Hisp | Yet another simple Scheme Interpreter
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kandi X-RAY | Hisp Summary
WARNING! This is a refactoring version of my final project of Software Development course, and it can not work until a β-version released.
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QUESTION
I have df
...ANSWER
Answered 2021-Oct-27 at 15:16We can use max.col
QUESTION
The fitted values returned from speedglm()
look really different from those returned from glm()
and i don't know why. For example, if I run this:
ANSWER
Answered 2021-Nov-24 at 15:29"Linear predictors" are not the same as "fitted values", unless a GLM is fitted with an identity link. In general the linear predictor is eta = b0 + b1*x1 + b2*x2 + ...
, while the fitted value is mu = linkinv(eta)
, where linkinv
is the inverse link function (e.g. logistic or inverse-logit in this case).
In general it's always safer to use accessor methods: that way you don't have to worry about internal definitions
QUESTION
I am analyzing the Males data set from the Ecdat package in R.
I would like to calulate the percentage of each group of people (black, hisp and other) which are affiliated to the union.
The structure of the data is:
...ANSWER
Answered 2020-Sep-07 at 04:08You can solve it using group_by()
and summarize()
, as follows:
QUESTION
Using data from the National Health Interview Survey, I am hoping to analyze the average marginal effect a variety of demographic factors have on the predicted probability of having hypertension using a logistic regression. To clarify, by average marginal effect I mean that I want to be computing the marginal effect at the mean of every X (like the STATA output).
My issue is that I have both binary and continuous independent variables, but from what I've read, it doesn't make sense to evaluate the binary variables at their mean, since it's either a 0 or 1. I don't know how to make the regression run where I can evaluate the continuous variables at their mean, but not the binary ones. Here is the code I have so far.
...ANSWER
Answered 2020-Sep-01 at 01:29The margins
package takes care of this automatically if you declare a variable to be a factor. See the subsetting section of the vignette or you can inspect the source code to see that marginal effects are computed as differences for factor variables.
Note that the default setting for margins
is to compute the "average marginal effect", and not the "marginal effect at the mean". IMO, the default setting is best in most cases, but if you insist on considering a "synthetic" average observation, it is easy to do with the at
argument of the margins
function.
Code example. In the first case, vs
is treated as a continuous variable. In the second, vs
is treated as a binary variable.
QUESTION
This is my abstract father:
...ANSWER
Answered 2020-Aug-30 at 18:35Finally, I managed to know how it's done. The way we use @AssociationOverrides and @JoinTable in my use case to override the parent-defined relation is as the following:
QUESTION
I am working on a plot of 21 different odds ratios and their respective confidence intervals - the odds ratios are stratified by racial group (7 groups) and death category (3 categories), and I'm pretty close to what I want, I just am stuck on a few things.
Here is what I've run so far:
...ANSWER
Answered 2020-Aug-02 at 13:47The problem is simply that you are drawing the gray background with your call to geom_rect
, which by default is gray. You can either make this white, or better still, remove it and use scales and themes to give your plot the desired look.
To remove the color guide from the legend, you can add + scale_color_discrete(guide = guide_none())
to your plot.
The symbols are being clipped (and don't align perfectly with the labels) because each of the facets is actually preserving a tiny space for all the groups. You therefore need to specify scales = "free_y"
to level everything out, give your error bars greater width and prevent the symbols from clipping.
You can also choose a global theme that requires less individual tweaks to the theme
parameters, and you may prefer the look of making the strip labels right-aligned and external to the y axis line.
QUESTION
I am hoping to create a formula in R that I can use to calculate a standard error estimate of population percentages for various demographic factors. There are 1,045 people in my sample. My data frame is called NHIS1, and, for example, I would like to calculate the standard error for the proportion of the population which is white or Hispanic. The variables I have for WHITE and HISP are binary with 0 or 1 indicators. I calculated the population percentages with this code:
#sum(NHIS1$WHITE)=637,nrow(NHIS1)=1045, and sum(NHIS1$HISP)=408
(sum(NHIS1$WHITE)/nrow(NHIS1))*100,
(sum(NHIS1$HISP)/nrow(NHIS1))*100
I thought my formula set up could look something like what's below, but I am not sure if there's a better way to set this all up so R can refer to these population proportions above without me manually plugging it in.
...ANSWER
Answered 2020-May-25 at 18:17You could try using a prop.test
of a table of each column, which gives you the proportion as well as 95% confidence intervals. Just multiply these by 100 to get percentages:
QUESTION
I have some data like below, this data can be found in library network, when I try list.vertex.attributes(v), it gives me the "Grade" "na" "Race" "Sex" "vertex.names", so I want to delete some node with Race="natAm", I have tried this code but my delete function does not work. can you help me?
...ANSWER
Answered 2020-Apr-18 at 17:34To delete vertices where Race=="NatAm"
, you can indicate this in the vid
argument of delete.vertices()
. But beware--delete.vertices()
modifies the network in place!
QUESTION
I have a weird problem when estimating a random effects with the plm
package in R.
Here is a link to a dput
of part of my data: https://pastebin.com/raw/mTdh26dg
My code is:
...ANSWER
Answered 2020-Apr-16 at 18:09I think the issue is that your data males_part
is a tibble, but you don't have the tibble
package loaded until you attach haven
. If you don't have tibble
loaded, then you won't have any methods for the tibble classes "tbl_df"
and "tbl"
, and it will act exactly like a data frame. Once tibble
is loaded, it will start to act like a tibble.
This is an issue because tibbles and data frames aren't identical, but the class of a tibble includes "data.frame"
. I'd guess what's happening is that plm
assumes that extracting a single column from a data frame gives a vector, but with a tibble, it gives another tibble.
The workaround for you is pretty simple. Just use males_part <- as.data.frame(males_part)
to remove the tibble class, and then haven
won't matter.
Conceivably this is worth reporting to the maintainer of plm
. It's a design flaw in tibble
that is causing the problem (if tibbles inherit from data.frame
, they should act like data frames), but tibbles are pretty common nowadays, and that design is unlikely to change. The plm
function could protect itself against this by putting data <- as.data.frame(data)
early in the pdata.frame
function,
or protecting every column extraction with drop = TRUE
.
QUESTION
Beginner question here. I'm trying to output the basic statistics into stargazer of a dataframe.
...ANSWER
Answered 2020-Feb-22 at 05:35I think you are doing it wrong, since no input data is given I am using iris. If you run the same command on iris , the error which you shown can be replicated as well.
From documentation:
The first argument(ellipsis) only accepts these things:
... one or more model objects (for regression analysis tables) or data frames/vectors/matrices (for summary statistics, or direct output of content). They can also be included as lists (or even lists within lists).
you should do it like this:
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