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QUESTION
I recently moved from working in the terminal to VScode and am needing to generate debugging information to use with the debugger in vscode.
My makefile is:
...ANSWER
Answered 2022-Jan-26 at 23:05A good proposal is to remove the @
s in front of the command names to see what commands make
is executing.... To make a program debuggable, you need to check that all the compilation steps are done using the -g
flag and that the linking step has also included the -g
flag. Also a good option is to specify no optimization so you will not get to problems with breakpoints you cannot fix because the compiler has eliminated or changed the final code, and has broken the correspondence between source lines and points in the code.
If you take off all the @
s there, you will see the commands as make
is executing them, think you don't see now. I think there's a command (berkeley make has it) to make make
to print the commands even though the @
s remain in place.
By the way, as you are telling you are using vscode
it should be fine if you execute make
on the command line alone, to see the output of the commands, and try to see if it is some problem with make or with vscode itself.
As you have not provided your complete project, I'm sorry to say that I can only test it with dumb/fake files and no program can be made to test it with gdb.
I guess that the problem is that you have put your project sources in a different directory than where the program is built, and the sources cannot be found by gdb and so, no source debugging can be done because gdb cannot find the source files. Gdb has some way to specify the path to the source files... You should look at gdb documentation.
QUESTION
I have the following inheritance model:
...ANSWER
Answered 2021-Nov-25 at 10:08Just replace
QUESTION
I'm trying to make a library for my project but I am very very new to Makefiles. I tried several configurations and adding -I
but none worked.
I have the following three:
...ANSWER
Answered 2021-Oct-26 at 16:40Yes, you're missing some things.
First, look at the command line make shows:
QUESTION
Here is my Makefile:
...ANSWER
Answered 2021-Oct-19 at 12:53Touching libprintf.a
won't cause anything to rebuild. Make rebuilds targets that are out of date. Out of date means that either the target doesn't exist, or some prerequisite of the target is newer than the target.
After you run make then libprintf.a
is up to date, which means it's newer than all its prerequisites. Running touch libprintf.a
just makes it even newer than its prerequisites than it was before, so make still considers it up to date.
If you want to rebuild libprintf.a
you need to touch (or delete) one of its prerequisites, not the target itself.
The reason for your second issue seems to be related to the makefile in the libft
subdirectory. It seems like you're using the --no-print-directories
option here: you should avoid using that, at least as long as you're debugging, so that you can see where make is going and which makefile it's running.
QUESTION
I am trying to compile a simple C function to handle two stacks of ints and sorting them with specific rules. I had no problem compiling earlier but I can't anymore. and receive this error message :
...ANSWER
Answered 2021-Jun-04 at 07:33The problem is that $(SRC:.c =.o)
doesn't work because of that space (there are no SRC
names ending with ".c "
(including the last space).
It should be $(SRC:.c=.o)
.
QUESTION
I am trying to create a static library using a shell script.
For creating the library I used following script:
...ANSWER
Answered 2021-Apr-27 at 12:57#include "file_name"
means like "please copy and paste the contents of the file file_name
here", so it shouldn't be used with .a
file.
You can write the declaration of the function to use directly instead of using .h
file.
QUESTION
So, right now my Makefile looks like this
...ANSWER
Answered 2021-Apr-21 at 05:31It should work to adjust your makefile as following
QUESTION
I have function named ft_split(char const *s, char c)
that is supposed to take strings and delimiter char c
and divide s
into bunch of smaller strings.
It is 3rd or 4th day I am trying to solve it and my approach:
Calculates no. of characters in the string including 1 delimiter at the time (if space is delimiter so if there are 2 or more spaces in a row than it counts one space and not more. Why? That space is a memory for adding '\0' at the end of each splitted string)
It finds size (k) of characters between delimiters -> malloc memory -> copy from string to malloc -> copy from malloc to malloc ->start over.
But well... function shows segmentation fault. Debugger shows that after allocating "big" memory it does not go inside while loop, but straight to big[y][z] = small[z] after what it exits the function.
Any tips appreciated.
...ANSWER
Answered 2021-Feb-27 at 21:29I didn't get everything what the code is doing, but:
You have a char **big
, it's a pointer-to-pointer-to-char, so presumably is supposed to point to an array of char *
, which then point to strings. That would look like this:
QUESTION
** Hello :)
So I have this task to write a program that will convert int to arg using malloc and well it all works fine, gdb shows no errors, but it is not printing any output in this form. If i delete itoa_buffer[i] = '\0'; than sometimes it shows output sometimes not. I do not know what is wrong here, seems fine.
I do not know where to ask for help as I like to follow my logic and find errors here instead of copying solutions from the internet. I willl appreciate some tips, its probably some small thing Id do not know and wont let me go further.**
...ANSWER
Answered 2021-Feb-23 at 10:41You are putting '\0'
as the first character of the string.
Instead of that, you should put that as the last character.
Instead of this part
QUESTION
I need something like strlen
but the string is filled with only null-terminators "\0\0\0\0\0\0\0"
and I need to fill it with another character up until (not including) the last \0
like so "FFFFFF\0"
. Is there a way to calculate the size without errors?
I had to implement bzero
for a school project called "libft". Then I was tasked with implementing strcpy
and I saw in the man pages that dest
needs to be large enough to receive the copy of src
so I want to account for a situation where bzero
was used on dest
and strcpy
doesn't allow me to pass the size of dest
as a parameter. I was just wondering (out of curiosity) how I would know how big dest
is because I know that strcpy
does not account for this. There is a warning in the man page "Beware of buffer overruns! (See BUGS.)".
I realise now that this might be impossible in C.
...ANSWER
Answered 2021-Jan-16 at 21:21What you're asking is whether you can know how much memory has been allocated.
If it was allocated with malloc
, no.
If it's an array allocated on the stack, like char foo[10]
, yes you can use sizeof(foo)
, but that doesn't tell you anything you didn't already know.
If you need to know the allocated size of the string, you need to remember it at allocation time and pass it around. You can use an extra variable, or you can make a struct
which has both the string and size.
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