hummingbird | Hummingbird init system for Linux based operating systems

 by   Sweets C Version: Current License: MIT

kandi X-RAY | hummingbird Summary

kandi X-RAY | hummingbird Summary

hummingbird is a C library. hummingbird has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

hummingbird is an init system designed for speed. It does nothing more than start the system and stop the system by default. There are three main "runlevels", fs which is called directly after the pseudo filesystems necessary for the system to run have been mounted, interlude which is ran before dropping the user into a tty, and tty which is what is responsible for actually starting ttys.
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              hummingbird has a low active ecosystem.
              It has 235 star(s) with 8 fork(s). There are 12 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 10 have been closed. On average issues are closed in 20 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of hummingbird is current.

            kandi-Quality Quality

              hummingbird has 0 bugs and 0 code smells.

            kandi-Security Security

              hummingbird has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              hummingbird code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              hummingbird is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              hummingbird releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            hummingbird Key Features

            No Key Features are available at this moment for hummingbird.

            hummingbird Examples and Code Snippets

            No Code Snippets are available at this moment for hummingbird.

            Community Discussions

            QUESTION

            Add multiple filtering keywords to a single blog in a gallery?
            Asked 2022-Jan-03 at 16:39

            I am planning to add a filtering feature to my website blogs. For this, each blog post will be associated with a keyword. Selecting these keywords will show/filter all the blogs associated with that specific keyword category.

            In the code below, I have separated my blogs into 3 categories (Forest, Birds and Sea). However, I also want some of the blogs to be associated with multiple keywords (two or three), see the 'Forest Birds' section in the snippet below. If someone can help me with how to do it, that would be great.

            ...

            ANSWER

            Answered 2022-Jan-02 at 18:43

            Here's what you can change, on line 198:

            Source https://stackoverflow.com/questions/70558659

            QUESTION

            Scrapy: Unable to get data
            Asked 2021-Aug-17 at 07:59

            I'm trying to scrape this website www.zillow.com by using Scrapy. I'm trying to import addresses from a CSV file and trying to search by it. But getting error. Here is my code.

            csv_read.py ...

            ANSWER

            Answered 2021-Aug-16 at 16:56

            It's the response parsing methond, your should use response.xpath() but not response.body

            Source https://stackoverflow.com/questions/68793709

            QUESTION

            Python/Pandas: How do I replace specific values of a Pandas Data Frame based on individual id?
            Asked 2021-Jul-07 at 17:10

            I have a long Pandas dataset that contains a column called 'id' and another column called 'species', among other columns. I have to perform a change on the 'species' column, based on specific values of the 'id' column.

            For example, if the 'id' is '5555555' (as a string), then I want that the 'species' value change its current value 'dove' (also a string) to 'hummingbird'. So far I have been using the method:

            df.loc[df["id"] == '5555555', "species"] = 'hummingbird'

            Here is short sample data frame:

            ...

            ANSWER

            Answered 2021-Jul-07 at 17:10

            QUESTION

            RainLab.Blog Post List: List Sub-Categories under a specific Top-Level Category
            Asked 2021-Jun-07 at 16:04

            I'm working on an October CMS project which use a blog where I need to seperate blog posts in two major categories. When listing blog posts using the RainLab.Blog plugin's Post List component, I need to list categories that are sub-categories under a specific top-level category and exclude other categories.

            In the TWIG template, I want to iterate through and list out the categories that belong to "Birds" and not "Sealife".

            In the default Post List component, categories are listed like this:

            ...

            ANSWER

            Answered 2021-Jun-07 at 16:04

            If it's totally fine to hardcode category then you can simply compare categories parent's slug or id to hardcoded value.

            Here I am using the slug to compare parent, you can also use id it's totally up to you.

            Source https://stackoverflow.com/questions/67866066

            QUESTION

            Adding supervisor and other info into bookdown pdf_book
            Asked 2021-May-05 at 09:02

            I want to include my supervisor's name, course name etc. for my paper written in bookdown. I specifically want this information to be in different lines. So far I have tried this in the yaml:

            ...

            ANSWER

            Answered 2021-May-05 at 09:02

            Using a "line block" should do the trick:

            Source https://stackoverflow.com/questions/67397354

            QUESTION

            OS Error in the listdir function of os module
            Asked 2021-Apr-14 at 08:14

            I am learning the os module of python, where I wrote the following code to try out the functions of the module.

            Input:

            ...

            ANSWER

            Answered 2021-Apr-14 at 06:34

            In python, the backslash is used as an ignore symbol. So after each backslash add another backslash

            Source https://stackoverflow.com/questions/67086612

            QUESTION

            Button Placement on split screen design
            Asked 2020-Aug-22 at 14:14

            Im playing around with bootstrap and i've come up against something I am struggling to find an answer to.

            I want to put a 'Login' on the bottom right of the screen, near the fold. Below is my code:

            ...

            ANSWER

            Answered 2020-Aug-22 at 14:14

            QUESTION

            Python: nested dictionary problem: trying to run a 'if' command to print out a string
            Asked 2020-Jul-19 at 06:01

            I am trying to do following 2 things for this nested dictionary:

            1. If a bird is aggressive, print out a string advising us to 'cover our heads' using the 'actions' list in this print statement.

            2. If a bird is endangered, print out a string advising us to 'back away', also using the actions list in this print statement.

            Here's what I have so far. Any help is much appreciated!:

            ...

            ANSWER

            Answered 2020-Jul-19 at 04:49
            final_actions={}
            for key, value in rarebirds.items():
                if final_actions.get(key)==None:
                    final_actions[key]=[]
                if 'Aggressive' in value and value.get("Aggressive")==True:
                    final_actions[key].append(actions[1])
                if 'Endangered' in value and value.get("Endangered")==True:
                    final_actions[key].append(actions[0])
                if ('Aggressive' in value and value.get("Aggressive")==False) and ('Endangered' in value and value.get("Endangered")==False):
                    final_actions[key].append(actions[2])
            print(final_actions)
            

            Source https://stackoverflow.com/questions/62976274

            QUESTION

            Display Only More Than One Unique Customer/Address Per Truck Number
            Asked 2020-Apr-29 at 15:40

            Been working on a project in which a report will generated from the SQL Query. I wish to display all Shipments (based on unique automatic truck ID) which contain any combination of:

            • Unique Customers (based on Customer Number, more than one Customer Number per shipment)
            • Unique Addresses (based on defined Address Field, more than one unique Address per shipment)

            The output should look like this when the code runs correct:

            ...

            ANSWER

            Answered 2020-Apr-29 at 15:40
            SELECT * FROM (SELECT DISTINCT shp.shipmentID
                                                                   , ven.CustomerCode
                                                                   , ven.CustomerName
                                                                   , ads.FirstAddress
                                                                   , ads.SecondAddress
                                                                   , ads.ThirdAddress
                                                                   , ads.City
                                                                   , ads.State
                                                                   , ads.Zip
                                                                   , CASE WHEN(ads.Country LIKE 'US') THEN N'USA' ELSE 'CANADA' END AS Country
                                                                   , COUNT (shp.shipmentID) OVER (PARTITION BY shipmentID ORDER BY shp.shpID) AS cntshpID
            
            
                                    FROM dbo.OrderItems AS ori
                                    JOIN dbo.OrderLineProducts AS olns ON olns.olnID = ori.olnID
                                    JOIN dbo.OrderLines AS oln ON oln.olnID = olns.olnID
                                    JOIN dbo.Orders AS ord ON oln.ordID = ord.ordID
                                    JOIN dbo.VendorCustomer AS ven ON ven.venID = ord.venID
                                    JOIN dbo.OrderAddresses AS oa ON oa.ordID = ord.ordID
                                    JOIN dbo.Address AS ads ON ads.addID = oa.addID
                                    JOIN dbo.AddressType AS adst ON adst.atcID = ads.atcID
                                                                   AND adst.atcAddressTypeCode = N'SHIP'
                                    JOIN dbo.OrderItemShipments AS shpo ON ori.itmID = shpo.itmID
                                                                   AND ori.itmIDInstance = shpo.itmIDInstance
                                                                   AND ori.olnID = shpo.olnID
                                                                   AND ori.olnIDInstance = shpo.olnIDInstance
                                    JOIN dbo.Shipments AS shp ON shp.shpID = shpo.shipmentID
                                    WHERE shpo.shpID = shp.shipmentID
            
                                    GROUP BY shp.shipmentID
                                                     , ven.CustomerCode
                                                     , ven.CustomerName
                                                     , ads.FirstAddress
                                                     , ads.SecondAddress
                                                     , ads.ThirdAddress
                                                     , ads.City
                                                     , ads.State
                                                     , ads.aZip
                                                     , ads.Country) AS bb
            
            WHERE bb.cntshpID > 1
            
            ORDER BY shpID ASC
            

            Source https://stackoverflow.com/questions/61488423

            QUESTION

            How to extract key value from a JS object through a common function?
            Asked 2020-Jan-01 at 11:15

            I try to extract a value from JS object.

            Here is my data -

            ...

            ANSWER

            Answered 2020-Jan-01 at 08:21

            You don't need a for loop. If you know the structure of your object, then you can simple do the following:

            Source https://stackoverflow.com/questions/59550869

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install hummingbird

            You can download it from GitHub.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/Sweets/hummingbird.git

          • CLI

            gh repo clone Sweets/hummingbird

          • sshUrl

            git@github.com:Sweets/hummingbird.git

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