local_binary_pattern | original LBP , circular LBP
kandi X-RAY | local_binary_pattern Summary
kandi X-RAY | local_binary_pattern Summary
The original LBP, circular LBP, rotation-invariant circular LBP, equivalent-mode circular LBP, rotation-invariant equivalent-mode circular LBP are implemented in python and c++. The python version LBP is used for model training, and the c++ version LBP is used for model deployment.
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QUESTION
I tried to change a few lines from the original code however when I tried to run , I got error that say 'AttributeError: module 'PngImageFile' has no attribute 'shape'. However, I had no problem when running the original code. What should I do to remove this error in my modified code?
Here is the original code :
...ANSWER
Answered 2021-Jun-11 at 02:11I saw anna_phog on other portal.
Problem is because this function needs numpy array
but you read image with pillow
Image.open()
and you have to convert img
to numpy array
QUESTION
I'm using scipy signaltonoise function below is the code but it returns an error. I searched regarding this in github too but couldn't find it. Can you please help.
...ANSWER
Answered 2020-Feb-04 at 12:59scipy.stats.signaltonoise()
was deprecated in scipy 0.16.0 and removed in 1.0.0. If you need to use the function without downgrading scipy, you can see the original code from the function before it was removed on github here, and reproduced below:
QUESTION
I need to know if there's a faster way to get the LBP and the resulting histograms of the MNIST dataset. This will be used for handwritten text recognition, through a model that I haven't decided yet..
I've loaded the MNIST dataset and split it to its x, y training sets and x, y test sets based on tensorflow
tutorials.
I've then used cv2
to invert the images.
From there I've defined a function using skimage
to get the LBP and the corresponding histogram of an input image
I finally used a classic for
loop to iterate through the images, get their histograms, store these in a separate list, and return the new list and the unaltered label list of both training and test sets.
Here is the function to load the MNIST dataset:
...ANSWER
Answered 2019-May-08 at 11:26I don't think there's a straightforward way to speed up the iteration over the images. One might expect that using NumPy's vectorize
or apply_along_axis
would improve performance, but these solutions are actually slower than a for
loop (or a list comprehension).
Different alternatives for iterating through the images:
QUESTION
I am new to computer vision and trying to build an image classifier to classify the images from different datasets. I'm going to extract visual features of these images like LBP histogram, color histogram using OpenCV. Since these images are crawled from different websites, they have different image sizes (e.g 136x215
vs. 266x382
). Should I adjust the images to the same size before extracting the features?
The code for extracting LBP histogram:
...ANSWER
Answered 2019-May-10 at 06:43Short answer: If you want to use the LBP histogram, then yes.
It actually depends on the feature descriptor you are using, as some rely on a grid system while others just look at the whole image distribution:
- For the color histogram you should be fine, since you analyze the color distribution, which is independent of the image size. The resulting feature vector should always have the same dimensions as long as you use the same color model and the same bin size.
- When calculating the LBP histogram you are in fact dependent on the image size, since you divide the image into a grid of cells which have a fixed pixel size. Each cell will yield you a 256-dimensional feature vector. When using the same grid size a bigger image will result in more cells, which will then result in a bigger feature space for your whole image.
As you can't use feature vectors of different dimensions for your classification, you will need to make sure that your descriptor always produces a vector of the same size.
QUESTION
For example, the lbp code of the pixel with coordinate (1, 1) is possible to calculate it with the pixels (0, 0); (0, 1); (0, 2); (1, 2); (2, 2); (2, 1); (2, 0); (1, 0) but the pixels of the extremes do not have those 8 neighborhood pixels, that is, the pixel (0, 0) only has 3 neighbors.
This question comes to me because I have obtained the LBP image using sicikit image, the code is as follows:
lbp = feature.local_binary_pattern (gray, 8, 1, 'ror')
Then I printed the values of the gray image and got these values:
...ANSWER
Answered 2019-Feb-05 at 13:00The function skimage.feature.local_binary_pattern
performs zero padding under the hood. As a consequence of it the LBP codes are actually computed from the padded image:
QUESTION
I want to plot the mean local binary patterns histograms of a set of images. Here is what I did:
...ANSWER
Answered 2018-Jun-20 at 07:36Try this. Here the array is your mean values from bins.
QUESTION
I'm running LBP
algorithm to classify images
by their texture features. Classifying method is LinearSVC
in sklearn.svm
package.
Getting histogram and fitting by SVM
is done, but sometimes length
of histogram
varies depending on image
.
Example is below:
...ANSWER
Answered 2018-May-07 at 10:44There are 59 different uniform LBPs for a neighbourhood of 8 points. This should be the dimension of your feature vectors, but it is not because you used itemfreq
to compute the histograms (as a side note, itemfreq
is deprecated). The length of the histograms obtained throug itemfreq
is the number of different uniform LBPs in the image. If some uniform LBPs are not present in the image the number of bins of the resulting histogram will be lower than 59. This issue can be easily fixed by utilizing bincount
as demonstrated in the toy example below:
QUESTION
I've been running into problems recently where the local binary pattern method in python skimage is producing unexpected results.
Have a look at the cartoon example below. It shows two flat color circles on a flat color background.
The local binary pattern (P=8 samples, Radius=1) output is:
(Image is color coded in jet colors). The gray color correctly represents 255. However, the blue color is 85 (binary 01010101).
So while the method correctly shows the background and the circle on the right as 255, it shows the left circle as 85. Apparently, the local binary pattern method in skimage thinks the region is completely noisy (hence the alternating binary pattern 01010101). This is not true, however, as I have double checked the individual pixels in the region shown in blue above and their values are identical (i.e. its flat color, just like the flat color background and other flat color circle).
Has anyone experienced a similar problem before?
Here is the code if you want to replicate this:
...ANSWER
Answered 2017-Mar-20 at 10:42I guess the issue is due to numeric errors. When the color image is read using
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