keyboard_layout | Моя раскладка для Ergodox EZ

As @Ben P. pointed out, i obviously have to change return keyboardView to return view. I had overlooked it at first.

Calling SendInput() with cInputs==1 is (almost) always a bug in user code. Don't do it! One of the main benefits of using SendInput() over keybd_event() is the ability to atomically submit an array of inputs at one time (so no need for using BlockInput() at all).

In this case, create an array of INPUTs for the keystrokes, and then call SendInput() only 1 time. And, per the KEYBDINPUT documentation, KEYEVENTF_UNICODE doesn't take virtual key codes as input, it takes actual Unicode text characters instead (which means you don't have to deal with keyboard layouts manually).

You are also not sending KEYEVENTF_KEYUP events at all. You need those, even when using KEYEVENTF_UNICODE.

See my previous answer to Sending Two or more chars using SendInput for more details.

With that said, try something more like this instead:

In this case, it is most preferable to use QGraphicsScene with QGraphicsItem, for this case I will use svg:

Hard to say exactly what's going on based on the code provided, but one thing you can try is changing your create_audit method to:

After searching a while I found a solution burried in this specific site.

If you've already set your .kivy/config.ini file up to work when you use a command to start kivy, this will work for you:

"sudo cp ~/.kivy/config.ini /root/.kivy/config.ini"

It copies the config file to the root folder, which made touchscreen on boot work for me.

source

Is there a way to find out current keyboard layout ?

Unless you mean "the keyboard that is visible to the user right this instant", there is no concept of a "current keyboard layout" in Android. A user may have 0-N input method editor implementations available to them, choosing among them as the user sees fit. Plus, depending on circumstances (e.g., inputType hints), an input method editor can display different input options.

Is it possible to find out if the current keyboard layout has there also digits row ?

No.

And potentially other "nonstandard" things ?

No.

I have worked it out many thanks for help, i have found that i was using the term story_category for the first statement, so i have written a new statement out for story tags

I wrote a script in Python that will generate the combinations of steno order like you wanted. Some notes:

• This is similar to some Plover code, which is also written in Python.
• This code will generate chords with impossible combinations (unless you use a Philly shift, e.g. -SD, -TZ, -TSD, -SDZ, etc.)
• I included the number bar output as well.

There are a lot of combinations…with chords ranging from 1 to 10 keys I got 1,698,159 results. For 1 to 23, there are 8,388,606 possible chords.

Here are the possible chords with 1 to 10 keys (note that this page will load slowly due to the large amount of data).

And here is the script that I used to generate this file:

Using auto w = WCHAR(malloc(1)) is wrong. malloc() dynamically allocates a block of bytes, not characters. WCHAR is 2 bytes in size, but you are allocating only 1 byte. Which doesn't matter since you don't use the pointer anyway. You are type-casting the pointer to a single WCHAR, truncating the pointer value. And then you are dismissing the value when passing &w to ToUnicodeEx() as it will overwrite the value of w. You are then leaking the allocated memory since you are not calling free() to deallocate it.

You don't need the malloc() at all: