fmem | Linux Kernel Module

by NateBrune C Version: Current License: GPL-2.0

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kandi X-RAY | fmem Summary

fmem is a C library. fmem has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

This repo is was originally a github mirror of the original fmem module. Later this repo became a maintained version of fmem to account for a changing Linux kernel. Bug reports and patches welcome. This module creates /dev/fmem device, that can be used for dumping physical memory, without limits of /dev/mem (1MB/1GB, depending on distribution). Tested on i386 and x64, feel free to test it on different architectures. (and send report please). Cloned from linux/drivers/char/mem.c (so GPL license apply). Original name of this tool was fdump, which was conflict with already existing tool, so name was changed to fmem.

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Support

fmem has a low active ecosystem.

It has 76 star(s) with 30 fork(s). There are 4 watchers for this library.

It had no major release in the last 6 months.

There are 2 open issues and 5 have been closed. On average issues are closed in 41 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of fmem is current.

Quality

fmem has 0 bugs and 0 code smells.

Security

fmem has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

fmem code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

fmem is licensed under the GPL-2.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

fmem releases are not available. You will need to build from source code and install.

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fmem Key Features

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fmem Examples and Code Snippets

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Community Discussions

Trending Discussions on fmem

Winsock - Retransmission Seq incremented

QUESTION

Winsock - Retransmission Seq incremented

Asked 2021-Aug-11 at 08:43

I get the following when communicating with a custom client. With custom client i mean a housemade PCB with a FPGA which runs the Triple-Speed Ethernet Intel FPGA IP. It does not make a difference if a switch is between the PC and the PCB.

Workflow seen from the Server(Windows PC) where i detect this behaviour with wireshark:

Connect to client (Syn - Syn/Ack - Ack) Winsock2.connect
Sending data > MTU with Winsock2.WSASend (4092 Bytes on a 4088 Bytes MTU)
Packet gets "fragmented" into 2 packets - do not fragment bit is set
A Retransmission happens (because the client answered too slow?)

I am using delphi 10.4 and use the Winsock2 functions. Bevore each send i check with select if fdwrite is set if FD_Isset. Nagle is deactivated.

The "retransmission" does not happen everytime and i could not detect any sort of pattern when they occur. Except most of the time it is when the client needs more than 30ms to send his ACK.

When the "retransmission" happens it is not packet 1 or two whicht is re-send, but packet 1 with an offset of 60 which is the payload of packet 2. The sequence number of packet 1 is incremented by 60 too. Even the data is correct, it's correctly incremented by 60. When I send 6000 Bytes i get the same behaviour with an incremented seq of 1968 which is correct too. What is happening here? Can i detect this with winsock2? Can i set the RTO with winsock? Why is the sequence number incremented and not packet 1, as it is, retransmitted?

Source Code of the send function:

...

ANSWER

Answered 2021-Aug-11 at 08:43

Got an answer on Microsoft Q&A. Looks like it was a tail loss probe problem where the destination host is at fault, because the reply took too long and srtt timed out.

Source https://stackoverflow.com/questions/68555195

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install fmem

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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