ramdisk | RAM disk driver for Windows
kandi X-RAY | ramdisk Summary
kandi X-RAY | ramdisk Summary
RAM disk driver for Windows. This is a modified version of the RAM disk sample driver from Microsoft, so that it is functional. It is possible to format the RAM disk as NTFS or FAT. Installation: devcon.exe install ramdisk.inf ramdisk.
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QUESTION
Background:
I have an old Seagate BlackArmor NAS 110 that I'm trying to install Debian on by following the instructions here: https://github.com/hn/seagate-blackarmor-nas.
I have a couple of USB to TTL serial adapters (one FTDI chipset and the other Prolific) that I've tried and have run into the same issue with both. I have made the connection to the serial port on the board of the NAS using a multimeter to make sure I've gotten the pinout correct.
Problem:
I'm not able to stop the autoboot process by pressing keys and any point during the boot process. The device also does not seem to respond to any keystrokes although they are echoed back.
What I've Tried So Far:
- Using USB to TTL serial adapters with two different chipsets
- Using the adapters on two different computers (MacBook Pro and a ThinkPad)
- Using different operating systems (MacOS, Windows 10, Ubuntu 20.04)
- Using different terminal programs (Screen, Minicom, Putty)
- Turned off hardware and software flow control
- Tested output of adapters by shorting RX and TX pins and seeing keystrokes echoed back
- Commands seem to be sent to device as when I type I see my commands echoed back (not sure if this is supposed to happen)
I've been at this for a few days and can't figure it out. I've also recorded my screen while experiencing the issue: https://streamable.com/xl43br. Can anyone see where I'm going wrong?
Terminal output while experiencing the problem:
...ANSWER
Answered 2021-Apr-22 at 15:51So it turns out there is a short somewhere between the RX pin and the +3.3V pin which is not allowing me to send anything to the board. Thank you to those who have commented.
QUESTION
I tried to use jcowgill's pre-compiled kernel and QCOW2 Disk Image, but qemu got stuck here after some output. Don't know what happened, qemu is just stuck here and I can't enter any commands.
Command:
...ANSWER
Answered 2021-Apr-01 at 19:04Your kernel command line says "console=tty0", which means "please send console to the first virtual terminal", ie to the graphics device. But there is no graphics device in the machine you're running (you say "-nographic" on your QEMU command line and the kernel says "Console: colour dummy device 80x25"). So what happens is that you see the initial bootup messages via the "uart8250" earlycon (ie the serial port), but as soon as the kernel gets to a point where it can honour your command line request, it enables tty0 (which goes nowhere) and disables uart8250 (so you see no further output).
You need to tell the kernel to send the console output to the serial port if that's where you'd like to see it appear, which for the malta board I think you can do by using "console=ttyS0" instead. Alternatively, you can drop '-nographic', make sure your kernel has the driver for the VGA card built in, and leave "console=tty0" and you'll see the console on the virtual console on the graphical window.
If you look at the README for the website you downloaded your image files from you'll see that it does indeed suggest using "console=ttyS0".
QUESTION
My boot chain is EFI --> U-Boot (as EFI app) --> loading itb file to the ramdisk --> starting kernel. When system ends startup process, and I've checked the /boot directory, I expected to see boot.cfg and image.itb files. I see bzImage file instead. Device architecture is x86_64.
My image content looks like:
...ANSWER
Answered 2021-Mar-26 at 19:18The problem was kernel had no drivers to SATA AHCI. The solution was to add a driver to configuration and rebuild kernel.
QUESTION
So I was looking around the Linux kernel (v 2.6.9) and I found that the boot sector code for i386 and x86_64 architectures have idential code. But isn't the golden rule of programming to keep your code DRY (do not write duplicate code)? So why the Linux maintainers didn't just re-use this file instead of copy - pasting it? I'm trying to learn good and clean code and this confused me. I mean if 2 architectures share the same boot code - just reuse it?
In the Linux source code these two files are exactly the same.
/arch/i386/boot/bootsect.S
and /arch/x86_64/boot/bootsect.S
ANSWER
Answered 2021-Mar-03 at 13:3132-bit x86 (i386) and 64-bit x86 (x86-64) do indeed have some commonalities, e.g. booting to exactly the same environment, and x86 processor in legacy 16-bit real mode.
The duplication between those two did not go unnoticed by the kernel developers either, see e.g. this LWN article (from 2007): i386 and x86_64: back together?. (2.6.9 appears to be from around 2004, so is by now over 16 years old.)
@IanAbbott mentions in a comment that the joining of those two into /arch/x86
eventually happened by 2.6.24 (which was released in January 2008, so about 13 years ago).
QUESTION
I'm creating tools using Python 3.8.1 for organizing my images. One of those tools is to detect and separate similar images. So, I need an algorithm to compare each images with all other images in that folder, more correctly, I need a BETTER algorithm to compare each images with all other images in that folder.
My approach for this problem is like this :
Let's take an example of 6 images. We name the image as 1, 2, 3, 4, 5, and 6. This is all the possible comparisons between each image to all images in that folder :
1 -> 1 2 -> 1 3 -> 1 4 -> 1 5 -> 1 6 -> 1
1 -> 2 2 -> 2 3 -> 2 4 -> 2 5 -> 2 6 -> 2
1 -> 3 2 -> 3 3 -> 3 4 -> 3 5 -> 3 6 -> 3
1 -> 4 2 -> 4 3 -> 4 4 -> 4 5 -> 4 6 -> 4
1 -> 5 2 -> 5 3 -> 5 4 -> 5 5 -> 5 6 -> 5
1 -> 6 2 -> 6 3 -> 6 4 -> 6 5 -> 6 6 -> 6
There are 6 * 6 = 36 comparisons.
Next, because we are comparing each images for finding similar image, it is logical to exclude comparisons between itself, so we need to remove comparison 1 -> 1, 2 -> 2, and so on. We also need to exclude comparing the images two times, for example, comparing 1 -> 2 and then comparing 2 -> 1 again. Logically speaking, what is the difference between comparing "me" and "you", and comparing "you" and "me". If "I" really am different than "you", then you don't need to compare it again.
Thus, the rest of the comparisons are :
1 -> 2
1 -> 3 2 -> 3
1 -> 4 2 -> 4 3 -> 4
1 -> 5 2 -> 5 3 -> 5 4 -> 5
1 -> 6 2 -> 6 3 -> 6 4 -> 6 5 -> 6
This reduces the total of images to compare to 5 + 4 + 3 + 2 + 1 = 15 comparisons, less than half the original.
I implement this using a method that takes a list of all the images in that folder, and then returning a list of pairs of two images according to the logic above. Here's the method :
ANSWER
Answered 2021-Jan-21 at 15:51Do not calculate hashes for each comparison. Open every file, calculate hash, store it. Then compare stored hashes for all combinations.
QUESTION
**Hello. Please help me with below. I want to access '3.21.228.186' of "public_ip": "3.21.228.186". What should be debug-var variable ? ##########Full output:
...ANSWER
Answered 2021-Jan-21 at 04:23instances
is a list, you can create a loop to print each public_ip
as below:
QUESTION
we are having issues saving excel sheets in PHP.
Minimalistic code:
...ANSWER
Answered 2020-Nov-10 at 16:53It can be an issue with user profile under which your PHP application is running. Please check article on server-side office automation of office products (it has common problems listed). To see if the problem is actually the account, I would try to change the account under Apache (PHP) is running to your account (or simply start Apache command line to see if it fixes the problem).
https://support.microsoft.com/en-us/help/257757/considerations-for-server-side-automation-of-office
https://theether.net/download/Microsoft/kb/288367.html
BTW, there are (paid) alternatives as well that can do calculations and run server-side.
QUESTION
I try to develop an android system, I have some problems with development.
I get used to ubuntu18 and tag of android 11 is android-11.0.0_r17,
I have built successfully with lunch 30 "aosp_x86-eng" and I have seen $OUT
files and checked
then I prepared test_aosp.sh file under ~/bin
the results are like that and no emulator window appears:
$ ./test_aosp.sh
ANSWER
Answered 2020-Nov-07 at 05:18if you successfully built, you can run emulator without additional arguments. Just typing emulator in console.
Or, please try to set ANDROID_SDK_ROOT as suggested.
QUESTION
Yesterday we lost contact with 10 identically configured servers, after some investigation the conclusion was that a reboot after security updates had failed.
We have so far not been able to get any of the servers back online, but were lucky enough to be able to reinstall the instances without data loss.
I will paste the console log below, can anyone help me determine the root cause and perhaps give me some advice on if there is a better way to configure the server to make recovery easier (like getting past the "Press Enter to continue." prompt, that it seems to hang in).
The full log is too big for SO, so I put it on pastebin and pasted a redacted version below. I have removed the escape sequences that colorize the output and removed some double new lines, but besides that it is complete.
...ANSWER
Answered 2020-Oct-30 at 11:21Ok, shortly after posting we figured it out. Seems like a mount point has changed (I expect due to a linux kernel update) and we have not used the nofail option in /etc/fstab as described in the aws knowledge center, this caused the server to hang at boot.
Going forward we will also ensure we use UUID mounting so we are independent on the device naming in /dev/.
QUESTION
I have following structure which consists of independent projects that are builded by the same Makefile (the differences are only in BUILD_TYPE
& LINKER_TYPE
variables):
ANSWER
Answered 2020-Oct-15 at 06:45I've figured it out. It is possible to use include
command of make
. My structure now look like this:
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