Hisp | Yet another simple Scheme Interpreter

 by   DeathKing C Version: Current License: MIT

kandi X-RAY | Hisp Summary

kandi X-RAY | Hisp Summary

Hisp is a C library. Hisp has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

WARNING! This is a refactoring version of my final project of Software Development course, and it can not work until a β-version released.
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              Hisp has a low active ecosystem.
              It has 11 star(s) with 1 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Hisp is current.

            kandi-Quality Quality

              Hisp has 0 bugs and 0 code smells.

            kandi-Security Security

              Hisp has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Hisp code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Hisp is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Hisp releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            Hisp Key Features

            No Key Features are available at this moment for Hisp.

            Hisp Examples and Code Snippets

            No Code Snippets are available at this moment for Hisp.

            Community Discussions

            QUESTION

            How do I create a new column from this data?
            Asked 2022-Jan-07 at 08:36

            I have df

            ...

            ANSWER

            Answered 2021-Oct-27 at 15:16

            QUESTION

            fitted values from speedglm() look very different from fitted values with glm()
            Asked 2021-Nov-24 at 15:29

            The fitted values returned from speedglm() look really different from those returned from glm() and i don't know why. For example, if I run this:

            ...

            ANSWER

            Answered 2021-Nov-24 at 15:29

            "Linear predictors" are not the same as "fitted values", unless a GLM is fitted with an identity link. In general the linear predictor is eta = b0 + b1*x1 + b2*x2 + ..., while the fitted value is mu = linkinv(eta), where linkinv is the inverse link function (e.g. logistic or inverse-logit in this case).

            In general it's always safer to use accessor methods: that way you don't have to worry about internal definitions

            Source https://stackoverflow.com/questions/70098526

            QUESTION

            Calculate the percentage of Ethnicity in R
            Asked 2020-Sep-07 at 04:26

            I am analyzing the Males data set from the Ecdat package in R.

            I would like to calulate the percentage of each group of people (black, hisp and other) which are affiliated to the union.

            The structure of the data is:

            ...

            ANSWER

            Answered 2020-Sep-07 at 04:08

            You can solve it using group_by() and summarize(), as follows:

            Source https://stackoverflow.com/questions/63770948

            QUESTION

            Estimating the average marginal effect of binary and continuous coefficients in logit model R
            Asked 2020-Sep-01 at 18:06

            Using data from the National Health Interview Survey, I am hoping to analyze the average marginal effect a variety of demographic factors have on the predicted probability of having hypertension using a logistic regression. To clarify, by average marginal effect I mean that I want to be computing the marginal effect at the mean of every X (like the STATA output).

            My issue is that I have both binary and continuous independent variables, but from what I've read, it doesn't make sense to evaluate the binary variables at their mean, since it's either a 0 or 1. I don't know how to make the regression run where I can evaluate the continuous variables at their mean, but not the binary ones. Here is the code I have so far.

            ...

            ANSWER

            Answered 2020-Sep-01 at 01:29

            The margins package takes care of this automatically if you declare a variable to be a factor. See the subsetting section of the vignette or you can inspect the source code to see that marginal effects are computed as differences for factor variables.

            Note that the default setting for margins is to compute the "average marginal effect", and not the "marginal effect at the mean". IMO, the default setting is best in most cases, but if you insist on considering a "synthetic" average observation, it is easy to do with the at argument of the margins function.

            Code example. In the first case, vs is treated as a continuous variable. In the second, vs is treated as a binary variable.

            Source https://stackoverflow.com/questions/63680030

            QUESTION

            Java Hibernate, change inherited ManyToMany relationship table name from @MappedSuperclass in the subclass entity
            Asked 2020-Aug-30 at 18:35

            This is my abstract father:

            ...

            ANSWER

            Answered 2020-Aug-30 at 18:35

            Finally, I managed to know how it's done. The way we use @AssociationOverrides and @JoinTable in my use case to override the parent-defined relation is as the following:

            Source https://stackoverflow.com/questions/63659285

            QUESTION

            Modifying a ggplot of odds ratios
            Asked 2020-Aug-02 at 13:47

            I am working on a plot of 21 different odds ratios and their respective confidence intervals - the odds ratios are stratified by racial group (7 groups) and death category (3 categories), and I'm pretty close to what I want, I just am stuck on a few things.

            Here is what I've run so far:

            ...

            ANSWER

            Answered 2020-Aug-02 at 13:47

            The problem is simply that you are drawing the gray background with your call to geom_rect, which by default is gray. You can either make this white, or better still, remove it and use scales and themes to give your plot the desired look.

            To remove the color guide from the legend, you can add + scale_color_discrete(guide = guide_none()) to your plot.

            The symbols are being clipped (and don't align perfectly with the labels) because each of the facets is actually preserving a tiny space for all the groups. You therefore need to specify scales = "free_y" to level everything out, give your error bars greater width and prevent the symbols from clipping.

            You can also choose a global theme that requires less individual tweaks to the theme parameters, and you may prefer the look of making the strip labels right-aligned and external to the y axis line.

            Source https://stackoverflow.com/questions/63216242

            QUESTION

            Create a function for standard error of a population percentage in R
            Asked 2020-May-25 at 18:21

            I am hoping to create a formula in R that I can use to calculate a standard error estimate of population percentages for various demographic factors. There are 1,045 people in my sample. My data frame is called NHIS1, and, for example, I would like to calculate the standard error for the proportion of the population which is white or Hispanic. The variables I have for WHITE and HISP are binary with 0 or 1 indicators. I calculated the population percentages with this code:

            #sum(NHIS1$WHITE)=637,nrow(NHIS1)=1045, and sum(NHIS1$HISP)=408 (sum(NHIS1$WHITE)/nrow(NHIS1))*100, (sum(NHIS1$HISP)/nrow(NHIS1))*100

            I thought my formula set up could look something like what's below, but I am not sure if there's a better way to set this all up so R can refer to these population proportions above without me manually plugging it in.

            ...

            ANSWER

            Answered 2020-May-25 at 18:17

            You could try using a prop.test of a table of each column, which gives you the proportion as well as 95% confidence intervals. Just multiply these by 100 to get percentages:

            Source https://stackoverflow.com/questions/62008025

            QUESTION

            delete vertices in r , as a network object
            Asked 2020-Apr-18 at 17:34

            I have some data like below, this data can be found in library network, when I try list.vertex.attributes(v), it gives me the "Grade" "na" "Race" "Sex" "vertex.names", so I want to delete some node with Race="natAm", I have tried this code but my delete function does not work. can you help me?

            ...

            ANSWER

            Answered 2020-Apr-18 at 17:34

            To delete vertices where Race=="NatAm", you can indicate this in the vid argument of delete.vertices(). But beware--delete.vertices() modifies the network in place!

            Source https://stackoverflow.com/questions/61292796

            QUESTION

            Error when estimating random effects model with plm package when haven is loaded
            Asked 2020-Apr-16 at 18:09

            I have a weird problem when estimating a random effects with the plm package in R.

            Here is a link to a dput of part of my data: https://pastebin.com/raw/mTdh26dg

            My code is:

            ...

            ANSWER

            Answered 2020-Apr-16 at 18:09

            I think the issue is that your data males_part is a tibble, but you don't have the tibble package loaded until you attach haven. If you don't have tibble loaded, then you won't have any methods for the tibble classes "tbl_df" and "tbl", and it will act exactly like a data frame. Once tibble is loaded, it will start to act like a tibble.

            This is an issue because tibbles and data frames aren't identical, but the class of a tibble includes "data.frame". I'd guess what's happening is that plm assumes that extracting a single column from a data frame gives a vector, but with a tibble, it gives another tibble.

            The workaround for you is pretty simple. Just use males_part <- as.data.frame(males_part) to remove the tibble class, and then haven won't matter.

            Conceivably this is worth reporting to the maintainer of plm. It's a design flaw in tibble that is causing the problem (if tibbles inherit from data.frame, they should act like data frames), but tibbles are pretty common nowadays, and that design is unlikely to change. The plm function could protect itself against this by putting data <- as.data.frame(data) early in the pdata.frame function, or protecting every column extraction with drop = TRUE.

            Source https://stackoverflow.com/questions/61249692

            QUESTION

            Output summary statistics with stargazer
            Asked 2020-Feb-22 at 05:35

            Beginner question here. I'm trying to output the basic statistics into stargazer of a dataframe.

            ...

            ANSWER

            Answered 2020-Feb-22 at 05:35

            I think you are doing it wrong, since no input data is given I am using iris. If you run the same command on iris , the error which you shown can be replicated as well.

            From documentation:

            The first argument(ellipsis) only accepts these things:

            ... one or more model objects (for regression analysis tables) or data frames/vectors/matrices (for summary statistics, or direct output of content). They can also be included as lists (or even lists within lists).

            you should do it like this:

            Source https://stackoverflow.com/questions/60349303

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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            You can download it from GitHub.

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