interp | Testing dispatch methods | Interpreter library

 by   vshymanskyy C Version: Current License: MIT

kandi X-RAY | interp Summary

kandi X-RAY | interp Summary

interp is a C library typically used in Utilities, Interpreter applications. interp has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Testing interpreter dispatch methods: Switching, Direct Threaded Code, Indirect Threaded Code, Tail-Calls and machine code Inlining. Supports x86, x86-64, arm, aarch64, mips, mipsel, rv32, rv64, xtensa architectures.
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              interp has a low active ecosystem.
              It has 30 star(s) with 1 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              interp has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of interp is current.

            kandi-Quality Quality

              interp has no bugs reported.

            kandi-Security Security

              interp has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              interp is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              interp releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            interp Key Features

            No Key Features are available at this moment for interp.

            interp Examples and Code Snippets

            No Code Snippets are available at this moment for interp.

            Community Discussions

            QUESTION

            Find out where rop gadgets are actually loaded in memory using Ropper
            Asked 2021-Jun-13 at 14:57

            I am studying ROP on Arm64, I posted my thread here Return Oriented Programming on ARM (64-bit)

            However a new/separate issue about choosing rop gadgets has arisen which requires the opening of a new thread. So to sum up i am studying ROP vulnerability on ARM 64 bit and i am trying to test it using a very simple c code (attached to the previous thread). I'am using ropper tool in order to search for gadgets to build my rop chain. But when i overflow the pc with the address of the gadget i got this within gdb:

            ...

            ANSWER

            Answered 2021-Jun-13 at 14:57

            Your gadget is at 0x55555558f8.

            Ropper shows the addresses of gadgets the way the ELF header describes the memory layout of the binary. According to that header:

            • The file contents 0x0-0xadc are to be mapped as r-x at address 0x0.
            • The file contents 0xdb8-0x1048 are to be mapped as rw- at address 0x10db8.

            Account for page boundaries and you get one page mapping file offset 0x0 to address 0x0 as executable and two pages mapping file offset 0x0 to address 0x10000 as writeable.

            From your GDB dump, these mappings are created at 0x5555555000 and 0x5555565000 in the live process, respectively.

            Source https://stackoverflow.com/questions/67953651

            QUESTION

            Python Interpolation manually
            Asked 2021-Jun-10 at 14:06

            I would like to do a linear interpolation of my data as np.interp() does but the machine I am using does not have numpy or scipy (and I don't have the rights to install them). Does anyone know a way to manually code this interp function please?

            My idea is to give as an input: x and y and interp_points:

            ...

            ANSWER

            Answered 2021-Jun-10 at 13:56

            Find the closest number below the number you are looking for, and the closest number above:

            Source https://stackoverflow.com/questions/67922216

            QUESTION

            Numpy iteration over all dimensions but the last one with unknown number of dimensions
            Asked 2021-Jun-07 at 11:09

            Physical Background

            I'm working on a function that calculates some metrics for each vertical profile in an up to four dimensional temperature field (time, longitude, latitude, pressure as height measure). I have a working function that takes the pressure and temperature at a single location and returns the metrics (tropopause information). I want to wrap it with a function that applies it to every vertical profile in the data passed.

            Technical Description of the Problem

            I want my function to apply another function to every 1D array corresponding to the last dimension in my N-dimensional array, where N <= 4. So I need an efficient loop over all dimensions but the last one without knowing the number of dimensions beforehand.

            Why I Open a New Question

            I am aware of several questions (e.g., iterating over some dimensions of a ndarray, Iterating over the last dimensions of a numpy array, Iterating over 3D numpy using one dimension as iterator remaining dimensions in the loop, Iterating over a numpy matrix with unknown dimension) asking how to iterate over a specific dimension or how to iterate over an array with unknown dimensions. The combination of these two problems is new as far as I know. Using numpy.nditer for example I haven't found out how to exclude just the last dimension regardless of the number of dimensions left.

            EDIT

            I tried to do a minimal, reproducible example:

            ...

            ANSWER

            Answered 2021-Jun-07 at 11:09

            I've used @hpaulj 's reshape approach several times. It means the loop can iterate the whole array by 1d slices.

            Simplified the function and data to have something to test.

            Source https://stackoverflow.com/questions/67857864

            QUESTION

            Matplotlib imshow: Color of NaN changes when change the center value of colorbar
            Asked 2021-May-29 at 21:18

            I plotted a data with np.NaN. And I also want to change the center value of the colorbar due to the distribution of original data. But when I change the Vmin, Vmax and vcenter value of the colorbar, the color of np.NaN value changes to other colors other than white. So how can I fix that? Here follows the codes:

            ...

            ANSWER

            Answered 2021-May-29 at 21:18

            Using the latest matplotlib version (3.4.2), the code seems to work as expected.

            Source https://stackoverflow.com/questions/67743589

            QUESTION

            How to Extract Data of ELF file (Executable of C program)?
            Asked 2021-May-28 at 06:20

            Edit: Still No answer works, the output is:

            ...

            ANSWER

            Answered 2021-May-27 at 20:53

            I think your arithmetic has gone wrong.

            The first LOAD segment is loaded at address 0x400000 and has size 0x1d14, so it indeed includes the 10 bytes starting at 0x401bc0, at offset 0x401bc0 - 0x400000 = 0x1bc0 into this segment. The segment starts at offset 0 in the file, so you need to look at offset 0x1bc0 in the file, not offset 0xbc0. And 0x1bc0 is decimal 7104.

            (And 0xbc0 in decimal is 3008, not 4660. A good fact to memorize for mental arithmetic is that 0x1000 = 4096 is one page. So 0x1bc0 must be between 4096 and 8192, and likewise 0xbc0 must be less than 4096. That's how I could tell at a glance that something was wrong with your math.)

            Source https://stackoverflow.com/questions/67728792

            QUESTION

            How to replace scipy.misc.imresize with Pillow in my example?
            Asked 2021-May-20 at 07:26

            I read up some threads about scipy.misc.imresize being removed in early versions, and how you have to use Pillow instead. The following is my line of code which is producing the error.

            ...

            ANSWER

            Answered 2021-May-20 at 07:26

            Let's check an old documentation page of scipy.misc.imresize:

            • arr is the image itself as a NumPy array.
            • size can be
              • an int (indicating some percentage),
              • a float (indicating some fraction, that's your example), or
              • a tuple (indicating a destination size).
            • interp is the interpolation method to use.

            Now, let's check, what PIL.Image.resize is capable of:

            • size must be a tuple. So, you'd need to determine the destination size beforehand when using a percentage or fraction as given above.
            • resample is the resampling filter, which is basically the interpolation method as given above.

            That's all we need to know to derive proper code:

            Source https://stackoverflow.com/questions/67614204

            QUESTION

            Performance issue with Scipy's solve_bvp and coupled differential equations
            Asked 2021-May-08 at 10:01

            I'm facing a problem while trying to implement the coupled differential equation below (also known as single-mode coupling equation) in Python 3.8.3. As for the solver, I am using Scipy's function scipy.integrate.solve_bvp, whose documentation can be read here. I want to solve the equations in the complex domain, for different values of the propagation axis (z) and different values of beta (beta_analysis).

            The problem is that it is extremely slow (not manageable) compared with an equivalent implementation in Matlab using the functions bvp4c, bvpinit and bvpset. Evaluating the first few iterations of both executions, they return the same result, except for the resulting mesh which is a lot greater in the case of Scipy. The mesh sometimes even saturates to the maximum value.

            The equation to be solved is shown here below, along with the boundary conditions function.

            ...

            ANSWER

            Answered 2021-May-08 at 10:01

            Based on semi-random inputs, we can see that max_mesh is sometimes reached. This means that coupling_equation can be called with a quite big z_mesh and a arrays. The problem is that coupling_equation contains a slow pure-Python loop iterating on each column of the arrays. You can speed the computation up a lot using Numpy vectorization. Here is an implementation:

            Source https://stackoverflow.com/questions/67400917

            QUESTION

            How can I make the event handler
            Asked 2021-May-08 at 04:03

            I finished my command handler but I got an error and was wondering if anyone in this community could help me fix the issue?

            my code:

            ...

            ANSWER

            Answered 2021-May-06 at 23:47

            You are using dirs when you have no such variable. I think you should use dir.

            Source https://stackoverflow.com/questions/67426725

            QUESTION

            PHP can't call API from FastAPI
            Asked 2021-May-03 at 18:00

            I built an API with FastAPI, then I want to call it by PHP (I ran PHP by Docker, expose port 80 to 80), but It give always boolean(False). However this API works very well with JavaScript, Postman, Firefox.(I want to give results from this API to externals users so my ideal is using PHP to bring the results from this API, then give it to Front-end, I don't know how to give this API directly from FastAPI to externals users). So you can see my code for FastAPI below:

            ...

            ANSWER

            Answered 2021-May-03 at 18:00

            I just found the solution, curl on php on docker can't call the api from host with ip 127.0.0.1. I use command ip addr show docker0 then I take the inet address instead of localhost, and It worked.

            Source https://stackoverflow.com/questions/67362462

            QUESTION

            How can I make some row values NA if other is NA in R?
            Asked 2021-Apr-29 at 02:06

            I have a dataframe with three columns Time, observed value (Obs.Value), and an interpolated value (Interp.Value). If the value of Obs.Value is NA then the value of Interp.Value should also be NA. I can make the whole row NA but I need to keep the Time value.

            Here is the repex:

            ...

            ANSWER

            Answered 2021-Apr-29 at 01:06
            dat$Interp.Value[is.na(dat$Obs.Value)] <- NA
            dat
            #    Time Obs.Value Interp.Value
            # 1     1         5            5
            # 2     2         6            6
            # 3     3         7            7
            # 4     4        NA           NA
            # 5     5        NA           NA
            # 6     6         5            5
            # 7     7         4            4
            # 8     8         3            3
            # 9     9        NA           NA
            # 10   10         2            2
            

            Source https://stackoverflow.com/questions/67309727

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

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            You can download it from GitHub.

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