papaya | 8912 sound chip expansion board for the Raspberry
kandi X-RAY | papaya Summary
kandi X-RAY | papaya Summary
an AY-3-8912 sound chip expansion board for the Raspberry Pi.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of papaya
papaya Key Features
papaya Examples and Code Snippets
Community Discussions
Trending Discussions on papaya
QUESTION
This is not a Duplicate question, I spent 3 days searching here and there is no other question similar to mine!
This javascript generates random words only when called from one single div, or the first one when trying different DOM Methods to get Elements.
I've tried several options and combinations with getElementsBy ID, Tag, Name, Class, and CSS Selector.
However after several days searching and testing, I can't make it work in more than one div.
I need to use the same array as the only source for all my 36 divs, to generate random words from an onClick event on each of them.
I'm open to edit it, or completely change it.
This is what I have currently working for the first div using getElementsByClassName which I suppose should be the correct way as I need to call this script from several elements, not just one:
...ANSWER
Answered 2021-Jun-13 at 21:11You can create a loop to add the click handler to all fruits
QUESTION
I want to eliminate the nested loop in my code and I can't seem to figure out the best way to do it. I have explained what I am trying to do below:
I have a dataframe df.
...ANSWER
Answered 2021-Jun-02 at 07:20my approach would be using .explode()
method and pandas.merge()
function.
QUESTION
I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:
...ANSWER
Answered 2021-May-27 at 21:44You are setting the ingredients
state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError
. If you want to send an array that way you must specify the array bracket [
and ]
in order to make it a valid array.
To solve it just change:
QUESTION
I want to aggregate over a dataframe, and sum it up by category. I have this
...ANSWER
Answered 2021-May-10 at 14:27With [1,]
you are subsetting rows and not columns. With [,1]
you select the first column as a vector. With [1]
you select the first column as a data.frame.
QUESTION
I have been trying to develop a search suggestion in React. The search suggestions will be displayed as the user types.
You can find the code on the link - https://codesandbox.io/s/heuristic-shaw-rqp2k?file=/src/Autocomplete.js
What I want to achieve is that the suggestions appearing must have a part in bold that the user typed.
Example - When the user types "pa" in the input field, we get two suggestions- Papaya and Paw Paw
So, the suggestion should appear as Papaya and Paw Paw.
I have been trying to use the replace method to achieve that by doing something like below -
...ANSWER
Answered 2021-May-05 at 15:53You can use dangerouslySetInnerHTML.
dangerouslySetInnerHTML is React’s replacement for using innerHTML in the browser DOM
instead of:
QUESTION
I have the following State
shape and want to define a flattened slice
const that has the types of the state properties without needing to explicitly define/reference them again, so I would like a mapped type like MapFlatSlice
:
ANSWER
Answered 2021-Apr-24 at 01:32Using a utility type ArrayType
to extract the keys from your const slice
arrays:
QUESTION
am trying to build a word guessing game. The function I'm trying to build should be able to display correctly guessed and repeating letters alongside blanks for not-yet-guessed letters. I got an index out of range error. Should I write an index method for all guesses and then reformat it back to string?
...ANSWER
Answered 2021-Apr-20 at 09:17The problem is that the blank
list only has one element, because you are re-initializing the value for each iteration of this loop:
QUESTION
am trying to build a function for a word guessing game, where the guessed letter will be displayed alongside blank space for yet-to-be guessed letters. In the following code I get type error, which says the guessed letter, a string, can't be concatenated in the list. Is this because of .join() being used incorrectly? Thanks!
...ANSWER
Answered 2021-Apr-19 at 05:07You have a couple of problems. You need to move blank = []
out of the loop, otherwise you reset the list every time. Your second join
call is not correct, but not because of join
, it's because you're "adding" three things here: a list, a string, and a list, and that's not allowed. You COULD turn them all into lists by making alist of the guess:
QUESTION
public class MainActivity extends AppCompatActivity {
SearchView searchView;
ListView listView;
ArrayList list;
ArrayAdapter adapter;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
searchView = findViewById(R.id.searchView);
listView = findViewById(R.id.listView);
list = new ArrayList<>();
list.add("Apple");//0th item
list.add("Apple");//1st item
list.add("Banana");//2nd item
list.add("Banana");//3rd item
list.add("Pineapple");//4th item
list.add("Pineapple");//5th item
list.add("Orange");//6th item
list.add("Orange");//7th item
list.add("Mango");//8th item
list.add("Mango");//9th item
list.add("Grapes");//10th item
list.add("Grapes");//11th item
list.add("Lemon");//12th item
list.add("Lemon");//13th item
list.add("Melon");//14th item
list.add("Watermelon");//15th item
list.add("Watermelon");//16th item
list.add("Papaya");//17th item
list.add("Papaya");//18th item
adapter = new ArrayAdapter(this, android.R.layout.simple_list_item_1,list);
listView.setAdapter(adapter);
searchView.setOnQueryTextListener(new SearchView.OnQueryTextListener() {
@Override
public boolean onQueryTextSubmit(String query) {
if(list.contains(query))
{
// Toast.makeText(getApplicationContext(),query,Toast.LENGTH_SHORT).show();
adapter.getFilter().filter(query);
}
else
{
Toast.makeText(MainActivity.this, "No Match found",Toast.LENGTH_LONG).show();
}
return false;
}
@Override
public boolean onQueryTextChange(String newText) {
adapter.getFilter().filter(newText);
//Toast.makeText(getApplicationContext(),newText,Toast.LENGTH_SHORT).show();
return false;
}
});
listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView parent, View view, int position, long id) {
int itemPosition = position;
Toast.makeText(MainActivity.this,adapter.getItem(position)+ "",Toast.LENGTH_SHORT).show();
String itemValue = (String) adapter.getItem(position);
Toast.makeText(getApplicationContext(),
"Position :"+itemPosition+" ListItem : " +itemValue , Toast.LENGTH_LONG)
.show();
}
});
}
}
...ANSWER
Answered 2021-Apr-13 at 15:03If you do a search for example using 'P', pineapple and papaya will be returned. Initially before search Pineapple is positions 4 and 5 and Papaya is 17th and 18th. But when you search only four results will be returned so Pineapple will be position 0, 1 and Papaya will be position 2 and 3. The position of items changes with the number of items in the list. So the behaviour you are seeing is the expected and correct one.
QUESTION
I have a Google spreadsheet with a column that looks like this:
Each cell is dropdown list containing Fruits = [Apple,Orange,Pineapple,Papaya,Cherry,Strawberry]
S.NO | Fruits- ...
ANSWER
Answered 2021-Apr-04 at 08:27If I understood correctly and assuming the fruits are in the range A2:A10, you should be able to use
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install papaya
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page