horizon | Horizon is a free EDA package

I am learning to program a game engine which is why I followed a tutorial, with that tutorial I have gotten this far and even though my code is identical to theirs (theirs did work in the videos) its not working the way it is meant to. The triangle stays black no matter what. There is not any errors.

Main Program Script:

I have x axis as some range ex: -100, -50, -12, -6, 0, 6, 12, 50, 100 and y axis is labels for ex: different chocolate brand name kitkat, 5star, milkybar, e.t.c or vice versa X and y Axis

I want scatter plots for each brands and conditional coloring( for each brand different conditions for coloring) ex: for kitkat brand, if value is in range less than or equal to -6 and +6 yellow color scatter plot, if greater that 6 green, if less than -6 it should be red. 5star - if value is in range less than or equal to -12 and +12 yellow color scatter, if greater that 12 green, if less than -12 it should be red.

I am new bee to plotly js. and i am finding x,y values in all examples but unable to find like brands in y axis and values in x axis.

i want each brand have respective scatters on that horizonal line only now am unable to show that.

here is my data,

What is the connection between discount factor gamma and horizon in RL.

What I have learned so far is that the horizon is the agent`s time to live. Intuitively, agents with finite horizon will choose actions differently than if it has to live forever. In the latter case, the agent will try to maximize all the expected rewards it may get far in the future.

But the idea of the discount factor is also the same. Are the values of gamma near zero makes the horizon finite?

In the last formula, I can not see the - sign. How to get around with this? many thanks in advance.

I have the following dataset with three variables. The first variable "Adversity.category" differentiates between 4 types of adversity. The second category "Adversity.subcategory" provides more fine-grained descriptions of the adversity whereas the "Adversity.event" refers to the specific event. I would like to the provide a summary table for each adversity category. Thus, I should have one summary table for "economic crisis", one for "natural disaster", one for "anthropogenic disaster", and one for "health" with two five columns in total: subcategory, specific event, n, total % and cumulative% starting with the highest count at the top.

So I have a data frame that I am working with below:

I need to integrate over a system of differential equations in GEKKO and want to use parameters to alter a gradient.

Conceptually this works, but the output is not what I expected. I added a code snippet for a sample problem below to illustrate the problem.

The solver will integrate over a specified time horizon, in this case t = [0, 1, 2, 3]

A parameter is defined that represents the gradient at each value in time called p = [0, 1, 2, 3].

My expectation is that the gradient at t=0 is 0, at t=1 is 1 and so forth. Instead GEKKO interprets it as the gradient at t=0 is 1, at t=1 is 2 etc.

Is there a reason why GEKKO does not use the gradient information at t=0?

As I have always been taught in logic, the "and" operator means both values must be true, for the entire statement to be true. If you have many statements chained with "and", then any one of them being false should make the whole claim false. In Ruby, however, I ran into this scenario:

Here is my SQL statement, which seemed to function perfectly well before we created a new database. This approach seems to work just fine on another, similarly structured, pair of tables.