rapidjson | custom distribution of rapidjson

 by   Kanma C Version: Current License: MIT

kandi X-RAY | rapidjson Summary

kandi X-RAY | rapidjson Summary

rapidjson is a C library. rapidjson has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

This is a custom distribution of rapidjson (version 0.11. This is a header-only library, no compilation required. The original README file of rapidjson is at 'readme-rapidjson.txt'. Note: Unlike the official rapidjson repository, this one doesn't include any example, nor the documentation.
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            kandi-support Support

              rapidjson has a low active ecosystem.
              It has 14 star(s) with 12 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              rapidjson has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of rapidjson is current.

            kandi-Quality Quality

              rapidjson has no bugs reported.

            kandi-Security Security

              rapidjson has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              rapidjson is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              rapidjson releases are not available. You will need to build from source code and install.

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            rapidjson Key Features

            No Key Features are available at this moment for rapidjson.

            rapidjson Examples and Code Snippets

            No Code Snippets are available at this moment for rapidjson.

            Community Discussions

            QUESTION

            Linking to curl from C++ on M1 Mac - undefined symbols for arm64
            Asked 2021-May-16 at 17:17

            I have an existing project that was on Windows and Linux. I recently got a mac for the first time and I am trying to set it up for C++ development but I'm having an issue linking to curl I believe.

            From what I've seen, curl supports the M1 arm based chip via homebrew which I installed using homebrew install curl.

            Below is my make file

            ...

            ANSWER

            Answered 2021-May-16 at 17:17

            I don't see any reference to the curl library in your makefile. To rectify this, you (probably) need to add -lcurl to your LDFLAGS.

            Also, /opt/homebrew/opt/curl/bin/curl is the curl executable, not the library. That is (probably) /opt/homebrew/opt/curl/lib/libcurl.so

            Source https://stackoverflow.com/questions/67558391

            QUESTION

            Is it possible to use a c++ library from an older c++ version?
            Asked 2021-May-13 at 02:44

            So I'm trying to use JSON as a file format for my c++ project. But I cant find a library for C++17. There are a few(nlohmann/json,RapidJSON) for older versions, such as C++11 but I don't know if it's possible to use an older one. Can I do this?

            ...

            ANSWER

            Answered 2021-May-10 at 18:51

            C++ versions are largely backwards compatible with prior versions. Any incompatibility are (usually) done for a specific purpose and with some degree of deprecation or the like.

            So broadly speaking, a C++11 library (header-only or compiled) will compile under a C++17 compiler. There are times when this will fail, but they're usually around specific library types (like std::auto_ptr or somesuch).

            For compiled libraries, ABI can be an issue (which means you may need to recompile them, which requires the source code). But for header-only libraries, this isn't a problem, since you're always compiling them.

            Source https://stackoverflow.com/questions/67475705

            QUESTION

            converting json++ implementation to use rapidJSON: handling mixture of string and wstring
            Asked 2021-Apr-29 at 10:44

            I'm converting some code that originally used the json++ library to now use rapidJSON. The code serializes and de-serializes various objects using json files. In json++, it looks something like this:

            serialize:

            ...

            ANSWER

            Answered 2021-Apr-29 at 10:44

            I think you need to use conversion here, I have go through the doc and src of RapidJSON, and confirmed that we can't mix GenericValue with Value.

            We can use the wstring_convert, see this answer as the reference.

            Or with boost.

            Source https://stackoverflow.com/questions/67307437

            QUESTION

            What is the easiest way to parse a json file using rapidjson?
            Asked 2021-Mar-02 at 01:12

            So I am just getting familiar with rapidjson.h but I can't find this one basic piece of example code of parsing the *.json file.

            I found the official [turorial][1]. But here however they parse the json stored in a C string. I know how this string is supposed to look like but I'm lazy to make a custom Parser just to convert my file to this string. I mean I was kinda hoping that rapidjson is supposed to do that for me. Please correct me if I'm wrong.

            The closest thing I found to what I need is here How to read json file using rapidjson and output to std::string?

            Therefore I was really surprised that I can't just do something like this (with *.json file being in the same folder as my program):

            ...

            ANSWER

            Answered 2021-Mar-01 at 23:52

            You can use FileReadStream and ParseStream instead of the IStreamWrapper. According to the documentation, FileReadStream is much faster than IStreamWrapper.

            The R means that it's a raw string literal. Without it, the backslashes are interpreted as the start of escape sequences and you would have to write it like this to make it correct:

            Source https://stackoverflow.com/questions/66431203

            QUESTION

            docker run -e not working (before image name)
            Asked 2021-Jan-31 at 23:40

            I am trying to make a docker container for a game server.(first container i ever made) When i try to change de environment variable with the docker run command, the variables do not change in the container. My dockerfile:

            ...

            ANSWER

            Answered 2021-Jan-31 at 23:40

            The AuthKey variable set in the docker run command will not affect the Server.cfg in the already created image from the docker build. At that point the image was already created with the file. You could solve that with a build arg, but that would result in what is normally a secret value and configuration data included in the image, which is an anti-pattern.

            Instead, I'd probably start by running the https://github.com/BeamMP/BeamMP-Server in your current repo and checkout your desired tag there, making it a git submodule. When cloning your repo you'd then include submodules with git clone --recurse-submodules. Then the Dockerfile just has a copy of that directory.

            After that, I would completely skip the creation of the Server.cfg inside of docker, or move that to an entrypoint that uses injected environment variables. Doing this outside of docker would involve creating the config file and mounting it as a volume. Performing the creation of this in the entrypoint could look like:

            Source https://stackoverflow.com/questions/65985215

            QUESTION

            Rapid json, c++, json, modify empty json array
            Asked 2020-Nov-26 at 16:24

            I have a json file, which contains two object. The first object is an array of objects. Each of these objects has an element "key" and empty array. I need to fill the array with 4 numbers and I need to save back the json. I am checking the tutorial, but probably I am missing something. May somebody help me please? Here is my code, that doesn't work:

            ...

            ANSWER

            Answered 2020-Nov-26 at 16:24

            This part of the code doesn't do anything:

            Source https://stackoverflow.com/questions/65024226

            QUESTION

            Loss of floating point values :: reading JSON with rapidjson
            Asked 2020-Nov-24 at 10:01

            In the project, the program reads JSON Document (using rapidjson) and then takes a part of that JSON document and tries to create new JSON Value. Following code is used for that

            ...

            ANSWER

            Answered 2020-Nov-24 at 10:01

            Converted OP's comment to an answer:

            The precision was set at 1, that's the reason you are getting this output. So set the precision to 18 and this issue should be solved.

            Source https://stackoverflow.com/questions/64983117

            QUESTION

            std::variant and std::visit: error: no member named 'valueless_by_exception'
            Asked 2020-Nov-17 at 07:50

            I have the following block of code:

            ...

            ANSWER

            Answered 2020-Nov-17 at 04:06

            The arguments to std::visit (value) should be std::variants but seems to be a std::pair.

            Example:

            Source https://stackoverflow.com/questions/64868836

            QUESTION

            Where the error come while parsing RapidJSON
            Asked 2020-Nov-16 at 12:11

            I'm trying to parse a JSON file using RapidJSON, I've created this code to get the integers (in this case), however, I get errors saying that some variables are not members of the structure when they are included. The declared struct is the original JSON format but formatted as struct to get the values.

            ...

            ANSWER

            Answered 2020-Nov-16 at 12:11
               struct MessageCam
               {
                  int generationDeltaTime;
                  struct MessageCamParameters
                  {
            

            Source https://stackoverflow.com/questions/64857677

            QUESTION

            Is there any conversions when storing/reading integers of different size to/from union?
            Asked 2020-Nov-15 at 20:32

            Reading Rapidjson code I found some interesting optimization with "type punning".

            ...

            ANSWER

            Answered 2020-Nov-15 at 20:32

            So is it legal in C++?

            No, it isn't legal in c++ (Wikipedia also already stated "While not allowed by C++ ...").

            In c++ a union is just reserving memory for the contained union members, such that it is enough to fit the largest member. That memory is shared by all members.

            Accessing a different member from the union as was used to initialize it, is undefined behavior. You need to decide beforehand with which union members to work, if these are shared by any functions (this is often done using a type discriminator).

            Source https://stackoverflow.com/questions/64849343

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install rapidjson

            You can download it from GitHub.

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