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kandi X-RAY | layout.c Summary
kandi X-RAY | layout.c Summary
Mirror of https://gist.github.com/vurtun/75ee8b43773152930d89b7d1fdbe6450
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QUESTION
I have the following network graph:
...ANSWER
Answered 2022-Mar-30 at 04:35You could just update relations
using complete
, and than filter out the rows where from
is equal to to
, which gives arrows from a node to itself.
QUESTION
I made the following 25 network graphs (all of these graphs are copies for simplicity - in reality, they will all be different):
...ANSWER
Answered 2022-Mar-03 at 21:12While my solution isn't exactly what you describe under Option 2
, it is close. We use combineWidgets()
to create a grid with a single column and a row height where one graph covers most of the screen height. We squeeze in a link between each widget instance that scrolls the browser window down to show the following graph when clicked.
Let me know if this is working for you. It should be possible to automatically adjust the row size according to the browser window size. Currently, this depends on the browser window height being around 1000px.
I modified your code for the graph creation slightly and wrapped it in a function. This allows us to create 25 different-looking graphs easily. This way testing the resulting HTML file is more fun! What follows the function definition is the code to create a list
of HTML objects that we then feed into combineWidgets()
.
QUESTION
On the localhost module, lazy loading is working fine, showing meta tags and HTML content in in the view page source, but it is not showing on the live server. On the live server, I can only see meta tags and HTML contents of components that are direct children of
AppModule
but lazy loaded modules components are not showing meta tags and HTML. This weird behavior is only on the live server.
app.server.module.ts
...ANSWER
Answered 2022-Mar-06 at 11:12There are several reasons why the body tag of your angular app fails to render on the server side. Here's a checklist:
- First make sure your live environment supports NodeJS. Without NodeJS on the server, you can't use server-side rendering
- In Visual Studio, try changing your
ASPNETCORE_ENVIRONMENT
environment variable fromDEVELOPMENT
toPRODUCTION
and run your application. In some cases the app behaves differently in either configuration (looks for themain.js
file in another location whenPRODUCTION
). After starting the debugger and trying to prerender a view, you may see some exceptions in the Visual Studio Output window.- In my case the
main.js
file had to end up atClientApp/dist/main.js
. So I had to modifyangular.json
changing theprojects:ClientApp:architect:build:options:outputPath
todist
(see also)
- In my case the
- If you experience this problem using Visual Studio, do always look at the Output window for errors which will point you in the right direction.
- If you're hosting a PWA (for example through
@angular/pwa
), then it's totally normal that you're getting an empty page when going to View source in the browser. If you'd then ctrl + F5, you'll be bypassing the angular service worker which shows you the prerendered html source. This is something you shouldn't bother about. Google, Bing, ... will actually fetch and index the server-side rendered version of your page. - If you're using ASP.NET Core 3.1 or earlier, you cannot have an
async
lambda for yourSupplyData
delegate.SupplyData
is not aFunc
and is not being awaited in the source code of ASP.NET Core. I changed this in my port to .NET 6
QUESTION
I made the following graph using the "visnetwork" library:
...ANSWER
Answered 2022-Mar-01 at 02:20The reason for the error is that there is no 8 and there are 2 12s.
QUESTION
I have the following network graph:
...ANSWER
Answered 2022-Feb-24 at 17:37I was not able to figure out how to do this with "visIgraph()" function - but I think I was able to figure out how to generate a random graph (meeting certain conditions: Generating Random Graphs According to Some Conditions) and using the regular "visNetwork()" function and then place a title on this graph:
QUESTION
I have the following graph:
...ANSWER
Answered 2022-Feb-25 at 11:37Not sure to fully understand what you are looking for but:
If you want the vertices to be placed randomly and not on a circle, you just need to use the argument
layout = "layout_randomly"
inside thevisIgraph()
function.If you want the vertices to be placed randomly and on a circle, you need to use the
permute()
function and then just add the argumentlayout = "layout_circle"
inside thevisIgraph()
function.
Please find below a reprex.
Reprex
- Your data
QUESTION
I have the following network graph:
...ANSWER
Answered 2022-Feb-24 at 17:12I don't know why you want to run a for
loop, but please find below a possible solution using the as_edgelist()
function from the igraph
library.
Reprex
- Your data
QUESTION
I need the widget's background to be loaded from my database (either the picture itself, or the picture linked to it). After looking at many tutorials (here is an example of what I need: https://youtu.be/mOhNdP1QZ7E), I could not solve this problem. The picture is not displayed. The java class code is 100% taken from the tutorial above. Tried others too.
...ANSWER
Answered 2022-Feb-20 at 12:24you can simply use a library, which is Glide.
1. add a dependency to build.gradle (app)
QUESTION
I'm trying to come up with a solution to allow multiple Pane nodes handle mouse events independently when assembled into a StackPane
...ANSWER
Answered 2022-Feb-09 at 18:34Using the hint from @jewelsea I was able to use a custom chain. I've done this from a "catcher" Pane which is added to the front of the StackPane. This then builds a chain using all the children, in reverse order, excluding itself.
QUESTION
I've been playing with Jetpack Compose Desktop. I noticed something I really don't understand:
...ANSWER
Answered 2022-Feb-09 at 09:11I thought, that on every recompose the mutable state get reinstanciated with the initial Value: so the Text should not be able to change
The point of having a state when recomposing is to prevent a variable from being re-initialized. The initial state is used only once when the first composition occurs and isn't used again when further recompositions occur. If however the composable is removed from the UI tree and then reinstated later on, the state of the variable will be destroyed and re-initialized as this is not really a recomposition but a composition (as if it were happening for the first time).
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