Wind | The Flow-based Programming Language | Code Inspection library

 by   jweinst1 C Version: v0.0.1 License: MIT

kandi X-RAY | Wind Summary

kandi X-RAY | Wind Summary

Wind is a C library typically used in Code Quality, Code Inspection applications. Wind has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

The Flow-based Programming Language.
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            kandi-support Support

              Wind has a low active ecosystem.
              It has 14 star(s) with 2 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 15 have been closed. On average issues are closed in 115 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Wind is v0.0.1

            kandi-Quality Quality

              Wind has 0 bugs and 0 code smells.

            kandi-Security Security

              Wind has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Wind code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Wind is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Wind releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Wind
            Get all kandi verified functions for this library.

            Wind Key Features

            No Key Features are available at this moment for Wind.

            Wind Examples and Code Snippets

            Table of Contents,Guide,Commands
            Cdot img1Lines of Code : 58dot img1License : Permissive (MIT)
            copy iconCopy
            wind> push 5 -> out
            [ 5 ]
            wind> clr -> out
            [ ]
            
            wind> push None True False 0 1 2 3
            wind> out
            [ None True False 0 1 2 3 ]
            
            wind> push 3 3 3 3 -> out
            [ 3 3 3 3 ]
            wind> clr -> out
            [ ]
            
            wind> push 6 7 8 9 10 12 14
            wind>  
            Table of Contents,Usage
            Cdot img2Lines of Code : 33dot img2License : Permissive (MIT)
            copy iconCopy
            Wind - Version (0.0.1)
            The Wind Programming Language REPL
            To exit, simply enter 'exit'.
            wind> push 7 7 7 8
            wind> out
            [ 7 7 7 8 ]
            wind> map + 5 | / 3
            wind> out
            [ 4 4 4 4.333 ]
            wind> filter > 4 -> out
            [ 4.333 ]
            wind> exit
            
            $ Win  
            Table of Contents,Guide,Types
            Cdot img3Lines of Code : 18dot img3License : Permissive (MIT)
            copy iconCopy
            wind> push None None None -> out
            [ None None None ]
            wind> map ! -> out
            [ False False False ]
            
            wind> push 5 True False -> out
            [ 5 True False ]
            wind> filter > 0 -> out
            [ 5 ]
            
            wind> push 5 -> map + True False | * True -&  

            Community Discussions

            QUESTION

            R - dplyr- Reducing data package 'storms'
            Asked 2022-Apr-15 at 11:08

            I am working with dplyr and the data package 'storms'.

            I need a table in which I have each measured storm in a column. Then I want to give each row an ID.

            So far I have

            ...

            ANSWER

            Answered 2022-Apr-15 at 09:37

            For you first problem:

            Source https://stackoverflow.com/questions/71882104

            QUESTION

            does --quit leave you with a clean index and worktree after a rebase or a cherry-pick operation?
            Asked 2022-Apr-14 at 23:00

            I know that --quit does not change your HEAD pointer, so any commits made successfully during a rebase or cherrypick are still there.

            But what I'm unsure of is, in case a conflict happened during a cherry-pick or a rebase, whether using --quit clear the changes brought about by the conflict, such as the successfully added changes, the conflict markers in the working directory, the multiple versions in the index etc ?

            The git rebase documentation has the following:

            --quit Abort the rebase operation but HEAD is not reset back to the original branch. The index and working tree are also left unchanged as a result.

            the cherry-pick documentation is less clear about the effects on the index and work tree:

            --quit Forget about the current operation in progress. Can be used to clear the sequencer state after a failed cherry-pick or revert.

            But this otherwise excellent answer in SO has the following:

            But if you choose --quit, Git terminates the rebase without moving HEAD, so that you wind up with:

            but a clean index and work-tree. So you don't have to be clever enough to attach a branch name before the --quit.

            So which is it ? I know that in a merge --quit will not clear the mess that a merge conflict makes in your index and work tree, it just abandons the merge head state. is it different in case of a cherry pick or a rebase ?

            ...

            ANSWER

            Answered 2022-Apr-14 at 23:00

            It really depends on the state you had at the time you issue the --quit: Git just stops here. I'll update the other answer to indicate that you can then git reset --hard to make it "clean" if you want, or leave it "dirty" if you want.

            Source https://stackoverflow.com/questions/71876806

            QUESTION

            PHP - How to compare two headings on a compass rose?
            Asked 2022-Mar-28 at 22:04

            Working on a tool to make runway recommendations for flight simulation enthusiasts based off of the real world winds at a given airport. The ultimate goal is to compare, and return a list of available runways in a list, with the smallest wind variance displaying at the top of the list.

            I would say that I probably have 95% of what I need, but where it gets slippery is for wind headings that approach 0 degrees (360 on a compass rose).

            If runway heading is 029 and wind heading is 360, it is only a difference of 29 degrees, but the formula that I have written displays a difference of 331 degrees.

            I have tried experimenting with abs() as part of the comparison but have gotten nowhere. I will link my current results here: https://extendsclass.com/php-bin/7eba5c8

            Attempted switching comparisons for wind heading and runway heading (subtracting one from the other, and then the other way around) with the same result.

            I am sure that the key lies in some little three line nonsense that I just cannot get the knack of (disadvantage of being a self-taught cowboy coder, I guess).

            I saw a post about how to do it in C# from about 11 years ago but I never messed around with that particular deep, dark corner of the programming world.

            The code is included below:

            ...

            ANSWER

            Answered 2022-Mar-28 at 18:40

            When you subtract two angles in a circle, you can either go the "short way" or the "long way" - it's a circle... So you have to calculate both ways and then find out, which one is shorter - and the direction too, because you have a fixed start angle and a fixed target angle:

            Source https://stackoverflow.com/questions/71651506

            QUESTION

            (De)serialize enum as string in Scala 3
            Asked 2022-Mar-27 at 00:30

            I am trying to find a simple and efficient way to (de)serialize enums in Scala 3 using circe.

            Consider the following example:

            ...

            ANSWER

            Answered 2022-Jan-23 at 21:34

            In Scala 3 you can use Mirrors to do the derivation directly:

            Source https://stackoverflow.com/questions/70802124

            QUESTION

            Trying to plot together discrete stat_bin_2d with continuous stat_density_2d
            Asked 2022-Mar-26 at 13:10

            I would like to use stat_bin_2d and stat_density_2d on data with wind direction and anomaly. I need to group the wind direction into 8 groups. As you can see below, A is the default output from using stat_bin_2d, while B is the addition of stat_density_2d. C is after wind direction has been grouped into 8 factors, and plotted wind direction as factor. D is when the wind direction as factor was turned back into numeric. As you can see, there are gaps between the tiles. F is an attempt to plot together C (wind direction as factor) with continuous stat_density_2d.

            Is there a way to match the scale of both discrete (it's based on continuous) with continuous?

            Is there a way to widen the tiles in D to match C?

            Is there a way to manually enter the bin information into stat_bin_2d so that it would produce C automatically, but the output is still continuous?

            Below is my attempt to do so.

            ...

            ANSWER

            Answered 2022-Mar-26 at 12:13

            You can work with your continuous data by setting the binwidth of both axes:

            Source https://stackoverflow.com/questions/71627457

            QUESTION

            Count the occurrences of a group of words in a text column in SQL
            Asked 2022-Feb-28 at 19:22

            I have two tables as follows :

            ...

            ANSWER

            Answered 2022-Feb-26 at 05:47

            Create Split Function like this

            Source https://stackoverflow.com/questions/71274186

            QUESTION

            Is there a way that I can console.log just once?
            Asked 2022-Feb-23 at 03:44

            I'm relatively new to Javascript and I tried to code a text adventure game. What I am trying to do is when numLives == 1, I want the game to display "BE CAREFUL" just once when user chooses the wrong path, and if the user chooses the right path after that, even with numLives == 1, the message "BE CAREFUL" will not display anymore.

            ...

            ANSWER

            Answered 2022-Feb-23 at 03:44

            You just need some basic conditional logic in there:

            Source https://stackoverflow.com/questions/71231097

            QUESTION

            Make a second API call based on first api call response in React with hooks
            Asked 2022-Feb-18 at 17:09

            I am trying to build a weather app with open weather API. There is a problem with the first call I have to get the value latitude and longitude from the first API to make a second API call. I have tried async / await but can't get the correct structure this code to work I also tried useEffect hook but failed again.

            My code is below. What am I missing?

            ...

            ANSWER

            Answered 2022-Feb-18 at 17:09

            What you are missing is that when you are calling searchFollowing(), React did not yet re-render, therefore location wouldn't be get updated. A way to do it is this :

            Source https://stackoverflow.com/questions/70960769

            QUESTION

            add the data every time the funtion is called into a array object of State
            Asked 2022-Feb-18 at 09:24

            i am having this handleCheckClick funtion witch gets Data i want to store the data into a state every time the handleCheckClick funtion is called so after many times handleCheckClick is called the state should look like the object array below

            ...

            ANSWER

            Answered 2022-Feb-18 at 09:07

            You have to take your data and call setState using the existing data merged with the new Data object. The merging can be done using ... (spread) operator. Here's the code with the relevant parts:

            Source https://stackoverflow.com/questions/71169881

            QUESTION

            Why does the output of of a linear mixed model using lme4 show one level of a factor but not another?
            Asked 2022-Feb-10 at 19:43

            I am using the lme4 package and running a linear mixed model but I am confused but the output and expect that I am encountering an error even though I do not get an error message. The basic issue is when I fit a model like lmer(Values ~ stimuli + timeperiod + scale(poly(distance.code,3,raw=FALSE))*habitat + wind.speed + (1|location.code), data=df, REML=FALSE) and then look at the results using something like summary I see all the model fixed (and random) effects as I would expect however the habitat effect is always displayed as habitatForest. Like this:

            ...

            ANSWER

            Answered 2022-Feb-10 at 19:43

            note: although your question is about the lmer() function, this answer also applies to lm() and other R functions that fit linear models.

            The way that coefficient estimates from linear models in R are presented can be confusing. To understand what's going on, you need to understand how R fits linear models when the predictor is a factor variable.

            Coefficients on factor variables in R linear models

            Before we look at factor variables, let's look at the more straightforward situation where the predictor is continuous. In your example dataset, one of the predictors is wind speed (continuous variable). The estimated coefficient is about -0.35. It's easy to interpret this: averaged across the other predictors, for every increase of 1 km/h in wind speed, your response value is predicted to decrease by 0.35.

            But what about if the predictor is a factor? A categorical variable cannot increase or decrease by 1. Instead it can take several discrete values. So what the lmer() or lm() function does by default is automatically code your factor variable as a set of so-called "dummy variables." Dummy variables are binary (they can take values of 0 or 1). If the factor variable has n levels, you need n-1 dummy variables to encode it. The reference level or control group acts like an intercept.

            In the case of your habitat variable, there are only 2 levels so you have only 1 dummy variable which will be 0 if habitat is not Forest and 1 if it is Forest. Now we can interpret the coefficient estimate of -68.8: the average value of your response is expected to be 68.8 less in forest habitat relative to the reference level of grassland habitat. You don't need a second dummy variable for grassland because you only need to estimate the one coefficient to compare the two habitats.

            If you had a third habitat, let's say wetland, there would be a second dummy variable that would be 0 if not wetland and 1 if wetland. The coefficient estimate there would be the expected difference between the value of the response variable in wetland habitat compared to grassland habitat. Grassland will be the reference level for all the coefficients.

            Default setting of reference level

            Now to directly address your question of why habitatForest is the coefficient name.

            Because by default no reference level or control group is specified, the first one in the factor level ordering becomes the reference level to which all other levels are compared. Then the coefficients are named by appending the variable's name to the name of the level being compared to the reference level. Your factor is ordered with grassland first and forest second. So the coefficient is the effect of the habitat being forest habitat, compared to the reference level, which is grassland in this case. If you switched the habitat factor level ordering, Forest would be the reference level and you would get habitatGrassland as the coefficient instead. (Note that default factor level ordering is alphabetical, so without specifically ordering the factor levels as you seem to have done, Forest would be the reference level by default).

            Incidentally, the two links you give in your question (guides to mixed models from Phillip Alday and Tufts) do in fact have the same kind of output as you are getting. For example in Alday's tutorial, the factor recipe has 3 levels: A, B, and C. There are two coefficients in the fixed effects summary, recipeB and recipeC, just as you would expect from dummy coding using A as reference level. You may be confusing the fixed effects summary with the ANOVA table presented elsewhere in his post. The ANOVA table does only have a single line for recipe which gives you the ratio of variance due to recipe (across all its levels) and the total variance. So that would only be one ratio regardless of how many levels recipe has.

            Further reading

            This is not the place for a full discussion of contrast coding in linear models in R. The dummy coding (which you may also see called one-hot encoding) I described here is just one way to do it. These resources may be helpful:

            Source https://stackoverflow.com/questions/71055840

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Wind

            To build Wind from source, run the following command in your terminal. To clean excess build files, run.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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