Binary-Bomb | Binary Bomb / Bomb Lab/ Assembly Bomb/ Dr Evil 's Binary Bomb | Hacking library

by luong-komorebi C Version: Current License: No License

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kandi X-RAY | Binary-Bomb Summary

Binary-Bomb is a C library typically used in Security, Hacking applications. Binary-Bomb has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Binary Bomb / Bomb Lab/ Assembly Bomb/ Dr Evil's Binary Bomb

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Support

Binary-Bomb has a low active ecosystem.

It has 46 star(s) with 21 fork(s). There are 3 watchers for this library.

It had no major release in the last 6 months.

Binary-Bomb has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Binary-Bomb is current.

Quality

Binary-Bomb has 0 bugs and 0 code smells.

Security

Binary-Bomb has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Binary-Bomb code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Binary-Bomb does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

Binary-Bomb releases are not available. You will need to build from source code and install.

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Binary-Bomb Key Features

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Binary-Bomb Examples and Code Snippets

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Community Discussions

Trending Discussions on Binary-Bomb

Difficulty understanding logic in disassembled binary bomb phase 3

QUESTION

Difficulty understanding logic in disassembled binary bomb phase 3

Asked 2020-Apr-07 at 17:18

I have the following assembly program from the binary-bomb lab. The goal is to determine the keyword needed to run the binary without triggering the explode_bomb function. I commented my analysis of the assembly for this program but I am having trouble piecing everything together.

I believe I have all the information I need, but I still am unable to see the actual underlying logic and thus I am stuck. I would greatly appreciate any help!

The following is the disassembled program itself:

...

ANSWER

Answered 2020-Apr-07 at 02:28

rep movsl copies 32-bit longwords from address %esi to address %edi, incrementing both by 4 each time, a number of times equal to %ecx. Think of it as memcpy(edi, esi, ecx*4).

See https://felixcloutier.com/x86/movs:movsb:movsw:movsd:movsq (it's movsd in Intel notation).

So this is copying 19*4=76 bytes.

Source https://stackoverflow.com/questions/61071660

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

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