Wind | The Flow-based Programming Language | Code Inspection library
kandi X-RAY | Wind Summary
kandi X-RAY | Wind Summary
The Flow-based Programming Language.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Wind
Wind Key Features
Wind Examples and Code Snippets
wind> push 5 -> out
[ 5 ]
wind> clr -> out
[ ]
wind> push None True False 0 1 2 3
wind> out
[ None True False 0 1 2 3 ]
wind> push 3 3 3 3 -> out
[ 3 3 3 3 ]
wind> clr -> out
[ ]
wind> push 6 7 8 9 10 12 14
wind>
Wind - Version (0.0.1)
The Wind Programming Language REPL
To exit, simply enter 'exit'.
wind> push 7 7 7 8
wind> out
[ 7 7 7 8 ]
wind> map + 5 | / 3
wind> out
[ 4 4 4 4.333 ]
wind> filter > 4 -> out
[ 4.333 ]
wind> exit
$ Win
wind> push None None None -> out
[ None None None ]
wind> map ! -> out
[ False False False ]
wind> push 5 True False -> out
[ 5 True False ]
wind> filter > 0 -> out
[ 5 ]
wind> push 5 -> map + True False | * True -&
Community Discussions
Trending Discussions on Wind
QUESTION
I am working with dplyr and the data package 'storms'.
I need a table in which I have each measured storm in a column. Then I want to give each row an ID.
So far I have
...ANSWER
Answered 2022-Apr-15 at 09:37For you first problem:
QUESTION
I know that --quit does not change your HEAD pointer, so any commits made successfully during a rebase or cherrypick are still there.
But what I'm unsure of is, in case a conflict happened during a cherry-pick or a rebase, whether using --quit clear the changes brought about by the conflict, such as the successfully added changes, the conflict markers in the working directory, the multiple versions in the index etc ?
The git rebase documentation has the following:
--quit Abort the rebase operation but HEAD is not reset back to the original branch. The index and working tree are also left unchanged as a result.
the cherry-pick documentation is less clear about the effects on the index and work tree:
--quit Forget about the current operation in progress. Can be used to clear the sequencer state after a failed cherry-pick or revert.
But this otherwise excellent answer in SO has the following:
But if you choose --quit, Git terminates the rebase without moving HEAD, so that you wind up with:
but a clean index and work-tree. So you don't have to be clever enough to attach a branch name before the --quit.
So which is it ? I know that in a merge --quit will not clear the mess that a merge conflict makes in your index and work tree, it just abandons the merge head state. is it different in case of a cherry pick or a rebase ?
...ANSWER
Answered 2022-Apr-14 at 23:00It really depends on the state you had at the time you issue the --quit
: Git just stops here. I'll update the other answer to indicate that you can then git reset --hard
to make it "clean" if you want, or leave it "dirty" if you want.
QUESTION
Working on a tool to make runway recommendations for flight simulation enthusiasts based off of the real world winds at a given airport. The ultimate goal is to compare, and return a list of available runways in a list, with the smallest wind variance displaying at the top of the list.
I would say that I probably have 95% of what I need, but where it gets slippery is for wind headings that approach 0 degrees (360 on a compass rose).
If runway heading is 029 and wind heading is 360, it is only a difference of 29 degrees, but the formula that I have written displays a difference of 331 degrees.
I have tried experimenting with abs() as part of the comparison but have gotten nowhere. I will link my current results here: https://extendsclass.com/php-bin/7eba5c8
Attempted switching comparisons for wind heading and runway heading (subtracting one from the other, and then the other way around) with the same result.
I am sure that the key lies in some little three line nonsense that I just cannot get the knack of (disadvantage of being a self-taught cowboy coder, I guess).
I saw a post about how to do it in C# from about 11 years ago but I never messed around with that particular deep, dark corner of the programming world.
The code is included below:
...ANSWER
Answered 2022-Mar-28 at 18:40When you subtract two angles in a circle, you can either go the "short way" or the "long way" - it's a circle... So you have to calculate both ways and then find out, which one is shorter - and the direction too, because you have a fixed start angle and a fixed target angle:
QUESTION
I am trying to find a simple and efficient way to (de)serialize enums in Scala 3 using circe
.
Consider the following example:
...ANSWER
Answered 2022-Jan-23 at 21:34In Scala 3 you can use Mirrors to do the derivation directly:
QUESTION
I would like to use stat_bin_2d
and stat_density_2d
on data with wind direction and anomaly. I need to group the wind direction into 8 groups. As you can see below, A is the default output from using stat_bin_2d
, while B is the addition of stat_density_2d
. C is after wind direction has been grouped into 8 factors, and plotted wind direction as factor. D is when the wind direction as factor was turned back into numeric. As you can see, there are gaps between the tiles. F is an attempt to plot together C (wind direction as factor) with continuous stat_density_2d
.
Is there a way to match the scale of both discrete (it's based on continuous) with continuous?
Is there a way to widen the tiles in D to match C?
Is there a way to manually enter the bin information into stat_bin_2d
so that it would produce C automatically, but the output is still continuous?
Below is my attempt to do so.
...ANSWER
Answered 2022-Mar-26 at 12:13You can work with your continuous data by setting the binwidth of both axes:
QUESTION
I have two tables as follows :
...ANSWER
Answered 2022-Feb-26 at 05:47Create Split
Function like this
QUESTION
I'm relatively new to Javascript and I tried to code a text adventure game. What I am trying to do is when numLives == 1
, I want the game to display "BE CAREFUL" just once when user chooses the wrong path, and if the user chooses the right path after that, even with numLives == 1
, the message "BE CAREFUL" will not display anymore.
ANSWER
Answered 2022-Feb-23 at 03:44You just need some basic conditional logic in there:
QUESTION
I am trying to build a weather app with open weather API. There is a problem with the first call I have to get the value latitude and longitude from the first API to make a second API call. I have tried async / await but can't get the correct structure this code to work I also tried useEffect hook but failed again.
My code is below. What am I missing?
...ANSWER
Answered 2022-Feb-18 at 17:09What you are missing is that when you are calling searchFollowing()
, React did not yet re-render, therefore location
wouldn't be get updated. A way to do it is this :
QUESTION
i am having this handleCheckClick funtion witch gets Data
i want to store the data into a state every time the handleCheckClick funtion is called so after many times handleCheckClick is called the state should look like the object array below
ANSWER
Answered 2022-Feb-18 at 09:07You have to take your data and call setState
using the existing data merged with the new Data
object. The merging can be done using ...
(spread) operator. Here's the code with the relevant parts:
QUESTION
I am using the lme4
package and running a linear mixed model but I am confused but the output and expect that I am encountering an error even though I do not get an error message.
The basic issue is when I fit a model like lmer(Values ~ stimuli + timeperiod + scale(poly(distance.code,3,raw=FALSE))*habitat + wind.speed + (1|location.code), data=df, REML=FALSE)
and then look at the results using something like summary
I see all the model fixed (and random) effects as I would expect however the habitat effect is always displayed as habitatForest. Like this:
ANSWER
Answered 2022-Feb-10 at 19:43note: although your question is about the lmer()
function, this answer also applies to lm()
and other R functions that fit linear models.
The way that coefficient estimates from linear models in R are presented can be confusing. To understand what's going on, you need to understand how R fits linear models when the predictor is a factor variable.
Coefficients on factor variables in R linear modelsBefore we look at factor variables, let's look at the more straightforward situation where the predictor is continuous. In your example dataset, one of the predictors is wind speed (continuous variable). The estimated coefficient is about -0.35. It's easy to interpret this: averaged across the other predictors, for every increase of 1 km/h in wind speed, your response value is predicted to decrease by 0.35.
But what about if the predictor is a factor? A categorical variable cannot increase or decrease by 1. Instead it can take several discrete values. So what the lmer()
or lm()
function does by default is automatically code your factor variable as a set of so-called "dummy variables." Dummy variables are binary (they can take values of 0 or 1). If the factor variable has n
levels, you need n-1
dummy variables to encode it. The reference level or control group acts like an intercept.
In the case of your habitat variable, there are only 2 levels so you have only 1 dummy variable which will be 0 if habitat is not Forest
and 1 if it is Forest
. Now we can interpret the coefficient estimate of -68.8: the average value of your response is expected to be 68.8 less in forest habitat relative to the reference level of grassland habitat. You don't need a second dummy variable for grassland because you only need to estimate the one coefficient to compare the two habitats.
If you had a third habitat, let's say wetland, there would be a second dummy variable that would be 0 if not wetland and 1 if wetland. The coefficient estimate there would be the expected difference between the value of the response variable in wetland habitat compared to grassland habitat. Grassland will be the reference level for all the coefficients.
Default setting of reference levelNow to directly address your question of why habitatForest
is the coefficient name.
Because by default no reference level or control group is specified, the first one in the factor level ordering becomes the reference level to which all other levels are compared. Then the coefficients are named by appending the variable's name to the name of the level being compared to the reference level. Your factor is ordered with grassland first and forest second. So the coefficient is the effect of the habitat being forest habitat, compared to the reference level, which is grassland in this case. If you switched the habitat factor level ordering, Forest
would be the reference level and you would get habitatGrassland
as the coefficient instead. (Note that default factor level ordering is alphabetical, so without specifically ordering the factor levels as you seem to have done, Forest
would be the reference level by default).
Incidentally, the two links you give in your question (guides to mixed models from Phillip Alday and Tufts) do in fact have the same kind of output as you are getting. For example in Alday's tutorial, the factor recipe
has 3 levels: A, B, and C. There are two coefficients in the fixed effects summary, recipeB
and recipeC
, just as you would expect from dummy coding using A as reference level. You may be confusing the fixed effects summary with the ANOVA table presented elsewhere in his post. The ANOVA table does only have a single line for recipe
which gives you the ratio of variance due to recipe
(across all its levels) and the total variance. So that would only be one ratio regardless of how many levels recipe
has.
This is not the place for a full discussion of contrast coding in linear models in R. The dummy coding (which you may also see called one-hot encoding) I described here is just one way to do it. These resources may be helpful:
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