percolation | C code for 2D/3D lattice percolation

 by   johnkerl C Version: Current License: BSD-2-Clause

kandi X-RAY | percolation Summary

kandi X-RAY | percolation Summary

percolation is a C library. percolation has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

John Kerl Jan. 20, 2010. PURPOSE / RESEARCH QUESTIONS. This code serves two purposes.
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            kandi-support Support

              percolation has a low active ecosystem.
              It has 7 star(s) with 3 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              percolation has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of percolation is current.

            kandi-Quality Quality

              percolation has 0 bugs and 0 code smells.

            kandi-Security Security

              percolation has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              percolation code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              percolation is licensed under the BSD-2-Clause License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              percolation releases are not available. You will need to build from source code and install.

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            percolation Key Features

            No Key Features are available at this moment for percolation.

            percolation Examples and Code Snippets

            Draws a polycolation matrix .
            javadot img1Lines of Code : 33dot img1License : Permissive (MIT License)
            copy iconCopy
            public static void draw(Percolation perc, int n) {
                    StdDraw.clear();
                    StdDraw.setPenColor(StdDraw.BLACK);
                    StdDraw.setXscale(-0.05*n, 1.05*n);
                    StdDraw.setYscale(-0.05*n, 1.05*n);   // leave a border to write text
                      

            Community Discussions

            QUESTION

            Create grid then color it following given scenario in tkinter
            Asked 2021-Dec-30 at 10:42

            I want to create a grid and color some cells sequentially so that the user can see cells turning on.

            For the moment I have:

            ...

            ANSWER

            Answered 2021-Dec-29 at 12:50

            The problem is you call color_cell in center.after() instead of passing a reference to the function. You must do: center.after(5000, color_cell, cells, 3, 4):

            Source https://stackoverflow.com/questions/70519225

            QUESTION

            Python: Identify breaking points in a data frame column
            Asked 2021-Jul-08 at 13:41

            I am interested in identifying when different trips take place in a dataset. There are two lock states, where lock means the vehicle is stationary and unlocked means that the vehicle is being used.

            As the same vehicle could be used by the same user multiple times, I first isolate the vehicle and a unique user through IDs and from a chronologically sorted time date column I can see when the vehicle was used. In order to identify different trips taken in the same vehicle by the same user I thought of identifying through my lock_state variable.

            I've been trying to find how this could be done and percolation is something I came across but it seems too complex to understand and implement. I was wondering if there is an easier way of achieving this.

            My end goal is to identify the number of trips (should be 2 in this example), add them to a new df alongside the user id and start/end datetimes (let's pretend all of this is the random column) and give them unique IDs. So the final output should be something like this (random made-up example):

            ...

            ANSWER

            Answered 2021-Jul-07 at 21:38

            shift your state column by 1 row; compare against the original, and filter on state "unlocked". Those identifies runs of consecutive "unlocked" states. The shift-compare portion is

            Source https://stackoverflow.com/questions/68293146

            QUESTION

            Python Matplotlib Graph Showing Incorrect Range in X axis
            Asked 2021-May-07 at 04:45

            Since the code is a lot of lines, I shall first show what the issue is:

            I defined a simple loop and am getting the appropriate results.

            Here when I attempt to plot it using matplotlib, the range shown on the x-axis is different from the range I inputted. I want 0 to 100 with a step size of 5 but I am getting 0 to 17.5 with a step size of 2.5.

            Is there any issue with just the way I have coded this? If not, here is the rest of the code, thank you!:

            ...

            ANSWER

            Answered 2021-May-07 at 04:45

            When plot() is only given one array:

            Source https://stackoverflow.com/questions/67428825

            QUESTION

            Trying to create and alter grid, but assigning values to specific index in nested list is unexpectedly duplicated to other nested lists
            Asked 2021-Apr-16 at 07:23

            (Python 3.9) I'm trying to solve a percolation problem/assignment, and just to start, I'm creating an n-by-n grid. While the grid looks correct on creation, when I try to alter a specific value inside the grid (in a nested list), it's assigning that value to every sublist, rather than only the list I'm referencing with it's index.

            Here's the class and relevant bits:

            ...

            ANSWER

            Answered 2021-Apr-16 at 07:23

            In python when you create a list and assign it to multiple places, it is the same list, not a new list with the same values. So when you create the list values and append it to grid, each nested list is actually the same list.

            One way you can avoid this problem is by copying the list using an index of the entire list [:] like: grid.append(values[:])

            Source https://stackoverflow.com/questions/67120683

            QUESTION

            How to show top to bottom leaks in my path
            Asked 2021-Feb-02 at 16:19

            I used the percolation class from the algs4.jar library, where you can simulate a whole labyrinth and see where the leaks are. I want to show the leaks that are from top to bottom, but now I get to see all of the leaks.

            Does anyone know how I can see only the leaks that are percolations?

            I thought maybe using dfs from the flow method in de Percolation.java class, and say something like only show when index i in rows is maxlength and marked but I don't really know how to say that, because I am not sure if this statement will show the entire leak of just the max length leak.

            code I run AssignmentTwo.java:

            ...

            ANSWER

            Answered 2021-Feb-02 at 16:19

            It seems that disabling double buffering will get you the result you want:

            Source https://stackoverflow.com/questions/65994196

            QUESTION

            Algorithm to find the longest cluster. (Python ideally, possibly Matlab)
            Asked 2020-Dec-06 at 18:40


            I am experimenting with something called "bond percolation theory" Effectively you have some n by n lattice grid and then (randomly) with some probability p you keep or delete an edge. Here is an example:

            Here is my code:


            I have 2 questions for this fantastic community:

            1. How do I get the grid I inserted to appear on all the integer values, so far it is only displaying on multiples of 5. (the thin grey lines)
            2. I wish to have an algorithm that provides something called the "longest cluster" A cluster is a connected graph of edges (thick black lines) for example in the top left corner we have a cluster of 6 (upside down f shape) , a cluster of 2 (the little arrow head), a cluster of 4 (the square) and a cluster of 3 (the backwards upside L) The longest cluster is simply the longest one.

            Any help is very appreciated. If I have posed this question badly please let me know or if any clarification is needed.

            ...

            ANSWER

            Answered 2020-Dec-06 at 13:53

            Your first problem can simply be solved by enabling the minor ticks:

            Source https://stackoverflow.com/questions/65168697

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install percolation

            You can download it from GitHub.

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