toss | Dead simple LAN file transfers from the command line
kandi X-RAY | toss Summary
kandi X-RAY | toss Summary
toss: dead simple command line file transfer.
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QUESTION
I'm right on the verge of tossing React and just using vanilla JS but thought I'd check here first. I'm simply trying to pass the contents of a variable, which contains an object, into state and have that update the element that depends upon it. If I pass setState
a variable containing the object, it doesn't work. If I pass it the explicit text of the object it does.
Using React v 18.0.0
...ANSWER
Answered 2022-Apr-15 at 23:15The issue is that of state mutation. Even though you've shallow copied the chartData
state you should keep in mind that this is a copy by reference. Each property is still a reference back into the original chartData
object.
QUESTION
I am trying to create a table (150 rows, 165 columns) in which :
- Each row is the name of a Pokemon (original Pokemon, 150)
- Each column is the name of an "attack" that any of these Pokemon can learn (first generation)
- Each element is either "1" or "0", indicating if that Pokemon can learn that "attack" (e.g. 1 = yes, 0 = no)
I was able to manually create this table in R:
Here are all the names:
...ANSWER
Answered 2022-Apr-04 at 22:59Here is the a solution taking the list of url to webpages of interest, collecting the moves from each table and creating a dataframe with the "1s".
Then combining the individual tables into the final answer
QUESTION
While setting up a basic unit testing system, I ran into an odd issue. My goal was to make sure all individual test scripts:
- were run with
set -e
to detect errors, without needing to explicitly set this in each file; - knew right away about the functions to be tested (stored in another file) without needing to explicitly source those in each test file.
Let this be a dummy test file called to-be-sourced.sh
. We want to be able to know if a command in it fails:
ANSWER
Answered 2022-Mar-25 at 16:19(This may not be precisely correct, but I think it captures what happens.)
In your first example, set -e
sets the option in a command that is lexically in the scope of an if
statement, and so even though it is set, it is ignored. (You can confirm it is set by running echo $-
inside to-be-sourced.sh
. Note, too, that .
itself has a 0 exit status, which you can confirm by replacing true
with an echo
statement; it's not that it fails but the failure is ignored.)
In your second example, -e
sets the errexit
option in a new process, which knows nothing about the if
statement and therefore it is not ignored.
QUESTION
I have the following statement I wish to parse:
key=value
- key: [a-zA-Z] ([a-zA-Z0-9_-])*
- value: [a-zA-Z] ([a-zA-Z0-9_-])*
The parser is always confused as key and value have the same rule.
my error grammar:
...ANSWER
Answered 2022-Mar-13 at 10:25ANTLR will always create a KEY
token for the input foo
. No matter if the input is mu = foo
, then too will there be 2 KEY
tokens created (with an OP
token in between).
This is simply how ANTLR's lexer works. The lexer is not "driven" by the parser. It doesn't matter if the parser is trying to match a VALUE
token, the input foo
will always be a KEY
token.
These are the 2 rules by which the lexer creates tokens:
- create the longest possible match
- if there are 2 or more lexer rules than match the same characters, let the one defined first "win"
Because of rule 2, you can see why KEY
will be created for foo
and not a VALUE
.
To fix this, do something like this:
QUESTION
I implemented and bench marked the following functions in c and java using the following code. For c, I'm getting about 1.688852 seconds while for java, it only takes like 0.355038 seconds. Even if I remove the sqrt
function, inline the code manually or change function signature to accept 6 double
coordinates (to avoid accessing via pointers) for c time lapsed doesn't improve much.
I'm compiling the c program like cc -O2 main.c -lm
. For java, I'm running the application in intellij idea with the default jvm options (java 8, openjdk).
c:
...ANSWER
Answered 2021-Oct-09 at 16:07First of all, the method used to measure the timings is very imprecise. The current methods introduce a huge bias that is probably bigger than the measure itself. Indeed, clock
is not very precise on many platforms (about 1 ms on my machine and often not better than 1 us on almost all platforms). Moreover, the imprecision is strongly amplified by the 10,000,000 iterations. If you want to measure the loop precisely, you need to move the clock call outside the loop (and if possible use a more accurate measurement function).
Still, the main problem is that the function result is unused and the Java JIT can see that and partially optimize that. GCC cannot because of the math function standard behaviour (errno
cause a side effect not available in the Java code). You can disable the use of errno using the command-line flag -fno-math-errno
. With that GCC can now totally optimize the function (ie. remove the function call) and the resulting time is much smaller. However, the benchmark is flawed and you probably do not want to measure that. If you want to write a correct benchmark, you need to read the computed value. For example, you can compute a checksum, at least to check the results are correct/equivalent.
QUESTION
So I had made this program thing in which it asks you to enter a random number,
The number can only be from the list; [1, 2, 3, 4, 5, 6, 10]
and nothing else.
I want to make if so if it is not from the list acceptables = [1, 2, 3, 4, 5, 6, 10]
it will print "Illegal Number" and exit() program. But I cannot do it .
Here is what I tried:
...ANSWER
Answered 2022-Feb-05 at 13:41Replace if toss != acceptables:
by if toss not in acceptables:
QUESTION
I am using background subtraction to identify and control items on a conveyor belt. The work is very similar to the typical tracking cars on a highway example. I start out with an empty conveyor belt so the computer knows the background in the beginning. But after the conveyor has been full of packages for a while the computer starts to think that the packages are the background. This requires me to restart the program from time to time. Does anyone have a workaround for this? Since the conveyor belt is black I am wondering if it maybe makes sense to toss in a few blank frames from time to time or if perhaps there is some other solution. Much Thanks
...ANSWER
Answered 2022-Jan-31 at 14:14You say you're giving the background subtractor some pure background initially.
When you're done with that and in the "running" phase, call apply()
specifically with learningRate = 0
. That ensures the model won't be updated.
QUESTION
I think that I would have to use a tuple or a list but I'm very new to Python so I do not know how to implement it. Any help will be greatly appreciated.
Here is my code:
...ANSWER
Answered 2022-Jan-28 at 02:45You have the right idea that another variable is needed. The most simple way would be to just have a variable for each number of wins and update it where you're printing who wins. For example
QUESTION
I am playing around with a existing perl module lets call it Obj. I have added some new features (subroutines / methods) to Obj but store them in another .pm call it Foo. However I dont want Obj to inherit every sub from Foo.
Now I have been reading perl documentation for a few hours and am confused. https://perldoc.perl.org/Exporter#Selecting-What-to-Export Just says 'Do not export method names!'
Here is some example code, I'd like to not see sub _not_exported from Obj.pm:
...ANSWER
Answered 2022-Jan-23 at 08:59[Note: I'm am a former maintainer of Exporter]
I believe you've confused exporting with inheritance. That's easy to do, Perl doesn't draw a line between "function" and "method", they're just sub
.
tl;dr You don't need to export, that's just how inheritance works, there is a work around.
Exporting lets you call a function from outside of a package without fully qualifying it. It would let you call Foo::hello
as just hello
. Exporting lets Perl know that hello
really means hello
in package Foo
.
But these are method calls, and you call them on a class or object. my $foo = Foo->new; $foo->hello
. No exporting required. Foo->new
calls new
in Foo
and returns a Foo
object. $foo->hello
knows to look for the method foo
in the ancestry of $foo
's class. You don't need to use exporter in a class, that's what "Do not export method names" means.
Exporting is a deliberate act which copies symbols around. Inheritance is all or nothing. If you inherit from a class you get all its methods (subs). This is a consequence of inheritance, and there are many other alternatives to inheritance such as composition.
In other OO languages you could declare the method private
and it would not be inherited. Perl doesn't have that. Normally you just live with this by convention as you have, put an underscore in front of the method name, don't document it, and if somebody uses it that's their problem. And that's usually fine.
But you can make truly private methods with anonymous subs and lexical variables.
QUESTION
I am trying to solve a probability question theoretically and then modeling it on C++ but my code outputs a different probability from the theoretical one.
Question:
A balanced coin is tossed three times. Calculate the probability that exactly two of the three tosses result in heads.
Answer:
Sample space: {(H,H,H), (H,H,T), (H,T,H), (H,T,T), (T,T,T), (T,T,H), (T,H,T), (T,H,H)}
Probablity that exactly two of the three tosses result in heads = 3/8
C++ Code:
...ANSWER
Answered 2022-Jan-21 at 06:39As n. 1.8e9-where's-my-share m.
correctly pointed out, You are calling TossCoin()
twice. This is your modified code that fixes the problem:
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