BEADS | A framework for automated vulnerability discovery in SDNs

 by   samueljero C Version: Current License: Non-SPDX

kandi X-RAY | BEADS Summary

kandi X-RAY | BEADS Summary

BEADS is a C library. BEADS has no bugs, it has no vulnerabilities and it has low support. However BEADS has a Non-SPDX License. You can download it from GitHub.

A framework for automated vulnerability discovery in SDNs
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              BEADS has a low active ecosystem.
              It has 10 star(s) with 7 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              BEADS has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of BEADS is current.

            kandi-Quality Quality

              BEADS has no bugs reported.

            kandi-Security Security

              BEADS has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              BEADS has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              BEADS releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            BEADS Key Features

            No Key Features are available at this moment for BEADS.

            BEADS Examples and Code Snippets

            No Code Snippets are available at this moment for BEADS.

            Community Discussions

            QUESTION

            Dealing with responsive css when phone is flipped horizontally
            Asked 2021-May-22 at 20:28

            Hi I'm currently creating a website for someone and my boss noticed that when the phone is flipped horizontally for example on a Iphone X, my images that are responsive the text in the middle is shifted up and you cannot read it. It's hard to explain in words so I have 2 pictures, one with what I'm getting and one with what I'm kind of looking for, I've been on this for a little while now.

            What I'm getting:

            What I'm looking for:

            This is my code:

            HTML

            ...

            ANSWER

            Answered 2021-May-22 at 19:09

            maybe this?....

            i removed the following as shown by commented out.

            Source https://stackoverflow.com/questions/67638917

            QUESTION

            Deserializing values I need from large JSON using System.Text.Json Utf8JsonReader
            Asked 2021-Apr-28 at 03:30

            I'm trying to do the following..

            Not represent JSON in a POCO

            Find and Deserialize only the value of a particular property hidden deep within a large JSON using Utf8JsonReader.

            Filter for JSON tokens : working

            Following is the code that is working.

            ...

            ANSWER

            Answered 2021-Apr-28 at 03:30

            What I need to do is if page type is Success Confirmation, get the value of orderid and amount_to_pay.

            I think you're overthinking it. You could just map the classes:

            Source https://stackoverflow.com/questions/67284469

            QUESTION

            Take user input from Kivy App and append to google sheets using Python
            Asked 2021-Apr-02 at 02:04

            I'm trying to make a simple Python Kivy app (using a kv file for the layout) that I will use to keep inventory of my parts for work. I am very new to python and kivy, so I need a little bit of direction on this.

            One of the basic functions will be to allow the user to input a new part on the "Add Part to Inventory" screen (one of four screens). The user input consists of four items (part name, serial number, on-hand quantity, and the minimum amount needed).

            Once the user enters this info and presses the 'Submit' button, I would like that data to be appended to a new row in a google sheet that I'm using as a backend database using the Google Drive/Sheets API (which I was able to get working).

            Most of the example apps that I've found online only have one screen, and are only dealing with one type of user input (usually text, whereas my input will be text and integers).

            I'm confused as to where I need to put my ids in the kv file (I'm assuming under the AddPartWindow layout), how to call a function when a button is pressed that is not in the root class, how to store the user input into a list since I'm not sure what the ObjectProperty function is really doing, and finally, how to append that list to a new row in my google sheet.

            I'm not looking for a cut and paste answer, just some direction would be nice as I have not been able to find a good reference for exactly what I'm trying to do. My main confusion lies in having multiple screens, and how to transfer data between the different screens and their respective classes. Should data only be funneled through a single root class? Or can each class be used to handle data coming from their respective screens (windows) in the app? What exactly is the ObjectProperty function doing? I find the kivy website to be a bit convoluted when describing the properties class.

            Any help/direction woud be greatly appreciated.

            Here is the main.py code:

            ...

            ANSWER

            Answered 2021-Apr-01 at 01:55

            this main.py feel free to import what u need. this a simple example of what u want to do

            Source https://stackoverflow.com/questions/66897185

            QUESTION

            Reset or make continuous Motion Layout for counter app
            Asked 2020-Dec-22 at 15:37

            I am building a counter-based android application using motion layout. I have built this scene using motion layout where you can slide the bead and it'll add +1 to the counter. The initial scene of moving the bead from one place to another on swipe works great but now I don't know how to make the bead start from the initial position it was on and then swipe it to the final position which will then add another +1 to the counter.

            I want the process to be continuous as if you're counting on real beads. The code below so far works great. I need help to make the counting process to continue and how to know when that the bead has reached its final position to add +1.

            counter_fragment.xml

            ...

            ANSWER

            Answered 2020-Dec-22 at 15:37

            You can use a listener :

            Source https://stackoverflow.com/questions/65279700

            QUESTION

            overlaying two normal distributions over two histograms on one plot in R
            Asked 2020-Aug-27 at 05:15

            I'm trying to graph two normal distributions over two histograms in the same plot in R. Here is an example of what I would like it to look like:

            Here is my current code but I'm not getting the second Normal distribution to properly overlay:

            ...

            ANSWER

            Answered 2020-Aug-27 at 05:15

            To have them on the same scale, the easiest might be to run hist() first to get the values.

            Source https://stackoverflow.com/questions/63604125

            QUESTION

            Apache Royale : How to detect enter key on j:textInput
            Asked 2020-May-28 at 11:08

            I have this code :

            ...

            ANSWER

            Answered 2020-May-27 at 23:14

            you need to listen for KeyboardEvent.KEY_DOWN on the strand (TextInput).

            If you are in MXML, first add a listener for initComplete in the surrounding container for listenKeyDown:

            Source https://stackoverflow.com/questions/62027555

            QUESTION

            Curse of the SKlearn Classifiers
            Asked 2020-May-22 at 12:38

            Suppose we have 1,000 beads 900 red and 100 blue ones. When I run the problem through SKlearn classifier ensembles,

            score = clf.score(X_test, y_test)

            They come up with scores of around .9 however, when I look at the predictions I see that it has predicted all of them to be Red and this is how it comes up with %90 accuracy! Please tell me what I'm doing wrong? Better yet, what does it mean when this happens? Is there a better way to measure accuracy?

            ...

            ANSWER

            Answered 2020-May-22 at 12:22

            You have an imbalanced classification problem. You are write, by default score measures accuracy, but it is recommended to look at recall and precision for imbalanced data.

            This video explains it better than I could

            The video above demonstrates you what you should do in order to measure classification performance in your data. To deal with data imbalance, you check imblearn library:

            https://imbalanced-learn.readthedocs.io/en/stable/api.html

            Source https://stackoverflow.com/questions/61954811

            QUESTION

            Apache Royale : equivalent of enabled property on j:Button
            Asked 2020-Apr-22 at 00:08

            I have issue on using "enabled" with j:Button.

            I know that I must add functionality with this bead :

            ...

            ANSWER

            Answered 2020-Apr-22 at 00:08

            There are a couple of ways this can be achieved.

            Access the bead dynamically on the button

            Source https://stackoverflow.com/questions/60760550

            QUESTION

            Getting the number of unique states in a graph
            Asked 2020-Apr-14 at 02:50

            I've been trying to solve MIT's Mathematics for Computer Science problem sets and here's one of the problems:

            Each monk entering the Temple of Forever is given a bowl with 15 red beads and 12 green beads. Each time the Gong of Time rings, a monk must do one of two things:

            1. Exchange: If he has 3 red beads in his bowl, then he may exchange 3 red beads for 2 green beads.
            2. Swap: He may replace each green bead in his bowl with a red bead and replace each red bead in his bowl with a green bead. That is, if he starts with i red beads and j green beads, then after he performs this operation, he will have j red beads and i green beads.

            A monk may leave the Temple of Forever only when he has exactly 5 red beads and 5 green beads in his bowl.

            There are sub-problems to this:

            1. Prove that no one ever leaves the temple. This I proved using mathematical induction.
            2. Prove that there are only a finite number of states that can be reached by this problem. This proof was also done by using mathematical induction and proving that the sum of number of red beads and green beads can only ever reduce or stay the same.
            3. (This is where I am stuck) What is the true maximal number of unique states a monk can visit in any execution of the Temple of Forever machine?

            After spending a considerable amount of time trying to think of sub-problem #3, I gave up and decided to write a program to count the number of unique states.

            ...

            ANSWER

            Answered 2020-Apr-13 at 17:31

            Edit: In the light of OP's own answer and our discussion in the comments, this was the key issue:

            We have to distinguish between two different numbers:

            1. The maximum number n of visited states in any one path the monk can take;
            2. The overall number N of states the monk could reach.

            Note that N is the cardinality of the union (taken over all possible paths) of the sets of states visited in any one path. This implies n <= N, and it's easy to see that these numbers are not equal. The MIT question asked about n, whereas OP's original code was designed to find N.

            The quoted proof is correct, so "an upper bound on [n] is 25 + 26 + 1 = 52".

            I tried a Monte Carlo approach to approximate N: Decide randomly whether to exchange or swap whenever there is a choice, repeat until the process oscillates between (2, 0) and (0, 2), and repeat all of this a huge number of times, while keeping track of all unique visited states.

            However, this does not appear to be practical, because the number of possible paths is too large, so the number we get does not come close to N with any feasible number of iterations. The following code already took about 15 minutes on my machine.

            Source https://stackoverflow.com/questions/61176175

            QUESTION

            Super stuck on USACO Broken Necklace Problem
            Asked 2020-Mar-20 at 03:29

            As a foreword, this problem has been asked about before. However, it's either been asked using different languages or different approaches, and I'd rather understand the problem with my code as opposed to copy-pasting the accepted solution.

            So, for context, the problem goes something like this:

            Given a string of beads like rwbbwrbwbrwbrb, find the maximum length of consecutive beads of one color (letter) followed by beads of the other color (letter) with the caveat that white can be counted as red or white.

            For example, wwwbbrwrbrbrrbrbrwrwwrbwrwrrb should return 11 because you could break the necklace after wwwbbrwrbrbrrbrbrwrwwrbto have wrwrrbwwwbb (keeping in mind that a necklace loops over itself, not like a list) which would end up being rrrrrbbbbbb in terms of color.

            My code(I've stripped all the I/O parts to simplify it) with the test case rwrwrwrwrwrwrwrwrwrwrwrwbwrwbwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwrwr of length 77:

            ...

            ANSWER

            Answered 2020-Mar-20 at 03:29
            Retraction: Alistair's answer is better & this program still doesn't account for starting on a w

            Never mind, I solved it. The solution was to also iterate over the list backwards. Here was my complete implementation

            Source https://stackoverflow.com/questions/60765354

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install BEADS

            You can download it from GitHub.

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            https://github.com/samueljero/BEADS.git

          • CLI

            gh repo clone samueljero/BEADS

          • sshUrl

            git@github.com:samueljero/BEADS.git

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