MathParser | a simple math parser and solver

by TezRomacH C# Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(5)Vulnerabilities Install Support

kandi X-RAY | MathParser Summary

MathParser is a C# library. MathParser has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

a simple math parser and solver

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Support

MathParser has a low active ecosystem.

It has 0 star(s) with 0 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

MathParser has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of MathParser is current.

Quality

MathParser has 0 bugs and 0 code smells.

Security

MathParser has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

MathParser code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

MathParser does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

MathParser releases are not available. You will need to build from source code and install.

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MathParser Key Features

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MathParser Examples and Code Snippets

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Community Discussions

Trending Discussions on MathParser

C# delegate casting from MethodInfo.Getmethod()

Build failed with an exception. Reason: IllegalArgumentException, message: Unsupported class file major version 57

mXparser - how to determine the token type of a user defined argument

IntelliJ indicating that enhanced switch block doesn't work despite using Java 14

mXparser result rounding

QUESTION

C# delegate casting from MethodInfo.Getmethod()

Asked 2021-May-04 at 16:22

I am writing program that makes mathematical operations on functions. I want user to input function so I wrote class which makes scource code with needed method, compiles it and saves method as delegate. This method is passed to constructor of my another class where it is stored in delegate. The problem is: it doesn't work. InvalidCastException occurs.

(I made it so I don't have to write my own math parser. Expressions such as Math.Pow(x, 2) * Math.Sin(x) should be OK, no need for things like x^2*sin(x) to work)

[Edited] Now I use

...

ANSWER

Answered 2021-May-04 at 16:22

Solution: MathParser class:

Source https://stackoverflow.com/questions/67382555

QUESTION

Build failed with an exception. Reason: IllegalArgumentException, message: Unsupported class file major version 57

Asked 2021-Apr-10 at 00:03

mxparser not working with jdk13

I am trying to use mxparser in my android project. I downloaded MathParser.org-mXparser-v.4.4.0-jdk13.jar and pasted it in libs folder of my project. But my app is failing to build and the build output is:

FAILURE: Build failed with an exception. What went wrong: Execution failed for task ':app:mergeDebugJavaResource'. Could not resolve all files for configuration ':app:debugRuntimeClasspath'. Failed to transform MathParser.org-mXparser-v.4.4.0-jdk13.jar to match attributes {artifactType=android-java-res, org.gradle.libraryelements=jar, org.gradle.usage=java-runtime}. > Execution failed for JetifyTransform: C:\Users\somagani\AndroidStudioProjects\MyApplication\app\libs\MathParser.org-mXparser-v.4.4.0-jdk13.jar. > Failed to transform 'C:\Users\somagani\AndroidStudioProjects\MyApplication\app\libs\MathParser.org-mXparser-v.4.4.0-jdk13.jar' using Jetifier. Reason: IllegalArgumentException, message: Unsupported class file major version 57. (Run with --stacktrace for more details.)

My dependencies in the build.gradle(:app) folder are

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ANSWER

Answered 2021-Apr-06 at 08:32

This is due to JDK version mismatch in the library. The library isn't updated to support the latest JDK version.

I have tested that jdk10 version works perfectly

Add jdk10 version of library to your libs folder from this folder:

Source https://stackoverflow.com/questions/66919192

QUESTION

mXparser - how to determine the token type of a user defined argument

Asked 2021-Feb-23 at 23:10

Using the library https://mathparser.org/mxparser-tutorial/playing-with-expression-tokens/

Assume I have the follow functions:

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ANSWER

Answered 2021-Feb-23 at 23:10

Take a look here:

Generally - in your example you did not define any argument. Parser will find names that are not recognized. It will give you a hint that it look like argument. Take a look on Token.looksLike field.

To define user argument follow the tutorial:

http://mathparser.org/mxparser-tutorial/user-defined-arguments/

To get the list of missing user defined arguments take a look on Expression.getMissingUserDefinedArguments(), Expression.getMissingUserDefinedUnits(), Expression.getMissingUserDefinedFunctions()

To understand the tokenTypId and tokenId study each mXparser class searching for TYPE_ID value and _ID value, for instance:

Best regards

Source https://stackoverflow.com/questions/66230273

QUESTION

IntelliJ indicating that enhanced switch block doesn't work despite using Java 14

Asked 2020-Aug-11 at 19:37

I am trying to use the enhanced switch block that was standardized in Java 14. The old version is this:

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ANSWER

Answered 2020-Aug-11 at 17:58

I have tried this and it is working just fine I think you might forget to add the package name

Source https://stackoverflow.com/questions/63363479

QUESTION

mXparser result rounding

Asked 2020-Feb-03 at 07:46

I am trying out mXparser in an android app and I almost have it working. But, if I parse the following expression "10/3" then it returns: 3.33333333335. Why this rounding in the end? and how do I tell mXparser to return 3.33333333333 instead?

I am writing the app using kotlin and has added mXparser through Maven.

Alternatively, do you know of a better/more used/more maintained math parser library for Android?

...

ANSWER

Answered 2020-Jan-28 at 09:13

The reason is that computers calculate in base 2, not base 10. The number 10/3 has an infinite expansion in both base 2 and base 10 meaning it must be truncated. The decimal expansion of 10/3 is 3.333..., which when you cut it off simplifies to a bunch of 3's; while the binary expansion is 11.010101010101... and when you cut it off and convert back to decimal, it's totally believable that you could get the 5 at the end. I'm not sure you can get around that when using a computer since computers have to use binary and they also have to truncate the binary expansion.

Source https://stackoverflow.com/questions/59944003

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

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Install MathParser

You can download it from GitHub.

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