mycode | Matlab implementation of our works on online hashing
kandi X-RAY | mycode Summary
kandi X-RAY | mycode Summary
ONLINE_HASHING_UTILS directory contains all baseline methods and online hashing tools. 2018ACMMM_HCOH directory contains the source codes of our paper, i.e., Supervised Online Hashing via Hadamard Codebook Learning , ACM MM, 2018. 2019ACMMM_BSODH directory contains the source codes of our paper, i.e., Towards Optimal Discrete Online Hashing with Balanced Similarity , AAAI, 2019. 2020IJCV_HMOH directory contains the source codes of our paper, i.e., Hadamard Matrix Guided Online Hashing , IJCV, 2020. Feel free to contact me at lmbxmu@stu.xmu.edu.cn.
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QUESTION
Tried to list all the ledgers from tally through odbc. got nothing. Mycode is as follows, no errors while executing. but not displaying the list of ledgers into the datagridview1
...ANSWER
Answered 2021-May-02 at 07:39I am curious what database you are using that requires ODBC and does not have a specific provider.
I have divided your code into user interface code and database code. This makes it easier to maintain.
Database objects like Connection, Command, and DataReader must be closed and disposed. Using...End Using
blocks take care of this even it there is an error.
You can pass the CommandText
and Connection
directly to the constructor of the Command
.
Don't hold the connection open while you update the user interface. Comparatively, this is a long process and too long to keep a connection open
This doesn't make any sense. You are resetting the DataSource
to the same value numerous times. But, it won't work anyway because a DataReader is not a valid DataSource
. See https://docs.microsoft.com/en-us/dotnet/api/system.windows.forms.datagridview.datasource?view=netframework-4.8&f1url=%3FappId%3DDev16IDEF1%26l%3DEN-US%26k%3Dk(System.Windows.Forms.DataGridView.DataSource)%3Bk(TargetFrameworkMoniker-.NETFramework%2CVersion%253Dv4.8)%3Bk(DevLang-VB)%26rd%3Dtrue#remarks
QUESTION
I want to use click to specify an option, but I want to access the value in a differently named variable.
So here is what I have
...ANSWER
Answered 2021-Jun-09 at 14:54I found a workaround by using multiple option names & putting the one we want in the variable name as the first one.
QUESTION
I've installed Anaconda 1.9.12 and everything works fine for designing python scripts and executing them. Now that I have my code ready, I want to allow for an external program to call python myCode.py myInputFile.dat
but this fails to activate the environment and my import commands fail. I can activate the environment manually by using the Activate.bat
file the Anaconda provides but when I put this into a batch file, the command prompt exists after I called Activate.bat
and never gets to python.exe
Here is my batch file
...ANSWER
Answered 2021-Jun-03 at 02:20Not sure where the conda.exe
is on Windows, but one can use conda.exe run
to execute commands within environments without having to activate them in a shell session. For example, you should be able to do something like
QUESTION
I was asked to Multiply two 8 bit and show the output in 6000 memory location but am unable to do so i can get output with RET without memory location in AX only.
...ANSWER
Answered 2021-May-28 at 18:11mul al
multiplies AL by AL and puts the result in AX. Since you set AL to 10h, the result is AX=100h and then you store AL which is zero. If you want to multiply AL by AH and store the result you should do this:
QUESTION
I've been using the HERE Reverse Geocoding endpoint (example URL below) to convert latlons into Location data (works a treat, thanks!).
I was wondering if there is a way to send a request for the same/a similar response as the above URL but passing LinkId/MapReferenceId (I believe the two are interchangeable) instead of pos=,?
...ANSWER
Answered 2021-May-28 at 08:29This isn't exactly an answer, but the question no longer needs to remain open - I found a workaround my end that removes the need for this endpoint.
QUESTION
The topic link: https://codeforces.com/problemset/problem/600/D
For the question, I'm wrong answer on test28, which could look like this:
correct answer:119256.95877838134765625000
my answer: 120502.639190673828125
I guess it is caused by calculation accuracy, but I don't have evidence. Maybe algorithm itself is faulty, please point it out.
Algorithm ideas:
For any given two circles, in order to simplify the calculation, we can translate the origin of the coordinates to the center of one of the circles, and then rotate the other circle to the x-axis by rotating. For calculating the intersection area of the circles, before and after are equivalent, and finally a purple circle and a red circle are formed. In fact, the final intersection area is equal to the sum of the areas of the two sectors minus the area of the diamond in the middle(the figure below, Horizontal axis x, vertical axis y). However, before that, we must first calculate the intersection point of the two circles.
The coordinates of the center of the first circle at the beginning: .
The coordinates of the center of the second circle at the beginning: .
The coordinates of the center of the first circle after a series of transformations: .
The coordinates of the center of the second circle after a series of transformations: ,
.
The equations of two circles are combined:
are the radius of the first and second circles respectively,so:
we can use the sector area formula : ,
, .
In this place, there will be problems with the positive and negative values of the radian(the two figures below), but it can be proved that they can be absorbed in the final result.
The final result is the sum of the areas of the two arcs minus the area of the middle diamond.
mycode:
...ANSWER
Answered 2021-May-27 at 06:10Don't use too many intermediate floating variables to get to the final answer. Small inaccuracies when add up lead to huge inaccuracy which you can clearly see in the expected and real output in your question. What you can do is to minimize these intermediate floating variables. For example
QUESTION
df
Id Section Comment
------------------------------------------------------------
1 Product A this is the general comment for product A
2 Product A this is the general comment for product A
3 Product A this is the general comment for product A
4 Product B this is the general comment for product B
5 Product B this is the general comment for product B
8 Product C this is the general comment for product C
9 Product C this is the general comment for product C
10 Product C this is the general comment for product C
...ANSWER
Answered 2021-May-26 at 16:56section_df<-section_df[complete.cases(section_df), ]
for(i in 1:nrow(df)){
if(i %in% section_df$index){
print(df$Section[i])
}
else{
print(df$Comment[i])
}
}
QUESTION
the property 'settings' can't be unconditionally accessed because the receiver can be 'null',what to do mycode :`import 'package:flutter/material.dart';
...ANSWER
Answered 2021-May-23 at 12:27Just use
QUESTION
This is the link to this algorithm topic: https://codeforces.com/problemset/problem/615/D
my code time limit exceeded on test40, I thought for a long time but no good way, is there a good optimization method, may be ?
mycode:
...ANSWER
Answered 2021-May-22 at 12:49An other formula for the product of the divisors of N
is N ** (D/ 2)
, where D is the number of divisors and may be found from your map count
by taking the product of entry->second + 1
for every entry.
This does raise the question of what to do when D
is odd, which it would be if N
is a perfect square. In that case it is easy to compute sqrt(N)
(the exponents would all be even, so you can halve them all and take the product of the primes to half of their original exponents), and then raise sqrt(N)
to the power of D
. Essentially this changes N ** (D / 2)
into (N ** (1 / 2)) ** D
.
For example if N = 2 * 3 * 2 = 12
(one of the examples), then D
will be (2 + 1) * (1 + 1) = 6
and the product of divisors will be 12 ** (6 / 2) = 1728
.
Computing N
(or its square root) should done modulo mod
. Computing D
should be done modulo mod - 1
(the totient of mod
, mod
is a prime so its totient is just one less). mod - 1
is even, so we could not have computed the modular multiplicative inverse of 2 to "divide" D
by 2 that way. When N
is a square then AFAIK we're really stuck with computing its square root (that's not so bad, but multiplying by a half would have been easier).
QUESTION
I can connect the BLE device with my XBee 3 device, but after connecting while trying to receive data through gattc_read_characteristic() method, it is receiving as empty bytes. But i can receive the data in my android mobile app. Please give me some solution !
Here is mycode.
...ANSWER
Answered 2021-May-20 at 20:04If I'm understanding everything right, you're trying to read from a characteristic which only supports notify. (According to this Microchip forum post, that characteristic only has notify.)
You want to call gattc_configure
to enable notifications and set up a callback on that characteristic. Here are the typehints for gattc_configure, and here's an example using it (with a Thunderboard device, but it's a starting point).
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