rmw | trashcan/recycle bin utility for the command line | Command Line Interface library
kandi X-RAY | rmw Summary
kandi X-RAY | rmw Summary
rmw (ReMove to Waste) is a safe-remove utility for the command line. It can move and restore files to and from directories specified in a configuration file, and can also be integrated with your regular desktop trash folder (if your desktop environment uses the FreeDesktop.org Trash specification). One of the unique features of rmw is the ability to purge items from your waste (or trash) directories after x number of days. rmw is for people who sometimes use rm or rmdir at the command line and would occasionally like an alternative choice. It's not intended or designed to act as a replacement for rm, as it's more closely related to how the FreeDesktop.org trash system functions.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of rmw
rmw Key Features
rmw Examples and Code Snippets
OPTIONS
-h, --help
show help for command line options
-c, --config FILE
use an alternate configuration
-l, --list
list waste directories
-g[N_DAYS], --purge[=N_DAYS]
meson builddir
cd builddir
ninja
meson -Dprefix=$HOME/.local builddir
meson configure -Dprefix=$HOME/.local
meson install
ninja uninstall (uninstalls the program if installed with 'ninja install`)
sh uninstall_langs.sh
Community Discussions
Trending Discussions on rmw
QUESTION
so the dataframe called idio_vol looks like:
...ANSWER
Answered 2022-Apr-02 at 20:46I could make this work, although I'm not sure if the result is correct.
I replace .transform
with .apply
, but I also had to put in a rather arbitrary call to df.columns
there. I can't tell yet whether this is a bug in Pandas (1.4.1) or there is something else I'm missing.
Here's my attempt:
QUESTION
Here's the code under consideration:
...ANSWER
Answered 2022-Mar-19 at 18:22
char*
pointer in the brackets is being converted to theint*
, causing resulting pointer addressing integer of 4 bytes size at base location (buffer + pos + 4
) and integer array index [0]
This incurs undefined behavior (UB) when the alignments requirements of int *
are not met.
Instead copy with memcpy()
. A good compiler will emit valid optimized code.
QUESTION
I am unable to run the command sudo apt install ros-foxy-desktop
. Following the guide here: https://docs.ros.org/en/foxy/Installation/Ubuntu-Install-Debians.html. I am able to complete all the steps until the final install which gives these errors.
Any help would be much appreciated. I've already tried to install by the guide here https://docs.ros.org/en/foxy/Installation/Ubuntu-Development-Setup.html. Is it because I am running ubuntu 21.10 desktop and need to be running 20.04 server? The issue I run into with the 20.04 server is that I won't be able to connect to the university I am at wifi, the wifi uses PEAP and I don't know how to set that up with the server to connect to the wifi.
...ANSWER
Answered 2022-Jan-25 at 19:51Currently Foxy is build for 20.04 and as such there is not a 21.04 release you can install. You will either have to install 20.04 or run some sort of container(i.e. docker).
As for the PEAP authentication, I would potentially look at this askubuntu thread.
QUESTION
I have 5 independent variables (Columns B-F in attached data) and some dependent variables (columns G-M in the attached data) and I need to do multiple regressions for each of the dependent variable against all independent ones. The regressions have to have a window of 4 years of data and they have to move one month ahead for each new estimation. I need to extract the coefficients and make vasicek adjustment for each one (except the intercept). That adjustment is just:
The data looks like
And the whole data is:
Where independent variables are placed in columns B-F and dependent variables are placed in columns G-M. I have being struggling with this problem and I have built two parts of code. First I reached to extract coefficients for regressions of each dependent variable and adjusted them according to vasicek adjustment but without taking the mobile windows I need:
...ANSWER
Answered 2021-Jun-21 at 11:15There isn't enough data in the question to run 4 years and the values of the dependent variables are missing so here is a simplified example using a w
of 3 months (rather than 4 years) and a simplified set of statistics that can be adapted by changing the inputs and reg
.
Note that yearmon class stores dates consisting of only year and month as year + fraction where fraction = 0, 1/12, ..., 11/12 for Jan, Feb, ..., Dec so the length of an interval of w months is w/12.
QUESTION
I want to supress Errors in Rmw files. So, i've tried to set the global chunk option error=TRUE
, but it doesn't work. Also it doesn't work to set the chunk option error=TRUE
directly in the chunk.
Here is an example code:
ANSWER
Answered 2021-Jan-17 at 21:53You seem to be using Sweave
from base R rather than knitr
. If you were using knitr
, you'd get a warning about the \SweaveOpts{concordance=TRUE}
statement.
If you are using RStudio, this is one of the Project Options. If you are running things directly, run knitr::knit("")
, instead of Sweave("")
.
There are a couple of other errors that will stop knitr
from working; this version fixes them:
QUESTION
The paper N4455 No Sane Compiler Would Optimize Atomics talks about various optimizations compilers can apply to atomics. Under the section Optimization Around Atomics, for the seqlock example, it mentions a transformation implemented in LLVM, where a fetch_add(0, std::memory_order_release)
is turned into a mfence
followed by a plain load, rather than the usual lock add
or xadd
. The idea is that this avoids taking exclusive access of the cacheline, and is relatively cheaper. The mfence
is still required regardless of the ordering constraint supplied to prevent StoreLoad
reordering for the mov
instruction generated.
This transformation is performed for such read-don't-modify-write
operations regardless of the ordering, and equivalent assembly is produced for fetch_add(0, memory_order_relaxed).
However, I am wondering if this is legal. The C++ standard explicitly notes under [atomic.order] that:
Atomic read-modify-write operations shall always read the last value (in the modification order) written before the write associated with the read-modify-write operation.
This fact about RMW operations seeing the 'latest' value has also been noted previously by Anthony Williams.
My question is: Is there a difference of behavior in the value the thread could see based on the modification order of the atomic variable, based on whether the compiler emits a lock add
vs mfence
followed by a plain load? Is it possible for this transformation to cause the thread performing the RMW operation to instead load values older than the latest one? Does this violate the guarantees of the C++ memory model?
ANSWER
Answered 2020-Dec-16 at 04:44(I started writing this a while ago but got stalled; I'm not sure it adds up to a full answer, but thought some of this might be worth posting. I think @LWimsey's comments do a better job of getting to the heart of an answer than what I wrote.)
Yes, it's safe.
Keep in mind that the way the as-if rule applies is that execution on the real machine has to always produce a result that matches one possible execution on the C++ abstract machine. It's legal for optimizations to make some executions that the C++ abstract machine allows impossible on the target. Even compiling for x86 at all makes all IRIW reordering impossible, for example, whether the compiler likes it or not. (See below; some PowerPC hardware is the only mainstream hardware that can do it in practice.)
I think the reason that wording is there for RMWs specifically is that it ties the load to the "modification order" which ISO C++ requires to exist for each atomic object separately. (Maybe.)
Remember that the way C++ formally defines its ordering model is in terms of synchronizes-with, and existence of a modification order for each object (that all threads can agree on). Not like hardware where there is a notion of coherent caches1 creating a single coherent view of memory that each core accesses. The existence of coherent shared memory (typically using MESI to maintain coherence at all times) makes a bunch of things implicit, like the impossibility of reading "stale" values. (Although HW memory models do typically document it explicitly like C++ does).
Thus the transformation is safe.
ISO C++ does mention the concept of coherency in a note in another section: http://eel.is/c++draft/intro.races#14
The value of an atomic object M, as determined by evaluation B, shall be the value stored by some side effect A that modifies M, where B does not happen before A.
[Note 14: The set of such side effects is also restricted by the rest of the rules described here, and in particular, by the coherence requirements below. — end note]...
[Note 19: The four preceding coherence requirements effectively disallow compiler reordering of atomic operations to a single object, even if both operations are relaxed loads. This effectively makes the cache coherence guarantee provided by most hardware available to C++ atomic operations. — end note]
[Note 20: The value observed by a load of an atomic depends on the “happens before” relation, which depends on the values observed by loads of atomics. The intended reading is that there must exist an association of atomic loads with modifications they observe that, together with suitably chosen modification orders and the “happens before” relation derived as described above, satisfy the resulting constraints as imposed here. — end note]
So ISO C++ itself notes that cache coherence gives some ordering, and x86 has coherent caches. (I'm not making a complete argument that this is enough ordering, sorry. LWimsey's comments about what it even means to be the latest in a modification order are relevant.)
(On many ISAs (but not all), the memory model also rules out IRIW reordering when you have stores to 2 separate objects. (e.g. on PowerPC, 2 reader threads can disagree about the order of 2 stores to 2 separate objects). Very few implementations can create such reordering: if shared cache is the only way data can get between cores, like on most CPUs, that creates an order for stores.)
Is it possible for this transformation to cause the thread performing the RMW operation to instead load values older than the latest one?
On x86 specifically, it's very easy to reason about. x86 has a strongly-ordered memory model (TSO = Total Store Order = program order + a store buffer with store-forwarding).
Footnote 1: All cores that std::thread
can run across have coherent caches. True on all real-world C++ implementations across all ISAs, not just x86-64. There are some heterogeneous boards with separate CPUs sharing memory without cache coherency, but ordinary C++ threads of the same process won't be running across those different cores. See this answer for more details about that.
QUESTION
I am learning the code of cppcoro project recently. And i have a question.
https://github.com/lewissbaker/cppcoro/blob/master/lib/async_auto_reset_event.cpp#L218 https://github.com/lewissbaker/cppcoro/blob/master/lib/async_auto_reset_event.cpp#L284
...ANSWER
Answered 2020-Dec-07 at 13:25The operations on the atomic variable itself will not cause data races either way.
std::memory_order_release
means that all modified cached data will be committed to shared memory / RAM. Memory order operations generate memory fences so other objects could be properly committed to / read from shared memory.
QUESTION
int value = 0;
volatile boolean done = false;
// Thread A:
value = 1; done = true;
// Thread B:
if (done) System.out.println(value);
...ANSWER
Answered 2020-May-14 at 08:53From the Javadoc of java.util.concurrent
:
The memory effects for accesses and updates of atomics generally follow the rules for volatiles, as stated in The Java Language Specification (17.4 Memory Model):
- get has the memory effects of reading a volatile variable.
- set has the memory effects of writing (assigning) a volatile variable.
- ...
So in this case, there is no difference between volatile
and AtomicBoolean
.
QUESTION
I am trying to do the panel regression, where dependent variable (stock returns for various companies) is regressed on 5 independent variables. Here is the reproductible example of a data frame of independent variables
...ANSWER
Answered 2020-May-07 at 05:59It is very likely that the error arises from the fact that you define a matrix as your independent (Y) variable, where a vector is needed. You need the data in long format, where your Y is one column, and an ID and a time column denotes the different observations.
I have some doubts about the compatibility of your two data sets, though, but you may want to merge them into one. Just carefully look, how you may merge your original data, particularly regarding the Date
columns.
When I understand your xxx
data right, the X*
are the different firms. Now convert the data in long format, using reshape
.
QUESTION
I sent an array to the server using AJAX:
...ANSWER
Answered 2020-Apr-24 at 21:02i think the best way you send JSON format, not in array
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