interp | Testing dispatch methods | Interpreter library
kandi X-RAY | interp Summary
kandi X-RAY | interp Summary
Testing interpreter dispatch methods: Switching, Direct Threaded Code, Indirect Threaded Code, Tail-Calls and machine code Inlining. Supports x86, x86-64, arm, aarch64, mips, mipsel, rv32, rv64, xtensa architectures.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of interp
interp Key Features
interp Examples and Code Snippets
Community Discussions
Trending Discussions on interp
QUESTION
I am studying ROP on Arm64, I posted my thread here Return Oriented Programming on ARM (64-bit)
However a new/separate issue about choosing rop gadgets has arisen which requires the opening of a new thread. So to sum up i am studying ROP vulnerability on ARM 64 bit and i am trying to test it using a very simple c code (attached to the previous thread). I'am using ropper tool in order to search for gadgets to build my rop chain. But when i overflow the pc with the address of the gadget i got this within gdb:
...ANSWER
Answered 2021-Jun-13 at 14:57Your gadget is at 0x55555558f8
.
Ropper shows the addresses of gadgets the way the ELF header describes the memory layout of the binary. According to that header:
- The file contents 0x0-0xadc are to be mapped as
r-x
at address 0x0. - The file contents 0xdb8-0x1048 are to be mapped as
rw-
at address 0x10db8.
Account for page boundaries and you get one page mapping file offset 0x0 to address 0x0 as executable and two pages mapping file offset 0x0 to address 0x10000 as writeable.
From your GDB dump, these mappings are created at 0x5555555000 and 0x5555565000 in the live process, respectively.
QUESTION
I would like to do a linear interpolation of my data as np.interp()
does but the machine I am using does not have numpy or scipy (and I don't have the rights to install them).
Does anyone know a way to manually code this interp function please?
My idea is to give as an input: x and y and interp_points:
...ANSWER
Answered 2021-Jun-10 at 13:56Find the closest number below the number you are looking for, and the closest number above:
QUESTION
Physical Background
I'm working on a function that calculates some metrics for each vertical profile in an up to four dimensional temperature field (time, longitude, latitude, pressure as height measure). I have a working function that takes the pressure and temperature at a single location and returns the metrics (tropopause information). I want to wrap it with a function that applies it to every vertical profile in the data passed.
Technical Description of the Problem
I want my function to apply another function to every 1D array corresponding to the last dimension in my N-dimensional array, where N <= 4. So I need an efficient loop over all dimensions but the last one without knowing the number of dimensions beforehand.
Why I Open a New Question
I am aware of several questions (e.g., iterating over some dimensions of a ndarray, Iterating over the last dimensions of a numpy array, Iterating over 3D numpy using one dimension as iterator remaining dimensions in the loop, Iterating over a numpy matrix with unknown dimension) asking how to iterate over a specific dimension or how to iterate over an array with unknown dimensions. The combination of these two problems is new as far as I know. Using numpy.nditer for example I haven't found out how to exclude just the last dimension regardless of the number of dimensions left.
EDIT
I tried to do a minimal, reproducible example:
...ANSWER
Answered 2021-Jun-07 at 11:09I've used @hpaulj 's reshape approach several times. It means the loop can iterate the whole array by 1d slices.
Simplified the function and data to have something to test.
QUESTION
I plotted a data with np.NaN. And I also want to change the center value of the colorbar due to the distribution of original data. But when I change the Vmin, Vmax and vcenter value of the colorbar, the color of np.NaN value changes to other colors other than white. So how can I fix that? Here follows the codes:
...ANSWER
Answered 2021-May-29 at 21:18Using the latest matplotlib version (3.4.2), the code seems to work as expected.
QUESTION
Edit: Still No answer works, the output is:
...ANSWER
Answered 2021-May-27 at 20:53I think your arithmetic has gone wrong.
The first LOAD segment is loaded at address 0x400000 and has size 0x1d14, so it indeed includes the 10 bytes starting at 0x401bc0, at offset 0x401bc0 - 0x400000 = 0x1bc0
into this segment. The segment starts at offset 0 in the file, so you need to look at offset 0x1bc0
in the file, not offset 0xbc0
. And 0x1bc0
is decimal 7104
.
(And 0xbc0
in decimal is 3008, not 4660. A good fact to memorize for mental arithmetic is that 0x1000 = 4096
is one page. So 0x1bc0
must be between 4096 and 8192, and likewise 0xbc0
must be less than 4096. That's how I could tell at a glance that something was wrong with your math.)
QUESTION
I read up some threads about scipy.misc.imresize
being removed in early versions, and how you have to use Pillow instead. The following is my line of code which is producing the error.
ANSWER
Answered 2021-May-20 at 07:26Let's check an old documentation page of scipy.misc.imresize
:
arr
is the image itself as a NumPy array.size
can be- an
int
(indicating some percentage), - a
float
(indicating some fraction, that's your example), or - a
tuple
(indicating a destination size).
- an
interp
is the interpolation method to use.
Now, let's check, what PIL.Image.resize
is capable of:
size
must be atuple
. So, you'd need to determine the destination size beforehand when using a percentage or fraction as given above.resample
is the resampling filter, which is basically the interpolation method as given above.
That's all we need to know to derive proper code:
QUESTION
I'm facing a problem while trying to implement the coupled differential equation below (also known as single-mode coupling equation) in Python 3.8.3. As for the solver, I am using Scipy's function scipy.integrate.solve_bvp
, whose documentation can be read here. I want to solve the equations in the complex domain, for different values of the propagation axis (z
) and different values of beta (beta_analysis
).
The problem is that it is extremely slow (not manageable) compared with an equivalent implementation in Matlab using the functions bvp4c
, bvpinit
and bvpset
. Evaluating the first few iterations of both executions, they return the same result, except for the resulting mesh which is a lot greater in the case of Scipy. The mesh sometimes even saturates to the maximum value.
The equation to be solved is shown here below, along with the boundary conditions function.
...ANSWER
Answered 2021-May-08 at 10:01Based on semi-random inputs, we can see that max_mesh
is sometimes reached. This means that coupling_equation
can be called with a quite big z_mesh
and a
arrays. The problem is that coupling_equation
contains a slow pure-Python loop iterating on each column of the arrays. You can speed the computation up a lot using Numpy vectorization. Here is an implementation:
QUESTION
I finished my command handler but I got an error and was wondering if anyone in this community could help me fix the issue?
my code:
...ANSWER
Answered 2021-May-06 at 23:47You are using dirs
when you have no such variable. I think you should use dir
.
QUESTION
I built an API with FastAPI, then I want to call it by PHP (I ran PHP by Docker, expose port 80 to 80), but It give always boolean(False). However this API works very well with JavaScript, Postman, Firefox.(I want to give results from this API to externals users so my ideal is using PHP to bring the results from this API, then give it to Front-end, I don't know how to give this API directly from FastAPI to externals users). So you can see my code for FastAPI below:
...ANSWER
Answered 2021-May-03 at 18:00I just found the solution, curl on php on docker can't call the api from host with ip 127.0.0.1.
I use command ip addr show docker0
then I take the inet address instead of localhost, and It worked.
QUESTION
I have a dataframe with three columns Time
, observed value (Obs.Value
), and an interpolated value (Interp.Value
). If the value of Obs.Value
is NA
then the value of Interp.Value
should also be NA
. I can make the whole row NA
but I need to keep the Time
value.
Here is the repex:
...ANSWER
Answered 2021-Apr-29 at 01:06dat$Interp.Value[is.na(dat$Obs.Value)] <- NA
dat
# Time Obs.Value Interp.Value
# 1 1 5 5
# 2 2 6 6
# 3 3 7 7
# 4 4 NA NA
# 5 5 NA NA
# 6 6 5 5
# 7 7 4 4
# 8 8 3 3
# 9 9 NA NA
# 10 10 2 2
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install interp
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page