dictd | server software , human language dictionary databases

 by   cheusov C Version: 1.13.1 License: No License

kandi X-RAY | dictd Summary

kandi X-RAY | dictd Summary

dictd is a C library. dictd has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Client/server software, human language dictionary databases, and tools supporting the DICT protocol (RFC 2229)
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              dictd has a low active ecosystem.
              It has 55 star(s) with 9 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 10 open issues and 3 have been closed. On average issues are closed in 8 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of dictd is 1.13.1

            kandi-Quality Quality

              dictd has no bugs reported.

            kandi-Security Security

              dictd has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              dictd does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              dictd releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            dictd Key Features

            No Key Features are available at this moment for dictd.

            dictd Examples and Code Snippets

            No Code Snippets are available at this moment for dictd.

            Community Discussions

            QUESTION

            IndexError: list index out of range error on python
            Asked 2021-Jun-03 at 09:13

            This is my code:

            ...

            ANSWER

            Answered 2021-Jun-03 at 09:02

            The problem you have in your code is with the empty strings in your items.txt file. When there's an empty string, fire would resolve to [''], which is a list of only 1 item, so you get an error when the code tries to run c = fire[1]. You can add a check to see if it's an empty line or not:

            Source https://stackoverflow.com/questions/67818280

            QUESTION

            ANTLR4 no viable alternative at input 'do { return' error?
            Asked 2021-Mar-27 at 14:13

            This ANTLR4 parser grammar errors a 'no viable alternative' error when I try to parse an input. The only rules I know of that matches the part of the input with the error are the rules 'retblock_expr' and 'block_expr'. I have put 'retblock_expr' infront of 'block_expr' and put 'non_assign_expr' infront of 'retblock_expr' but it still throws the error.

            input:

            print(do { return a[3] })

            full error:

            line 1:11 no viable alternative at input '(do { return'

            parser grammar:

            ...

            ANSWER

            Answered 2021-Mar-27 at 14:13

            Your PRINT token can only be matched by the blk_expr rule through this path:

            There is no path for retblock_expr to recognize anything that begins with the PRINT token.

            As a result, it will not matter which order you have elk_expr or retblock_expr.

            There is no parser rule in your grammar that will match a PRINT token followed by a LPR token. a block_expr is matched by the program rule, and it only matches (ignoring wsp) block_expr or retblock_expr. Neither of these have alternatives that begin with an LPR token, so ANTLR can't match that token.

            print(...) would normally be matched as a function call expression that accepts 0 or more comma-separated parameters. You have no sure rule/alternative defined. (I'd guess that it should be an alternative on either retblock_expr or block_expr

            That's the immediate cause of this error. ANTLR really does not have any rule/alternative that can accept a LPR token in this position.

            Source https://stackoverflow.com/questions/66831117

            QUESTION

            Why is my ANTLR4 parser grammar erroring 'no viable alternative at input'?
            Asked 2021-Mar-25 at 02:52

            When I run my grammar (lexer and parser) in powershell, it produces these errors:

            ...

            ANSWER

            Answered 2021-Mar-23 at 10:50

            Both global and a are listed in your grammer under kwr rule.

            kwr is mentioned in the inl rule which isn't used anywhere. So your parser don't know how to deal with inl and don't know what to do with two inl chained together (global a)

            Source https://stackoverflow.com/questions/66761457

            QUESTION

            Calculate time difference in a Python dictionary
            Asked 2021-Jan-24 at 11:14
            • I have a Dictionary called d, which maps different number of dates for each key. I have multiple keys.
            • What I really want to do, is to calculate the total time difference between the earliest and latest date for each key.
            • I have tried few different ways but nothing works, as I don't seem to be able to access the values sequentially and perform operations.

            This is my code:

            ...

            ANSWER

            Answered 2021-Jan-23 at 22:48

            This code below will do the trick:

            Source https://stackoverflow.com/questions/65865112

            QUESTION

            returning **unique** counts from each row json data
            Asked 2019-Jan-31 at 18:39

            I've been working on this for a while and can't quite seem to get around it: I have a block of JSON data that looks like this

            ...

            ANSWER

            Answered 2019-Jan-28 at 07:26

            Can't understand the second for loop the temp_list is created at every iteration as empty list, then why do you need to do this lis = tuple(set(temp_list)) instead read it in a variable name :

            Source https://stackoverflow.com/questions/54397092

            QUESTION

            How to get a placeholder from a list of placeholders using a placeholder in Tensorflow?
            Asked 2018-Mar-14 at 08:29

            I have a list of placeholders as follows:

            ...

            ANSWER

            Answered 2018-Mar-14 at 08:29

            You just need to reshape your output from tf.gather as explained in this answer:

            Source https://stackoverflow.com/questions/49271153

            QUESTION

            Writing line, reading line, then closing a socket
            Asked 2017-Apr-14 at 17:46

            I need to connect from Java to a tcp/ip socket, in order to execute a few things:

            1) read data from the socket (the optional 'hello' message), then discard it;

            2) write a single line of data, as a string, to the socket;

            3) read the response from the socket, a single line, and store it into a String;

            4) close the socket;

            I wrote this code:

            ...

            ANSWER

            Answered 2017-Apr-14 at 17:46

            Your method is called writeLine but it doesn't write a line, unless the string already has a line terminator. Add one.

            Source https://stackoverflow.com/questions/43414323

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install dictd

            You can download it from GitHub.

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            https://github.com/cheusov/dictd.git

          • CLI

            gh repo clone cheusov/dictd

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            git@github.com:cheusov/dictd.git

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