pear | WebRTC Library for IoT/Embedded Device using C
kandi X-RAY | pear Summary
kandi X-RAY | pear Summary
Pear is a WebRTC SDK written in C. The SDK aims to integrate IoT/Embedded device video/audio streaming with WebRTC.
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pear Examples and Code Snippets
Community Discussions
Trending Discussions on pear
QUESTION
I've got two data tables as below:
...ANSWER
Answered 2022-Mar-28 at 05:22library(data.table)
cbind(have1, transpose(have2, make.names = "variable"))
QUESTION
Say I have the following typescript code:
...ANSWER
Answered 2022-Mar-26 at 08:55It's not "vscode's typescript extension," it's TypeScript. It doesn't let you do two mappings in a single type
construct. It's just the syntax of the construct doesn't allow it.
Instead, you do what you showed:
QUESTION
I cannot find anywhere how to convert a pandas dataframe to type datasets.dataset_dict.DatasetDict
, for optimal use in a BERT workflow with a huggingface model. Take these simple dataframes, for example.
ANSWER
Answered 2022-Mar-25 at 15:47One possibility is to first create two Datasets and then join them:
QUESTION
df1:
...ANSWER
Answered 2022-Mar-21 at 18:49It is not clear from your example how you want to combine the fruits in meats with the fruits in fruit, but based on your actual example:
QUESTION
I want to convert pandas dataframe to a key value pair dictionary by combining index and column name as key. Is there a easy way to do it?
Before:
...ANSWER
Answered 2021-Oct-11 at 14:27Use DataFrame.to_dict
followed by a dictionary comprehension:
QUESTION
Given the user table as follow:
...ANSWER
Answered 2022-Mar-13 at 14:30Here's one way:
QUESTION
import pandas as pd
data_list = [['Name', 'Fruit'],
['Abel', 'Apple'],
['Abel', 'Pear'],
['Abel', 'Coconut'],
['Abel', 'Pear'],
['Benny', 'Apple'],
['Benny', 'Apple'],
['Cain', 'Apple'],
['Cain', 'Coconut'],
['Cain', 'Pear'],
['Cain', 'Lemon'],
['Cain', 'Orange']]
record_df = pd.DataFrame(data_list[1:], columns = data_list[0])
...ANSWER
Answered 2022-Feb-13 at 06:58The subset
parameter is for saying where you're looking for duplicates, so it should be 'Fruit'
. The name
column is what you want to group by, so you can do:
QUESTION
I have a table with x num of rows, I have a second table with the same number of rows but different columns and metadata, they have different table models. but each row represents the same object (a song).
I want to synchronize row sorting between the two tables so for example if I sort on column 2 of table 1 then rows of the table will be sorted in the same order. But currently, I just have sorted by matching sort keys so sort on the same column (but because different data get different results)
e.g
Starting point
...ANSWER
Answered 2022-Feb-09 at 16:07Here is what I meant in the comments:
QUESTION
I'm fairly new to R and am sure there's a way to do the following without using loops, which I'm more familiar with.
Take the following example where you have a bunch of names and fruits each person likes:
...ANSWER
Answered 2022-Feb-06 at 17:53df %>%
unnest(everything()) %>%
xtabs(~., .) %>%
as.data.frame.matrix() %>%
rownames_to_column('name')
name apple banana pear
1 Alice 1 0 1
2 Bob 1 1 0
QUESTION
Similar questions have been asked, however, none have the additional element of having to split the vector names, so I am asking a new question.
I am trying to turn a named vector into a symmetric matrix in R. My vector contains the names of every combination of values in the matrix. so I need to split the names into their component parts.
For example, if my data looks like this:
...ANSWER
Answered 2022-Feb-02 at 18:22We could split the names, expand the data to create the missing combinations (complete
) and reshape to wide with pivot_wider
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