lci | A lambda calculus interpeter
kandi X-RAY | lci Summary
kandi X-RAY | lci Summary
LCI - A lambda calculus interpreter Copyright (C) 2004-8 Kostas Chatzikokolakis. This program is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 2 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program; if not, write to the Free Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA.
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QUESTION
I'm working on a habitat occupancy prediction encompassing the entire state of Wyoming. Certain site covariate rasters work in the prediction while others with matched resolution, extent, etc. do not.
A short reproduceable example of my code is below. After extensive troubleshooting I've found I have 3 rasters of the 5 I need to use that cause this script to fail, all with the same error. I'm assuming my rasters have somehow become corrupted(?) but wanted to see if anyone has another idea on what could be happening.
Data is at this link. The data is the unmarked object (saved as .rds) and 2 very small clips off of: 1. the raster that works, and 2. one of the rasters that does not work
Steps I took to originally align the rasters for stacking - for information purposes ...ANSWER
Answered 2021-Jun-07 at 08:27Answer
The error arises because you have missings in sNoJoy
. Had those not been missing, it would have worked just fine.
Question rewritten
Your problem has nothing to do with your parallel code. It boils down to this:
QUESTION
I expect identical results calculating a CI for a proportion using qbinom
and binom.test
, but they are actually slightly different:
ANSWER
Answered 2021-Jun-05 at 16:15The source code for the binom.test
function uses qbeta
rather than qbinom
, as this is the accepted formula for exact binomial confidence intervals. Where x
is the number of successes, the lci and uci as given by binom.test
are:
QUESTION
I am trying to figure out how to autofill a specific range of cells based on already defined data in the same row. My task is more complex, but a simplification of the step can be seen in the code below. What I want to achieve is:
- Define a range where I want to output my values
- Multiply two values in the same row of the selected range cell (to its left), and output this number in the currently selected range cell. To do this, one of the numbers to be multiplied will be dependant on a string also in the row (which describes its type).
- Loop through the defined range and repeat the calculation on each row.
My current code is as follows and outputs a "application defined or object defined error".
Any help would be much appreciated.
...ANSWER
Answered 2021-May-25 at 14:04You are close.
You need to think of
a
as a cell or Range object. That variable is the cell itself which has properties likea.row
anda.column
that describe its location on the sheet in which it lives. When you sayCells(a, -10)
you are saying "On theActivesheet
I want a Cell where the row isa
, and where the column has the number-10
". There is no rowa
(asa
is a range/cell object and because you didn't specify which property ofa
you are wanting here it will default toa.value
which is probably nothing) and there is no column-10
on the Activesheet.Your loop is defined incorrectly. You can use a For Each loop to loop through cells in a range.
Instead:
QUESTION
I have imported ecoinvent 3.7.1 on a brightway project and i followed a few tutorials to understand brightway set up procedures and usage.
I want to use brightway to perform calculations on the inventory data of some processes (in particular i want to sum all emissions to air of CO2, CH4, N2O.
I tried with:
...ANSWER
Answered 2021-May-06 at 07:30you ask several things in the same question, but I will try to answer them.
lets take as an example the query you used. If I run
QUESTION
I want to analyse individual data frames within a list of data frames and then store the results of each individual analysis in a new data frame. Any advice would be great, i've tried lapply()
and a for loop
but can't get either working.
I have a list of data frames:
...ANSWER
Answered 2021-May-06 at 14:39You were almost there. You can use lapply
like so:
QUESTION
I'm trying to receive stock data for about 1000 stocks, to speed up the process I'm using multiprocessing, unfortunately due to the large amount of stock data I'm trying to receive python as a whole just crashes.
Is there a way to use multiprocessing without python crashing, I understand it would still take some time to do all of the 1000 stocks, but all I need is to do this process as fast as possible.
...ANSWER
Answered 2021-Jan-31 at 19:18Ok, here is one way to obtain what you want in about 2min. Some tickers are bad, that's why it crashes.
Here's the code. I use joblib for threading or multiprocess since it doesn't work in my env. But, that's the spirit.
QUESTION
I'm having the hardest time generating confidence intervals for my glmer poisson model. After following several very helpful tutorials (such as https://drewtyre.rbind.io/classes/nres803/week_12/lab_12/) as well as stackoverflow posts, I keep getting very strange results, i.e. the upper and lower limits of the CI are identical.
Here is a reproducible example containing a response variable called "production," a fixed effect called "Treatment_Num" and a random effect called "Genotype":
...ANSWER
Answered 2021-Jan-07 at 16:05Ignore my comment!
The issue is with the function you created to pass to bootMer()
. You wrote:
QUESTION
I am plotting a smooth to my data using geom_smooth
and using geom_ribbon
to plot shaded confidence intervals for this smooth. No matter what I try I cannot get a single legend that represents both the smooth and the ribbon correctly, i.e I am wanting a single legend that has the correct colours and labels for both the smooth and the ribbon. I have tried using + guides(fill = FALSE)
, guides(colour = FALSE)
, I also read that giving both colour
and fill
the same label inside labs()
should produce a single unified legend.
Any help would be much appreciated.
Note that I have also tried to reset the legend labels and colours using scale_colour_manual()
The below code produces the below figure. Note that there are two curves here that are essentially overlapping. The relabelling and setting couours has worked for the geom_smooth
legend but not the geom_ribbon
legend and I still have two legends showing which is not what I want.
ANSWER
Answered 2020-Nov-05 at 10:23The problem is that you provide new labels for the color-aesthetic but not for the fill-aesthetic. Consequently ggplot shows two legends because the labels are different.
You can either also provide the same labels for the fill-aesthetic (code option #1 below) or you can set the labels for the levels of your grouping variable ("tagged") before calling ggplot (code option #2).
QUESTION
I've tried to write an implementation of the Weasel Program. I have compiled three versions, all exactly identical, with the names "weasel.exe", "weasel2.exe", and "weasel3.exe". "weasel.exe" produces the expected output,
...ANSWER
Answered 2020-Aug-25 at 16:48As a first step, change your generateOffspring
loop as follows:
QUESTION
I have a dataframe, df
:
ANSWER
Answered 2020-Aug-24 at 14:08I would suggest next approach. You can define the variables to keep as cols
in pivot_longer()
and then order columns and arrange rows:
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