cups | OpenPrinting CUPS Sources | 3D Printing library
kandi X-RAY | cups Summary
kandi X-RAY | cups Summary
OpenPrinting CUPS is the most current version of CUPS, a standards-based, open source printing system for Linux and other Unix-like operating systems. CUPS supports printing to:. CUPS provides the System V ("lp") and Berkeley ("lpr") command-line interfaces, a configurable web interface, a C API, and common print filters, drivers, and backends for printing. The [cups-filters][3] project provides additional filters and drivers. CUPS is licensed under the Apache License Version 2.0 with an exception to allow linking against GNU GPL2-only software. See the files LICENSE and NOTICE for more information. [1]: [2]: [3]:
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of cups
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QUESTION
System.out.println("Write how many ml of water the coffee machine has: ");
int waterInMachine = scanner.nextInt();
System.out.println("Write how many ml of milk the coffee machine has: ");
int milkInMachine = scanner.nextInt();
System.out.println("Write how many grams of coffee beans the coffee machine has: ");
int beansInMachine = scanner.nextInt();
System.out.println("Write how many cups of coffee you will need: ");
int countCups = scanner.nextInt();
int water = 200 * countCups;
int milk = 50 * countCups;
int coffeeBeans = 15 * countCups;
int amountWater = waterInMachine;
int amountMilk = milkInMachine;
int amountCoffeeBeans = beansInMachine;
int count = 0;
while (amountWater > 200 && amountMilk > 50 && amountCoffeeBeans > 15) {
amountWater -= 200;
amountMilk -= 50;
amountCoffeeBeans -= 15;
count++;
}
if (waterInMachine >= water && milkInMachine >= milk && beansInMachine >= coffeeBeans && count > countCups) {
System.out.println("Yes, I can make that amount of coffee (and even " + (count - countCups) + " more than that)");
} else if (waterInMachine >= water && milkInMachine >= milk && beansInMachine >= coffeeBeans) {
System.out.println("Yes, I can make that amount of coffee");
} else if (count < countCups) {
System.out.println("No, I can make only " + count + " cup(s) of coffee");
}
ANSWER
Answered 2021-Jun-05 at 17:10You are making coffees while you have more than enough ingredients.
That means you won't make a coffee when you have exactly the right amount of ingredients.
Try changing this:
QUESTION
I have a JavaScript script that fetches API data like this:
...ANSWER
Answered 2021-Apr-26 at 12:58Use string concatenation to add the values from the object in your AJAX request to the HTML you output. As you're using a template literal already, the syntax is very simple:
QUESTION
I'm trying to make a Java program where it calculates the total price of 3 differently valued items. Currently I'm trying to figure out why it won't let me multiply together a preset price and the amount inputted. Sorry for sloppy coding, I don't know Java basically at all. Here is code:
...ANSWER
Answered 2021-Apr-21 at 00:26cup is a double type, so if you multiply a double with int you will always have a double value. Just change cupprice to double and everything will works fine
change line 10 to double cupprice;
QUESTION
I need to implement some kind of coffee machine. It has initial state of ingridients (WATER = 400; MILK = 540; BEANS = 120; EMPTY_CUPS = 9; MONEY = 550) and can do some actions (BUY = "buy" - buy some coffee(1 - espresso, 2 - latte, 3 - cappuccino); FILL = "fill" - add ingridients; TAKE = "take" - take all earned money; REMAINING = "remaining" - show remaining ingridients; EXIT = "exit"). After buying or filling the amount of ingridients changes. Here is my code
...ANSWER
Answered 2021-Apr-02 at 22:00Everytime you're calling water = WATER + add_water and similar, you're adding to a constant (capitalized) variable that never changes. What you want is water += add_water and so forth in your constants.
QUESTION
am looking to match everything before (and after) zero or more from a list of items. Here is what I am currently using: (?<=\))(.*)(?=(or|,|\())
In this case, I want to match everything after a closing parenthesis ) and everything before or , or ). This works ok (probably not optimally), however, if there are none of the 3 items match, there are no matches.
For example, the sentence 2 cups (500 ml) mushroom, or vegetable broth matches for mushroom, however, 2 cups (500 ml) mushroom doesn't match anything.
Basically, my goal is to find the ingredient from the ingredient + qty string, with the above sentence matching mushroom and the sentence salt matching the whole string salt
Here are more examples:
1 thyme sprig should match thyme sprig
1 garlic clove, chopped should match garlic clove
1 cup (180 g) quinoa, rinsed and drained should match quinoa
2 tbsp (30 ml) olive oil, plus more for serving should match olive oil
Vegan Parmesan, to taste returns Vegan Parmesan
The difference between the first 2 and last 2 is tricky, as if there is a closing parenthesis (as in the last 2 examples), the ingredient should be after the closing parenthesis. If there are no closing parenthesis (as in the first 2 examples, everything after the number should be taken.
...ANSWER
Answered 2021-Mar-19 at 21:22Add |$ (end of string) to the ending group: (?<=\))(.*?)(?=(or|,|\(|$))
Edit: After testing here, I found you also need to make the main group non-greedy.
QUESTION
I try to print an image from python script on Debian 10 using cups:
...ANSWER
Answered 2021-Mar-13 at 09:43Problem was solved with using PIL module. Working code:
QUESTION
I'm trying to write a code to remove all the words coming after a certain word from a set of words as below. I tested out but since I'm quite new to python I'm not sure if this code might cause a problem.
Can anyone review this code and point any possible risk from using this code?
...
ANSWER
Answered 2021-Mar-05 at 04:04I think your implementation is good, it could be simplified a little bit.
QUESTION
Hi I tried to match the words using spacy for the texts like
1 cups 1 1/2 cups 1 1/2-inch
To achieve this, I created matcher pattern as below.
...ANSWER
Answered 2021-Mar-03 at 21:24In Spacy 2.3.2, 1 1/2-inch is tokenized as ('1', 'NUM'), ('1/2-inch', 'NUM'), so there will be no match with your current patterns if you do not introduce a new, specific pattern.
Here is an example one: pattern3=[{'POS':'NUM'},{"TEXT": {"REGEX":"^\d+(?:/\d+)?-\w+$"}}];. The regex matches a token whose text starts with one or more digits, then has an optional sequence of / and one or more digits and then has a - and then any one or more word chars (letters, digits or _). You may replace \w with [^\W\d_] to match only letters.
QUESTION
I read a documentation saying nlp.pipe() has a better performance to deal with a large amount of data.
And the way to iterate is by calling the list of it.
But When I run this code, checking if the token is like a num doesn't work. and I checked the type of the object and it returns doc object not token object.
What should I do to check if the individual words are like_num and remove those?
...ANSWER
Answered 2021-Mar-03 at 05:09You loop through a list of docs. To get tokens, you need to loop through each doc. Something like:
[token.like_num for token in doc for doc in a]
QUESTION
I need to declare an array like this:
...ANSWER
Answered 2021-Mar-02 at 08:14for question: Is there any better way to declare the cups array
you can use another protocl Called DrinkGeneric like this and implement it by Cup Struct:
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