alcove | Erlang system containers

 by   msantos C Version: Current License: ISC

kandi X-RAY | alcove Summary

kandi X-RAY | alcove Summary

alcove is a C library. alcove has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

When alcove is started, it enters an event loop:.
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            kandi-support Support

              alcove has a low active ecosystem.
              It has 43 star(s) with 3 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 2 have been closed. On average issues are closed in 503 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of alcove is current.

            kandi-Quality Quality

              alcove has 0 bugs and 0 code smells.

            kandi-Security Security

              alcove has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              alcove code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              alcove is licensed under the ISC License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              alcove releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.

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            alcove Key Features

            No Key Features are available at this moment for alcove.

            alcove Examples and Code Snippets

            No Code Snippets are available at this moment for alcove.

            Community Discussions

            QUESTION

            How to rerender a component from another component
            Asked 2022-Feb-16 at 19:01

            ...

            ANSWER

            Answered 2022-Feb-16 at 13:10

            Actually, when Filter update data, is just the state, so CarCard don't know that something change. You need put the dataState and the setfunction on Home component and provide the setfucntion callback and dataState to your Filter component and provide the dataState to CarCard.

            Source https://stackoverflow.com/questions/71142000

            QUESTION

            expanding data columns by row value
            Asked 2021-Jul-16 at 13:16

            I have data which looks like:

            ...

            ANSWER

            Answered 2021-Jul-16 at 13:16

            You can achieve this by using replace and fill -

            Source https://stackoverflow.com/questions/68409598

            QUESTION

            Make sure no duplicates in "parent" of parent
            Asked 2020-Dec-15 at 19:40

            I'm using MariaDB and PHPMyAdmin, but my code is all neutral so happy to switch to Postgres or whatever, but this should be straight forward enough. I haven't designed anything yet, just after best approaches.

            I have 3 database tables that describes a premises. Let's say a hotel.

            This theoretical hotel has multiple venues - 2 restaurants and a bar. Each of those has a few different rooms/areas. In these rooms are tables that customers can sit at.

            In SQL, I imagine the tables would look like this

            Venues Venue ID Venue Name 1 Restaurant 1 2 Restaurant 2 3 Bar Rooms Room ID Room Name Parent Venue (foreign key) 1 Patio 1 2 Function Room 1 3 Alcove 3 4 Private Dining 2 Tables Table ID Table Name Parent Room (foreign key) 1 Table 1 1 2 Table 2 1 3 Table 3 1 4 Table 4 2 5 Table 1 3 6 Table 2 3 7 Table 3 3 8 Table 4 3 9 Table 1 4 10 Table 2 4 11 Table 3 4

            I hope that data is correct :p

            What I want to do is define a relationship whereas it's impossible to add a Table Name if it already exists in that venue. It doesn't matter what room the table is in.

            E.g if I was to add another "Table 4", it would succeed in being entered if it was entered into Room 4, as Room 4 belongs to Restaurant 2, which does not already have a "Table 4". However if it was entered into any other room, it would fail as Restaurant 1 and Bar already have a "Table 4" in one of their rooms.

            Now in the server side code this is fairly easy to check as I can do multiple queries or joins or a myriad of other ways, however I was wondering how to do this in SQL/PhpMyAdmin directly. I'm having a bit of trouble finding my way around MyAdmin.

            Cheers

            ...

            ANSWER

            Answered 2020-Dec-14 at 14:59

            My recommendation is to redundantly include the parent venue in the tables table. So tables would have the additional column:

            Source https://stackoverflow.com/questions/65291186

            QUESTION

            How can I transform this dataframe in order to print it with seaborn ( lineplot )?
            Asked 2020-Sep-04 at 11:49

            I have a dataframe like the following:

            ...

            ANSWER

            Answered 2020-Sep-04 at 11:49

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install alcove

            When starting alcove, pass in the exec option:.
            sudo
            setuid
            Linux: file capabilities See capabilities(7) and setcap(8).

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/msantos/alcove.git

          • CLI

            gh repo clone msantos/alcove

          • sshUrl

            git@github.com:msantos/alcove.git

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