, not covering this particular case for result_of. Am I wrong?

...

ANSWER

Answered 2018-Nov-08 at 18:08

result_of_t means "the result of calling/invoking F with Args...".

result_of_t means "the result of calling int with bar&". Which doesn't exist because you can't call an int with, well, anything.

result_of is not "extract the return type from a function type".

Source https://stackoverflow.com/questions/53213504

QUESTION

Understanding overload resolution ranking involving user defined conversion

Asked 2017-Dec-08 at 18:46

I am trying to understand overload resolution.

First let's consider this first case:

...

ANSWER

Answered 2017-Dec-08 at 12:33

N4713 16.3.3.2:

3.3 User-defined conversion sequence U1 is a better conversion sequence than another user-defined conversion sequence U2 if they contain the same user-defined conversion function or constructor or they initialize the same class in an aggregate initialization and in either case the second standard conversionsequence of U1 is better than the second standard conversion sequence of U2. [Example

Source https://stackoverflow.com/questions/47712965

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