C-Programming | C programming example codes | Interpreter library

 by   adityamangal1 C Version: Current License: No License

kandi X-RAY | C-Programming Summary

kandi X-RAY | C-Programming Summary

C-Programming is a C library typically used in Utilities, Interpreter applications. C-Programming has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

C programming example codes.
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              C-Programming has a low active ecosystem.
              It has 8 star(s) with 1 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              C-Programming has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of C-Programming is current.

            kandi-Quality Quality

              C-Programming has 0 bugs and 0 code smells.

            kandi-Security Security

              C-Programming has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              C-Programming code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              C-Programming does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              C-Programming releases are not available. You will need to build from source code and install.

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            C-Programming Key Features

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            C-Programming Examples and Code Snippets

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            Community Discussions

            QUESTION

            Basic Programming Python3 practice question with runtime error from Hackerearth
            Asked 2022-Mar-05 at 11:27

            I am trying to solve a question where I am supposed to print the max number of a particular symbol that repeats continuously but I have to give inputs manually for each individual row. If I copy and paste the test cases it returns an error. Below is the full code and testcase with outputs given after.

            NOTE: if not fully understood the problem please visit https://www.hackerearth.com/practice/basic-programming/input-output/basics-of-input-output/practice-problems/algorithm/maximum-border-9767e14c/

            ...

            ANSWER

            Answered 2022-Mar-05 at 11:27

            QUESTION

            Native image with gluonfx fails if I use org.graalvm.nativeimage.c
            Asked 2022-Feb-28 at 13:02

            I have a JavaFx project that I am compiling to native with no problems using GluonFx.

            I recently had to add a feature that uses a DLL through to make use of its native functions. I have done this through GraalVm using this solution: https://yyhh.org/blog/2021/02/writing-c-code-in-javaclojure-graalvm-specific-programming/

            Now when trying to compile to native with gluonfx:build I am getting the following error:

            ...

            ANSWER

            Answered 2022-Feb-28 at 13:02

            Answered by José Pereda in comments

            "Did you add the required dependencies (like org.graalvm.nativeimage:library-support) to the project?"

            Adding the dependency solved my problem. Thanks

            Source https://stackoverflow.com/questions/71293023

            QUESTION

            StackOverflowError caused by memoized Fibonacci on Clojure
            Asked 2021-Dec-25 at 01:33

            Config

            Tested under clojure 1.10.3 and openjdk 17.0.1

            Problem

            Below is the slightly revised version of the memoized Fibonacci, and the general techniques refer to wiki memoization.

            ...

            ANSWER

            Answered 2021-Dec-20 at 16:30

            Memoize returns function, so you have to use def:

            Source https://stackoverflow.com/questions/70424825

            QUESTION

            Does C have 32 or 44 keywords?
            Asked 2021-Dec-23 at 02:10

            ISO/IEC 9899:2017 C N2176 document link: https://files.lhmouse.com/standards/ISO%20C%20N2176.pdf

            There are plenty of sources on world wide web, which say that there are 32 keywords in C langauge, But this document (I think it's a draft version, but there's no much changes as compared to the previous version, right?) has 44 words that are defined to the keywords of C language.

            Please explain this.

            ============================================================

            Link to the sources which say that there are 32 keywords in C language:

            1. https://www.programiz.com/c-programming/list-all-keywords-c-language
            2. https://tutorials.webencyclop.com/c-language/c-keyword/
            3. https://www.educba.com/c-keywords/
            4. https://www.javatpoint.com/keywords-in-c
            5. https://beginnersbook.com/2014/01/c-keywords-reserved-words/
            6. https://www.phptpoint.com/c-keywords/
            7. https://www.guru99.com/c-tokens-keywords-identifier.html
            8. https://fresh2refresh.com/c-programming/c-tokens-identifiers-keywords/
            9. https://www.w3schools.in/c-tutorial/keywords/

            Note: Some of these sites are useful for beginners to learn basic concepts and terminalogies of C.

            ...

            ANSWER

            Answered 2021-Dec-22 at 18:07
            • The claims of there being "32" keywords in C refer to the original ANSI-specified version of C from 1989, aka C89.
              • Because this is the Internet, and because the real C specifications are behind ISO's ridiculous paywall most people so-inclined probably can't fact-check the claim.
              • And it's not a claim worth fact-checking: the number of keywords in a language is utter trivia of no consequence.
            • The ISO/IEC 9899 specification you linked to refers to C17 (the proposed updated C specification in 2017) which postdates C89 by 28 years.
            • It should come as no surprise that a future updated revision of a programming language introduces new keywords.

            Historically, when C was introduced, people were impressed by its minimalist syntax and how the language's design effectively reified everything by implementing functionality as library features instead of language features which is what keeps C simple and helps mitigate every language's designer's fears about feature creep.

            In comparison, C's early contemporaries like COBOL, opted to implement functionality into their own languages as first-class features, which is why COBOL has over 300 keywords; so I'll admit that using the stark difference in keyword-count does serve as a proxy for language-complexity and by extension: a way to almost quantify good design. But using it as the basis for comparing languages today in 2021 is of limited-utility as the most relevant programming languages today1 are already either inspired by C or derived from it somehow, and they all share C's decision to do things in the library instead of the language, so all those languages similarly have a low keyword count compared to COBOL, SQL, and others, and so that's why C's keyword count just isn't interesting anymore.

            1: C-inspired or C-derived languages in use today: C++, Objective-C, Java, Groovy, Swift, C#, JavaScript, TypeScript, Go, PHP, Perl. Other popular languages that aren't modelled on C (like Haskell, OCaml, etc) do share C's library-first philosophy, but I can't say if C originated it or not - but I feel that languages opting for library-first designs is inevitable: the cost to implement language-features is easily ten-fold that of implementing library features.

            Source https://stackoverflow.com/questions/70452853

            QUESTION

            Cuda unified memory: Program gets different result when use pointer or non-pointer object as class member
            Asked 2021-Dec-22 at 10:27

            Recently, I learnt how to code using the cuda unified memory. But what weird is that the kernel reports different result when I replace the pointer object by the non-pointer one.

            Please refer to the Core.cuh and main.cu.

            The ClassManaged.h is base class for new and delete overload and CMakeList.txt for build the test case.

            ...

            ANSWER

            Answered 2021-Dec-22 at 10:27

            Question shows that when Core is as created by cudaMallocManaged, bug appears. However, for Core created by cudaMalloc and cudaMemcpy, the kernel gives the correct answer.

            This bug relates to CUDA DOC.

            In detail, the CUDA DOC denotes that:

            The CUDA compiler follows the IA64 ABI for class layout, while the Microsoft host compiler does not. Let T denote a pointer to member type, or a class type that satisfies any of the following conditions:

            T has virtual functions.

            T has a virtual base class.

            T has multiple inheritance with more than one direct or indirect empty base class.

            All direct and indirect base classes B of T are empty and the type of the first field F of T uses B in its definition, such that B is laid out at offset 0 in the definition of F.

            Let C denote T or a class type that has T as a field type or as a base class type. The CUDA compiler may compute the class layout and size differently than the Microsoft host compiler for the type C. As long as the type C is used exclusively in host or device code, the program should work correctly.

            Passing an object of type C between host and device code has undefined behavior e.g., as an argument to a global function or through cudaMemcpy*() calls.

            Since both of Box and Core are children of Managed (empty class overloading new and delete operator).

            If we place the box (non-pointer object) at the first field of Core, we meets the fourth case All direct and indirect base classes B of T are empty and the type of the first field F of T uses B in its definition.

            Due to the different ABI between Windows host (x64) and CUDA device (IA64), the undefined behaviour of kernel appears as result.

            -------------> Personal analysis

            The CUDA DOC also denotes that the undefined behaviour of kernel can be associated with class which is created on host but run on device and vice versa.

            In other words, Core created using cudaMalloc may avoid the bug by a consistent creation and run environment (both host or both device).

            The same thing for the box as pointer object, because it eliminates the bug by avoiding the fourth case (children class of a empty base class locates at the first field).

            Source https://stackoverflow.com/questions/70427559

            QUESTION

            How do I assign return variable in prolog?
            Asked 2021-Dec-14 at 02:38

            I'm totally new to Prolog so I might be really off here. I'm trying to solve the following problem for the past week:

            ...

            ANSWER

            Answered 2021-Dec-13 at 21:47

            QUESTION

            Non-termination when query variable is on a specific position
            Asked 2021-Nov-30 at 20:08

            Consider this blog post where the author implements palindrome relation using reverso:

            ...

            ANSWER

            Answered 2021-Nov-30 at 20:08

            The problem is that when you give appendo a fresh variable on the left and a fresh variable for the result, it can produce arbitrarily many answers, none of which will lead to a solution for your overall reverso question. Witness the definition of appendo:

            Source https://stackoverflow.com/questions/70159176

            QUESTION

            Cuda complex object initialization within device: problem with cudaDeviceSetLimit
            Asked 2021-Nov-19 at 08:31

            I am trying to initialize complex objects within my device, within threads and within blocks. It seems to me I have a problem with the cudaDeviceSetLimit. Given my understanding of the problem, I am not setting correctly the heap memory amount per thread. This part of the documentation refers to my problem. But they do not initialize an object. I have also read this post but wasn't able to get my code working.

            Edit

            Contrary to the first answer: doing this inside the kernel is a must in my problem configuration, because I want to take advantage of initializing the objects across blocks in parallel.

            I have made the following toy example which works for a low number of blocks (65) but not for 65535 blocks (the maximum amount of blocks I could use on my device):

            ...

            ANSWER

            Answered 2021-Nov-18 at 20:55

            To answer your question:

            Due to memory padding and allocation granularity, each block probably requires more memory than the calculated size. You should always check the return value of new. If it is nullptr, the allocation failed.

            However, if the total number of nodes for all networks is known up front, it would be more efficient to just cudaMalloc the memory for all nodes, (and all networks). Then, in the kernel just update the pointers accordingly.

            Something like this:

            Source https://stackoverflow.com/questions/70024184

            QUESTION

            Make all conroller methods async easy way
            Asked 2021-Nov-17 at 01:15

            I have a web api with controller methods being like this:

            ...

            ANSWER

            Answered 2021-Nov-17 at 01:15

            Is there some way to refactor only the controller, i.e. "topmost" methods into being asyncronous so server won't run out of threads?

            No.

            You can think of it this way: synchronous calls block a thread. As long as your business logic / DAL methods are synchronous, they will block a thread.

            As some have noted in the comments, Task.Run will allow those methods to block a thread pool thread instead of the calling thread, and that's a fine approach for many GUI apps (block thread pool threads instead of the GUI thread), but it's counterproductive on server apps (block one thread pool thread instead of another thread pool thread).

            I recommend first analyzing your app and determining which requests are the slowest or most frequently called, and changing just those to be async all the way. You can use the flag argument hack (attribution: me) to avoid code duplication in your logic/DAL types when creating asynchronous equivalents of synchronous methods.

            Source https://stackoverflow.com/questions/69731654

            QUESTION

            CUDA atomicAdd_block is undefined
            Asked 2021-Nov-02 at 22:56

            According to CUDA Programming Guide, "Atomic functions are only atomic with respect to other operations performed by threads of a particular set ... Block-wide atomics: atomic for all CUDA threads in the current program executing in the same thread block as the current thread. These are suffixed with _block, e.g., atomicAdd_block"

            However, I cannot use atomicAdd_block while my code is compiled fine with atomicAdd. Is there any header or library that I should add or link to?

            ...

            ANSWER

            Answered 2021-Nov-02 at 22:56

            atomicAdd() has been supported for a long time - by earlier versions of CUDA and with older micro-architectures. However, atomicAdd_system() and atomicAdd_block were introduced, IIANM, with the Pascal micro-architecture, in 2016. The minimum Compute Capability in which they are supported is 6.0. If you're targeting CC 5.2 or earlier - or if your CUDA version is several years old - then they might not be available to you.

            This is actually likely to be the case, since even for the current version of CUDA, nvcc will default to Compute Capability 5.2 if no other value is specified with -gencode or -arch (e.g. if you run nvcc -o out my_file.cu).

            Source https://stackoverflow.com/questions/69817605

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