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QUESTION
ANSWER
Answered 2020-Sep-23 at 09:21Those offsets are the addresses of variables on the stack. Where they are positioned depends completely on the functions called before the starting point.
For example, imagine this code, in an imaginary simple 16-bit processor that uses the stack to pass all parameters:
QUESTION
I have done up a query builder using join with the following setup:
My Tables
...ANSWER
Answered 2020-Sep-03 at 13:22If you perform the correct joins, you'll get the output you expect:
following your description, you start with selecting from table users, then join add_game table on it, next you join game table on add_game and last you join table teams again on add_game.
the query looks like:
QUESTION
So I have these three lists which I want to hide.
...ANSWER
Answered 2020-Jul-05 at 11:24querySelectorAll
only takes one parameter:
QUESTION
I am trying to sort all of the game objects inside games alphabetically I have a function for it and where I am calling it but my button does not appear to do anything onclick the idea is to upon accessing the site nothing is sorted then once you click the button it sorts all games by title alphabetically. I am still new to Javascript any advice on achieving this better then my current sort function is appreciated. Below are my code snippets for the sort function the event listener and the html implementation.
*edit 1: I have refactored a bit and it is coming back as undefined when the button is clicked. Adding my 2 snippets as I am executing it differently now.
...ANSWER
Answered 2020-May-04 at 18:40With some refactoring what was becoming an issue was within the HTML I was calling the function before the data was being rendered causing the function to work on an array of 0 objects altering my button click and adding the event listener to where the rest of them were being initialized resolved the issue. Below is the updated HTML and JS Function that worked for me.
QUESTION
I'm working on android with Java and I'm implementing the Model-View-Presenter architecture. There are two types of games the player can play:
- Game A
- Game B
Both games are really similar but with each their respective .class documents and (e.g. GameA.class and a GameB.class).
In both cases, their respective presenters are the same, with the only thing changing being the instantiation & declaration of the model class. For example:
GameAPresenter.class:
...ANSWER
Answered 2020-Jan-15 at 19:45You are gonna want to create a generic Game
class that GameA
and GameB
can then both inherit from.
Same can go with the GamePresenter
, create a generic one that GamePresenterA
and GamePresenterB
can inherit from. Also you can give the GamePresenter
a Game
everytime you create a new instance of it or call a certain method. That way there can be a single GamePresenter
and it can take whatever Game
to present it.
QUESTION
ANSWER
Answered 2018-Apr-16 at 22:02One option would be to have an SQL query do the work. For example the following query:-
QUESTION
I am learning the concepts of object-oriented programming. One of them is abstraction. I understand that any class containing an abstract method should be abstract as well and that an abstract class cannot be instantiated. To use an abstract class I have to inherit it from another.
So far so good. Let's take the following code:
...ANSWER
Answered 2017-Dec-18 at 16:49Right, so in a sense abstract class / interfaces are contracts that require you to provide your own implementation of the contract. For instance you're writing a logging library that can write to a file, database, etc. Consider how would you mandate any one to implement the functionality to persist to the underlying io. To achieve this you make your code to work with an instance of your interface / abstract class. Now the difference between those two is as simple as interfaces have no implementation. Well, up until Java 8, but nevermind, that's not something to be concerned about ATM. Your abstract class can have certain methods implemented. Such as retry if your write attempt did not succeed. But the actual write operation will only exist in the one implementing it. The interface can not.
QUESTION
@interface ViewController ()
@property (nonatomic,strong) NSMutableArray * gameB;
@property (nonatomic,strong) NSMutableArray * rows;
- (IBAction)initialize:(id)sender;
- (BOOL) isEmpty;
@end
ANSWER
Answered 2017-Jan-27 at 08:59Just loop through the array and set the label.
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