AES-C | A C implementation of AES got from OpenSSL | Encryption library
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kandi X-RAY | AES-C Summary
A C implementation of AES got from OpenSSL.
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QUESTION
I'm using https://github.com/eblocha/django-encrypted-files to encrypt files uploaded to a server through a simple contact form app in Django. django-encrypted-files
uses AES in CTR mode to encrypt an uploaded file via an upload handler while streaming the file to the server.
What I'm trying to do is manually decrypt the encrypted file by downloading the file via FTP and decrypting it locally in the Python shell. I do not want or need to stream decrypt the file from the server or modify django-encrypted-files
; I only want to manually download and then decrypt files locally in the Python shell.
The problem is I can't get local Python decryption to work. The docs at Cryptography show an example of encryption and decryption using a sample text input in the Python shell. But there are no examples of encrypting/decrypting a file.
The code below what I'm trying to use in the Python shell. The original file uploaded via Django is uploaded_file.txt. The encrypted file downloaded from the server is encrypted.txt; the file to save the decrypted text to is decrypted.txt.
But when I try the code below, the decrypted.txt is empty. Is this an issue with writing the file? Or an issue with the iv
?
What is a working example of decrypting a AES-CTR mode file in the local Python shell?
uploaded_file.txt: https://paste.c-net.org/MiltonElliot
encrypted.txt: https://paste.c-net.org/ChasesPrints
Python shell:
...ANSWER
Answered 2022-Mar-22 at 20:33During encryption, IV and ciphertext are concatenated: IV || ciphertext
. During decryption, a random IV is used, which is wrong. Instead, the IV of the encryption must be applied. For this, IV and ciphertext have to be separated.
In addition, the update()
and finalize()
methods must be called, which perform the actual decryption.
The following code essentially matches your code, extended by the missing parts:
QUESTION
I am using this c library, and have the following:
...ANSWER
Answered 2022-Mar-13 at 20:07You cannot use a password as a key this way. If you have a human-typable password (such as "key"), you need to convert that to a key using a PBKDF such as PBKDF2. See http://bxr.su/OpenBSD/lib/libutil/pkcs5_pbkdf2.c#77 for an example implementation in C and https://en.wikipedia.org/wiki/PBKDF2 for a description of the algorithm.
In your code, the key you're using is 0x6b 0x65 0x79 0x00 ("key\0") followed by some number of semi-random garbage bytes that happened to be after argv[1]
in memory. That's why you get different results every time. (The number of garbage bytes depends on what key size you compiled into Tiny AES. The default key size is 128 bits, so it'll pick up 12 bytes of garbage data.)
Also, even with a proper key, the output content
will be unprintable. It will be a series of bytes with values between 0 and 255. Many of those values cannot be printed on a terminal, and as you've written it, you'll keep printing until you find the first zero (which will be at a random location, possibly somewhere inside the ciphertext, possibly after it). In order to print cipher text, you need to encode it somehow, such as Base64 or Hex. Tiny AES has no features for any of this; that's part of why it's so tiny. It just does the most basic AES encryption and decryption. Everything else is up to you.
QUESTION
I've already looked at several plausible options, but none seem to address my bug. Here are the three closest I found:
When I create a stacked 100% horizontal barplot, the individual components show as uniform grey. I want to use scale_color_brewer(type = "qual", palette = "Paired")
, but it doesn't work. I continue getting the same output (no error messages).
This is the data file and my code (none of the four fill methods shown in this block worked for me):
...ANSWER
Answered 2022-Jan-29 at 20:45As @stefan said in the comments, it's just a typo: use fill = Tasks
, not Fill
.
Changing that fixes the problem immediately.
QUESTION
I need to generate and verify 4 byte MAC from the data which is authenticated only using AES-CCM with 32 bytes of key and a Nonce.
I tried using "CcmBlockCipher(new AesEngine())" object but it expects data to be encrypted or decrypted. However, the data I have got is not encrypted but has plain text data + MAC in it which is only mean to authenticate purpose using AES-CCM.
How to use BouncyCastle C# library in order to just generate MAC on plain text data using AES-CCM and verify the same from the received MAC?
...ANSWER
Answered 2022-Jan-16 at 03:18This type of data is commonly called "additional authenticated data" (AAD). It will be included in the calculation of the authentication tag, but not encrypted (resp. decrypted).
You can use the ProcessAadBytes
(also ProcessAadByte
) method to provide this type of input to CcmBlockCipher
. Note that there is no output buffer for these methods because the cipher doesn't consider AAD part of its "stream".
So in your case, for "encryption", with no actual data to encrypt, you just add all the plaintext using ProcessAadBytes
and then call DoFinal
to get the output, which will consist only of the authentication tag. If you need to send the plaintext also, you have to arrange that yourself.
Similarly for decryption, CcmBlockCipher
does not consider the AAD as part of its usual input; it should be added using ProcessAadBytes
, followed by a DoFinal
that consists of just the tag in your case.
QUESTION
I'm using electron(you can consider it as nodejs) for making a player for playing encrypted videos. using code below I'm able to encypt videos
exec(
ffmpeg -i "${file}" -encryption_scheme cenc-aes-ctr -encryption_key ${encryptionKey} -encryption_kid ${encryptionKey} "${pathWithoutExtension}".CONVERTED.${extension}
)
and using this command I'm able to decypt and at the same time play the video
...ANSWER
Answered 2022-Jan-13 at 10:41finaly find the solution: this command added text watermark to encrypted file and show it during playtime
QUESTION
I'm trying to implement a simple encryption-decryption script with pycryptodome and AES-CBC, that is:
- no iv,
- no padding, therefore the string to encrypt is stripped do 16 characters
- key is not random and is a fixed string. However I fail by decrypting the message. Here is the script:
ANSWER
Answered 2022-Jan-08 at 07:34Unlike ECB, CBC does require an initialization vector. As the documentation says:
If [iv argument] not provided, a random byte string is generated (you must then read its value with the iv attribute).
To apply that to your code:
QUESTION
How can I force a function to resolve a pending promise before using it in JavaScript
...ANSWER
Answered 2021-Nov-23 at 05:13QUESTION
I arrived at the following code and would like to know if this is a correct and secure way to generate an AES-CBC-192 cipher with CryptoJS:
Original Question Code:
...ANSWER
Answered 2021-Nov-22 at 21:04here one i just finished for AES-CBC-256 from a password using PBKdf2, this is using the Web crypto api https://developer.mozilla.org/en-US/docs/Web/API/Web_Crypto_API
not what you are looking for exactly but it might help with direction, remove importKey from below and read up on https://developer.mozilla.org/en-US/docs/Web/API/SubtleCrypto/generateKey
QUESTION
I am doing some dpdk cryptodev tests related to throughout with intel QAT. When using the dpdk app dpdk-test-crypto-perf , I notice that the throughput is way less than what is mentioned in http://fast.dpdk.org/doc/perf/DPDK_20_11_Intel_crypto_performance_report.pdf
...ANSWER
Answered 2021-Nov-16 at 07:44Based on the logs and live to debug it is concluded the performance is in line with the expected values of both SW and HW
. Following are the reasons variation
- QAT HW crypto is done on Xeon cascade lake cores
- SW Crypto is run on corei7 11th gen platform
- Core clocks on corei7 goes up to 5Ghz with turbo boost
- HW crypto is run with CPU cores from remote NUMA
- HW crypto is limited with memory controller to use with
-n 4
- HW crypto runs for a total of
30000000
and SW crypto is run for10000000
- HW crypto devices are 3 but lcores passed is 5 causing 2 lcores to share the same HW.
- HW crypto is done over 3 VF hence total capacity should be summed up rather than individual results.
With these the right command to use is
HW: ./dpdk-test-crypto-perf --socket-mem 2048,1 --legacy-mem -l 4,6 -w 0000:3d:01.0 -- --buffer-sz 64,128,256,512,1024,2048 --optype cipher-then-auth --ptest throughput --auth-key-sz 64 --cipher-key-sz 16 --cipher-iv-sz 16 --auth-op generate --burst-sz 32 --total-ops 30000000 --silent --digest-sz 20 --auth-algo sha1-hmac --cipher-algo aes-cbc --cipher-op encrypt --devtype crypto_qat
SW: ./dpdk-test-crypto-perf --socket-mem 2048,1 --legacy-mem -l 4,6 --vdev crypto_aesni_mb_pmd_1 -a 0000:00:00.0 -- --buffer-sz 64,128,256,512,1024,2048 --optype cipher-then-auth --ptest throughput --auth-key-sz 64 --cipher-key-sz 16 --cipher-iv-sz 16 --auth-op generate --burst-sz 32 --total-ops 30000000 --silent --digest-sz 20 --auth-algo sha1-hmac --cipher-algo aes-cbc --cipher-op encrypt --devtype crypto_aesni_mb
for 64B on Xeon (3.1Ghz) we were able to get 3.2Gbps, while corei7 (5Ghz) with SW was able to get 4.2Gbps. with 2048B HW on Xeon were able to achieve 50Gbps while SW 19.2Gbps.
Note: in Xeon there are drops for enqueue and dequeue, which can be reduced with platform and BIOS settings further.
QUESTION
I am trying to convert the following Java encryption snippet to C#
...ANSWER
Answered 2021-Oct-11 at 11:23The reason is you are using StreamWriter
, which is intended to write text into the stream, but then you write raw bytes there:
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