Technicolor | Technicolor lets you add rainbow colors | Command Line Interface library
kandi X-RAY | Technicolor Summary
kandi X-RAY | Technicolor Summary
Rainbow? To hell with rainbows! Technicolor is where it's at! Sounds fancier! Because it is. Technicolor lets you add rainbow colors to your lights, notes, walls, sabers, and even bombs. Chose between different Technicolor styles for your personal rainbow experience. Check out this comparison video:
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Trending Discussions on Technicolor
QUESTION
OK, I am stumped. For the past couple of months, I have been getting stern messages occasionally from GitHub warning me that I committed my R package using password authentication, and that will be going away. Fine. So I'd love to switch; but...
I looked at various help files. I have gotten R to generate an RSA key. I have copied that key to my GitHub account. I have run ssh-add
. After all this, I push an update and find that my SSH key info on GitHub still says it has never been used.
I seemed to find something helpful here. I in fact verified that my remote origin comes out as https://github.com/rvlenth.git
which indicates that it's still set up for password authentication. So I did what was suggested there to remove that origin. It suggests looking for something (shown in a little picture) that would give me the new link, but I can't find it on my repository. It looks like it should be git@github.com:rvlenth/emmeans
, so, like a fool, I ran git remote add origin git@github.com:rvlenth/emmeans
.
It seemed to accept that, but now the pull and push buttons in my RStudio interface are grayed out. I tried to revert back to the https
setup, and am still grayed-out.
What do I do to get this to work? I'm feeling under duress because GitHub's going to shut me down if I can't figure out how to do this.
UpdateOK, I found the green button and copied the URL it gives for SSH authentication. I also created a new key, typing-in my GitHub password in the process, and copied the public key to GitHub. I have an email from GitHub confirming that. It still fails. In fact, I tried just creating a new project and it wouldn't even work for that:
...ANSWER
Answered 2021-Mar-15 at 06:15QUESTION
I am working on CodePen and included Fabric.js in JavaScript settings. CodePen automatically bought version 2.4.4 for me: https://cdnjs.cloudflare.com/ajax/libs/fabric.js/2.4.4/fabric.min.js
When I am trying to use for example the Tint filter, I am getting its not a constructor
error in browser console.
But, the Tint filter is already available in the Fabric.js docs: http://fabricjs.com/docs/fabric.Image.filters.Tint.html
I also did: console.log(fabric.Image.filters);
and the output is:
ANSWER
Answered 2018-Dec-09 at 10:41I made some investigation to find where's tint filter gone. look at the commit: https://github.com/fabricjs/fabric.js/commit/e96ccf9ea64df529cbbbea869561a5a8da2cf1ac#diff-92d93b4f6664e4db62af0f12768dfe56R39
Tint isn't gone, but the code has changed, to use tint filter you should write:
var filter = new fabric.Image.filters.BlendColor({
color: 'red',
mode: 'tint',
alpha: 0.5
});
QUESTION
when I run
...ANSWER
Answered 2018-Apr-09 at 20:00The last IP is your scanning machine. Because it is accessed over the loopback interface, it does not have an associated MAC address. The Loopback link type does not have a physical medium, so it does not need or have a "media access control" (MAC) address. It is listed last because Nmap first scanned all the targets that used Ethernet (or similar, like WiFi) links in one group, leaving only your local address in the last group.
QUESTION
The code I have to work with is Visual Basic. I have JSON that needs to be deserialized to an object.
I am running into the error:
Cannot deserialize the current JSON object (e.g. {"name":"value"}
) into type System.Collections.Generic.List1[AgentGroup]
because the type requires a JSON array (e.g. [1,2,3]
) to deserialize correctly.
To fix this error either change the JSON to a JSON array (e.g. [1,2,3]
) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object.
Path '[0].agentGroup.id', line 3, position 7
Now what I've done is instantiated the object, serialized it and write to a text file so that I can see how that data looks in JSON, which came out to this:
...ANSWER
Answered 2018-Apr-04 at 17:52This sounds a bit simplistic but can you do the following (done with VBA as per tag - oops) ?
Standard module:
QUESTION
I am trying to select one dropdown in a group of several elements and or some reason ONE of the dropdowns cannot be selected. I get the error : => {"message":"unknown error: Element ... is not clickable at point (433, 15). Other element would receive the click: ...\n Screen shot from the product
The only control I cannot select is the PRIMARY LANGUAGE dropdown. I am trying to do it with XPATH. the addtrlno element is the Trailer Number dropdown several elements away from the Primary Language. I hate including tons and tons of code but I will try to include a LOT and see if maybe there is an errror one of you can spot.
...ANSWER
Answered 2017-Jun-03 at 04:35try following code & see if it works:
QUESTION
ANSWER
Answered 2017-Jun-06 at 10:53Use pojo generator to make pojo class
QUESTION
Ok, so I have javascript and CSS that makes words appear and then disappear permanently based on whether or not the mouse is hovering over them. Some words (exceptions
) remain visible the entire time. I'm trying to make it so there are some words that are invisible at first, but only after being hovered over, appear. Any thoughts? I've added a moreExceptions
variable, that I hope to manipulate in this way. Other than that, I'm stumped. Sorry, I'm really not a coder.
JS:
...ANSWER
Answered 2017-May-12 at 19:37UPD I like the solution with CSS by Joe Higley
Look at this.
I added css class .alwaysVisible
, which is same as .hovering
Then in JS use #[removeClass][1]
onmouseout
P.S. I also made your Exception words #toLowerCase (because some words in there were capitalized)..
QUESTION
I've created a webpage that I'm pretty happy with except it looks different on differently sized monitors. The basic idea is that you hover over the words and then they appear and disappear forever. On my laptop, I've made it so that the words go to the edge of the page--so long as it is fullscreen--and then continue on the next line, but I've noticed that this doesn't work properly on differently sized screens. The problem comes with the fact that I'm also using bottom-borders as an aesthetic element. Each line is its own element with its own borders, so that each line of text sits atop a grey bar.
Is there anyway that I can adjust the size of the page or anything to fit differently sized monitors?
CSS:
...ANSWER
Answered 2017-May-09 at 17:24There's only one thing keeping your page from doing what you expect it to and it's this:
**************************************************************************************************************************************************************
This is essentially one really long word. By default words don't break on their own so it's stretching out parent and ancestor elements, making your page wider than you'd like.
Remove this line, replace it with something else or apply word-break: break-word;
to the element containing all the asterisks.
QUESTION
I am working with movie data and have a dataframe column for movie genre. Currently the column contains a list of movie genres for each movie (as most movies are assigned to multiple genres), but for the purpose of this analysis, I would like to parse the list and create a new dataframe column for each genre. So instead of having genre=['Drama','Thriller'] for a given movie, I would have two columns, something like genre1='Drama' and genre2='Thriller'.
Here is a snippet of my data:
...ANSWER
Answered 2017-Apr-04 at 14:37I think you need DataFrame
constructor with add_prefix
and last concat
to original:
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