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kandi X-RAY | perfbook Summary
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QUESTION
Consider the following program: 2 threads are iterating through the same function that consists of incrementing the value of a shared counter variable. There's no lock protecting the variable, as such we're talking about lock-free programming. We're also ensuring that the threads will run on different cores/CPUs. The number of iterations is sufficiently large (eg N=100,000).
The operations themselves are below, listed as pseudocode. As expected, there will be various delays between the instructions, depending on what other things the CPUs do. The one below is just one possible way of running them.
...ANSWER
Answered 2020-Aug-04 at 15:46You're correct, memory barriers can't create atomicity. They only order this core's own accesses to its L1d cache (e.g. drain the store buffer before later stores or loads = full barrier, or wait for earlier loads to read cache before any later loads and stores can execute = light-weight barrier). They don't bundle together multiple instructions into an atomic RMW transaction.
To create atomicity wrt. anything another core can do, you need this core to keep the cache line in MESI Exclusive or Modified state from the load to the store (Can num++ be atomic for 'int num'?). Barriers don't do that, you need special asm instructions like x86 lock add dword [mem], 1
or on many RISC-like machines, an LL/SC retry loop that aborts the store if the cache line hasn't stayed exclusive to this core since the load-linked.
Memory barriers are important for C++ std::atomic
because that also implies ordering (acquire, release, or seq_cst), unless you use memory_order_relaxed
in which case compilers will never use barrier instructions.
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