dstep | A tool for converting C and Objective-C headers to D modules | Compiler library
kandi X-RAY | dstep Summary
kandi X-RAY | dstep Summary
DStep is a tool for automatically generating D bindings for C and Objective-C libraries. This is implemented by processing C or Objective-C header files and output D modules. DStep uses the Clang compiler as a library (libclang) to process the header files.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of dstep
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Trending Discussions on dstep
QUESTION
I am trying to plot the discrete transfer function H(z) = (0.5 - 0.50z)/(z-1.0) using python but I keep getting errors with the plot. I was trying to use the dstep function in scipy.signal. Continuous plots worked fine but I am getting an error with the line plt.plot(t,y,'k-',label=name)
. I used this for the continuous transfer function and worked fine. I think one of the arguments must be incorrect
ANSWER
Answered 2021-Apr-25 at 01:55y
is a tuple of a numpy array, so it needs to be indexed as y[0]
and flattened with ravel()
(it seems matplotlib can figure it out without flattening):
QUESTION
Recently, our lab bought a new server with 9 GPUs and I want to run my programming on this machine. However, I do not change my right code and I got an unexpected error like the following.
...ANSWER
Answered 2019-Jan-19 at 05:35The error is caused by the version mismatching between the RTX GPU cards and the CUDA driver.
QUESTION
I've found scipy.signal.dstep
, scipy.signal.dlsim
functions that help simulate behavior of a transfer function, for example:
signal.dlsim(signal.cont2discrete(([1], [1, 1]), 0.1), u=[1, 1], t=[0.0, 0.1])
allows to model 1/(s+1)
function in [0, 0.1]
time interval with control signal with value 1
.
But these functions do not allow to model just one step with initial values.
Are there any other functions that allow to model one step of a transfer function or how it's better to do it?
...ANSWER
Answered 2018-Dec-18 at 11:07First of all, i'm not sure, if you want to use discrete time or continuous time, because you're using s
operator for cont. time, the functions dstep
and dlsim
are used for discrete time representation. However, i used the continuous one in my example.
You can create a dlti
object in python with scipy.signal
's lti
function. The created filter object has a method step
where the first parameter is used for the initial time vector. lti.step
So you can plot your step response with this snippet.
QUESTION
I was doing some tests using the distortion model of OpenCV. Basically what I did is, implement the distortion equations and see if the cv::undistortPoints function gives me the inverse of these equations. I realized that cv::undistortPoints does not exactly give you the inverse of the distortion equations. When I saw this, I went to the implementation of cv::undistortPoints and realized that in the end condition of the iterative process of computing the inverse of the distortion model, OpenCV always does 5 iterations (if there are no distortion coefficients provided to the function it actually does 0 iterations) and does not use any error metric on the undistorted point to see if it is precisely undistorted. Haveing this in mind, I copied and modified the termination condition of the iteration process to take and error metrics into account. This gave me the exact inverse of the distortion model. The code showing this is attached at the end of this post. My question is:
Does this happen because OpenCV prefers performance (spending a bit less time) over accuracy (spending a bit more time) or is this just a "bug"? (it is obvious that with the termination condition that I propose the function will take more time to undistort each point)
Thank you very much!
...ANSWER
Answered 2017-May-17 at 12:15As suggested, you could get actual motivation from the OpenCV forums. Note however that historically OpenCV has been developed with real-time or near-real-time applications in mind (for example, the Darpa Grand Challenge), hence you'll find easily code that optimizes for speed over accuracy.
QUESTION
I am trying to figure out how SPIN chooses the order in which to execute and terminate processes in the following example. I realize that a main focus of SPIN is analyzing concurrent processes, but for my purposes I am just interested in simple linear execution. In the following example I just want step1() then step2() to be executed in that order.
...ANSWER
Answered 2017-Aug-01 at 13:00First, let me try give short answers to each of your questions:
1. I realise that proc 0 can't terminate until 1 and 2 have terminated, but why are the terminations of 2 and 1 being interleaved non-deterministically?
The processes always terminate in a deterministic fashion: 2
terminates before 1
, 1
before 0
and 0
is always the last one. However, there is nothing special about process termination: it is simply the final transition that is taken by a process. As a result, process interleaving is possible at any point in time in which there are more than one process with an (immediately) executable instruction.
2. Any why is SPIN randomly choosing between executing proc 1 and proc 2 when the init function is atomic and therefore should be executed in order?
Although it is true that init
executes both of his instructions atomically, the important fact to keep in mind is that step1
and step2
are independent processes and are executed after init
exits its atomic block: run
is not a function call, it just spawns a process inside the environment with absolutely no guarantee that such process is executed immediately. That might or might not happen depending on whether the spawned process has any executable instruction, whether the process that is currently executing is in an atomic sequence and on the outcome of the non-deterministic scheduler process selection.
3. And why can I get proc 2 to start and terminate before proc 1 (in Run 3) but not the other way around?
In Promela, processes can only die in reverse order of their creation, as indicated in the docs:
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