papaya | 8912 sound chip expansion board for the Raspberry

 by   gasman C Version: Current License: No License

kandi X-RAY | papaya Summary

kandi X-RAY | papaya Summary

papaya is a C library typically used in Internet of Things (IoT), Raspberry Pi, Pygame applications. papaya has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

an AY-3-8912 sound chip expansion board for the Raspberry Pi.
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              papaya has a low active ecosystem.
              It has 13 star(s) with 1 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              papaya has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of papaya is current.

            kandi-Quality Quality

              papaya has no bugs reported.

            kandi-Security Security

              papaya has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              papaya does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              papaya releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of papaya
            Get all kandi verified functions for this library.

            papaya Key Features

            No Key Features are available at this moment for papaya.

            papaya Examples and Code Snippets

            No Code Snippets are available at this moment for papaya.

            Community Discussions

            QUESTION

            Make this javascript random word generator work on many divs within the same document, from the same single array, onclick event
            Asked 2021-Jun-13 at 22:13

            This is not a Duplicate question, I spent 3 days searching here and there is no other question similar to mine!

            This javascript generates random words only when called from one single div, or the first one when trying different DOM Methods to get Elements.

            I've tried several options and combinations with getElementsBy ID, Tag, Name, Class, and CSS Selector.

            However after several days searching and testing, I can't make it work in more than one div.

            I need to use the same array as the only source for all my 36 divs, to generate random words from an onClick event on each of them.

            I'm open to edit it, or completely change it.

            This is what I have currently working for the first div using getElementsByClassName which I suppose should be the correct way as I need to call this script from several elements, not just one:

            ...

            ANSWER

            Answered 2021-Jun-13 at 21:11

            You can create a loop to add the click handler to all fruits

            Source https://stackoverflow.com/questions/67962647

            QUESTION

            Replacing nested loops over a dataframe with faster/more efficient alternatives
            Asked 2021-Jun-02 at 07:46

            I want to eliminate the nested loop in my code and I can't seem to figure out the best way to do it. I have explained what I am trying to do below:

            I have a dataframe df.

            ...

            ANSWER

            Answered 2021-Jun-02 at 07:20

            my approach would be using .explode() method and pandas.merge() function.

            Source https://stackoverflow.com/questions/67800146

            QUESTION

            Posting array of objects to REST API with ReactJS
            Asked 2021-May-28 at 07:30

            I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:

            ...

            ANSWER

            Answered 2021-May-27 at 21:44

            You are setting the ingredients state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError. If you want to send an array that way you must specify the array bracket [ and ] in order to make it a valid array.

            To solve it just change:

            Source https://stackoverflow.com/questions/67730171

            QUESTION

            Aggregate and sum a dataframe
            Asked 2021-May-10 at 17:29

            I want to aggregate over a dataframe, and sum it up by category. I have this

            ...

            ANSWER

            Answered 2021-May-10 at 14:27

            With [1,] you are subsetting rows and not columns. With [,1] you select the first column as a vector. With [1] you select the first column as a data.frame.

            Source https://stackoverflow.com/questions/67472112

            QUESTION

            How to make the part of search suggestion bold based on the user input?
            Asked 2021-May-06 at 06:26

            I have been trying to develop a search suggestion in React. The search suggestions will be displayed as the user types.

            You can find the code on the link - https://codesandbox.io/s/heuristic-shaw-rqp2k?file=/src/Autocomplete.js

            What I want to achieve is that the suggestions appearing must have a part in bold that the user typed.

            Example - When the user types "pa" in the input field, we get two suggestions- Papaya and Paw Paw

            So, the suggestion should appear as Papaya and Paw Paw.

            I have been trying to use the replace method to achieve that by doing something like below -

            ...

            ANSWER

            Answered 2021-May-05 at 15:53

            You can use dangerouslySetInnerHTML.

            dangerouslySetInnerHTML is React’s replacement for using innerHTML in the browser DOM

            instead of:

            Source https://stackoverflow.com/questions/67404248

            QUESTION

            How can I create this mapped type to reduce the input to the desired shape?
            Asked 2021-Apr-25 at 02:13

            I have the following State shape and want to define a flattened slice const that has the types of the state properties without needing to explicitly define/reference them again, so I would like a mapped type like MapFlatSlice:

            ...

            ANSWER

            Answered 2021-Apr-24 at 01:32

            Using a utility type ArrayType to extract the keys from your const slice arrays:

            Source https://stackoverflow.com/questions/67236922

            QUESTION

            Is an index method needed here? (python)
            Asked 2021-Apr-20 at 09:17

            am trying to build a word guessing game. The function I'm trying to build should be able to display correctly guessed and repeating letters alongside blanks for not-yet-guessed letters. I got an index out of range error. Should I write an index method for all guesses and then reformat it back to string?

            ...

            ANSWER

            Answered 2021-Apr-20 at 09:17

            The problem is that the blank list only has one element, because you are re-initializing the value for each iteration of this loop:

            Source https://stackoverflow.com/questions/67174925

            QUESTION

            Is .join() being used incorrectly or is there other mistake? (python)
            Asked 2021-Apr-19 at 05:07

            am trying to build a function for a word guessing game, where the guessed letter will be displayed alongside blank space for yet-to-be guessed letters. In the following code I get type error, which says the guessed letter, a string, can't be concatenated in the list. Is this because of .join() being used incorrectly? Thanks!

            ...

            ANSWER

            Answered 2021-Apr-19 at 05:07

            You have a couple of problems. You need to move blank = [] out of the loop, otherwise you reset the list every time. Your second join call is not correct, but not because of join, it's because you're "adding" three things here: a list, a string, and a list, and that's not allowed. You COULD turn them all into lists by making alist of the guess:

            Source https://stackoverflow.com/questions/67156143

            QUESTION

            Not Showing Correct Position While Searching in Listview
            Asked 2021-Apr-13 at 15:03
            public class MainActivity extends AppCompatActivity {
              
                SearchView searchView;
                ListView listView;
                ArrayList list;
                ArrayAdapter adapter;
            
                @Override
            
                protected void onCreate(Bundle savedInstanceState) {
                    super.onCreate(savedInstanceState);
                    setContentView(R.layout.activity_main);
                    searchView = findViewById(R.id.searchView);
                    listView = findViewById(R.id.listView);
            
                    list = new ArrayList<>();
                    list.add("Apple");//0th item
                    list.add("Apple");//1st item
                    list.add("Banana");//2nd item
                    list.add("Banana");//3rd item
                    list.add("Pineapple");//4th item
                    list.add("Pineapple");//5th item
                    list.add("Orange");//6th item
                    list.add("Orange");//7th item
                    list.add("Mango");//8th item
                    list.add("Mango");//9th item
                    list.add("Grapes");//10th item
                    list.add("Grapes");//11th item
                    list.add("Lemon");//12th item
                    list.add("Lemon");//13th item
                    list.add("Melon");//14th item
                    list.add("Watermelon");//15th item
                    list.add("Watermelon");//16th item
                    list.add("Papaya");//17th item
                    list.add("Papaya");//18th item
            
                    adapter = new ArrayAdapter(this, android.R.layout.simple_list_item_1,list);
                    listView.setAdapter(adapter);
            
                    searchView.setOnQueryTextListener(new SearchView.OnQueryTextListener() {
                        @Override
                        public boolean onQueryTextSubmit(String query) {
                            if(list.contains(query))
                            {
                                // Toast.makeText(getApplicationContext(),query,Toast.LENGTH_SHORT).show();
                                adapter.getFilter().filter(query);
                            }
                            else
                            {
                                Toast.makeText(MainActivity.this, "No Match found",Toast.LENGTH_LONG).show();
                            }
                            return false;
                        }
                        @Override
                        public boolean onQueryTextChange(String newText) {
                            adapter.getFilter().filter(newText);
                            //Toast.makeText(getApplicationContext(),newText,Toast.LENGTH_SHORT).show();
                            return false;
                       }
                    });
                    listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
                        @Override
                        public void onItemClick(AdapterView parent, View view, int position, long id) {
                            int itemPosition     = position;
            
                            Toast.makeText(MainActivity.this,adapter.getItem(position)+ "",Toast.LENGTH_SHORT).show();
                            String  itemValue    = (String) adapter.getItem(position);
                            Toast.makeText(getApplicationContext(),
                                    "Position :"+itemPosition+"  ListItem : " +itemValue , Toast.LENGTH_LONG)
                                    .show();
            
                        }
                    });
                }
            }
            
            ...

            ANSWER

            Answered 2021-Apr-13 at 15:03

            If you do a search for example using 'P', pineapple and papaya will be returned. Initially before search Pineapple is positions 4 and 5 and Papaya is 17th and 18th. But when you search only four results will be returned so Pineapple will be position 0, 1 and Papaya will be position 2 and 3. The position of items changes with the number of items in the list. So the behaviour you are seeing is the expected and correct one.

            Source https://stackoverflow.com/questions/67056798

            QUESTION

            formula in google sheet to count number of different objects?
            Asked 2021-Apr-04 at 08:51

            I have a Google spreadsheet with a column that looks like this:

            Each cell is dropdown list containing Fruits = [Apple,Orange,Pineapple,Papaya,Cherry,Strawberry]

            S.NO | Fruits
            1. ...

            ANSWER

            Answered 2021-Apr-04 at 08:27

            If I understood correctly and assuming the fruits are in the range A2:A10, you should be able to use

            Source https://stackoverflow.com/questions/66939122

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install papaya

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/gasman/papaya.git

          • CLI

            gh repo clone gasman/papaya

          • sshUrl

            git@github.com:gasman/papaya.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link