Rivers | fast graphing library that allows for constructing
kandi X-RAY | Rivers Summary
kandi X-RAY | Rivers Summary
Rivers is a light-weight graphing library written in C#. It contains a model for directed and undirected graphs, as well as a whole bunch of standard algorithms to analyse graphs. Rivers is released under the MIT license.
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Rivers Key Features
Rivers Examples and Code Snippets
public int numRescueBoats(int[] people, int limit) {
Arrays.sort(people);
int i = 0;
int j = people.length - 1;
int boats = 0;
while (i < j) {
if (people[i] + people[j] <= limit) {
Community Discussions
Trending Discussions on Rivers
QUESTION
I have two large-ish data frames I am trying to append...
In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.
In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.
Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.
Edit: dput(df2)
...ANSWER
Answered 2022-Apr-18 at 03:52Here's one way you could turn state abbreviations into state names using R's built in state vectors:
QUESTION
I have a dataframe (df) that contains datapoints along rivers, where each river basin (Basin ID) contains multiple rivers (River ID), and each river has points along its length (Length). It looks something like this (simplified):
Basin_ID River_ID Length 1 1 5 1 1 10 1 2 5 1 2 7 1 2 12 1 3 5 2 1 5 2 1 10 2 1 12 2 1 14 2 2 5In this example Basin 1 has three rivers, and Basin 2 has two rivers. The actual table has 600K rows and 12 other columns with other river data.
Objective: I want to extract the single longest river subset for each unique basin in df, so that I end up with something like this:
Basin_ID River_ID Length 1 2 5 1 2 7 1 2 12 2 1 5 2 1 10 2 1 12 2 1 14I assume that I would need to do something like
...ANSWER
Answered 2022-Apr-07 at 20:58df2=df.assign(maxRiverLength=df.groupby('Basin_ID').transform(lambda x: x.max())['Length']).set_index(['Basin_ID','River_ID'])
df.set_index(['Basin_ID','River_ID']).loc[df2[df2['Length']==df2['maxRiverLength']].index].reset_index()
QUESTION
I need to define a recursive ML function composition that accepts two relations and returns the composition of the two relations. I need to use the thhisIsTheImageOf and createRelationFromImage function in my definition of composition.
Here is the code that is needed to be used to define the composition
...
ANSWER
Answered 2022-Apr-04 at 00:15fun composition([],_ )=[]
| composition((a,b)::rest,relation)=
let
fun thisIsTheImageOf(e,[])=[]
|thisIsTheImageOf(e,(a,b)::xs) =
if e=a
then b::thisIsTheImageOf(e,xs)
else thisIsTheImageOf(e,xs);
fun createRelationFromImage(e,[])=[]
| createRelationFromImage(e,x::xs)= (e,x)::createRelationFromImage(e,xs);
in
createRelationFromImage(a, (thisIsTheImageOf(b, relation)))@ composition(rest, relation)
end;
QUESTION
I have a list that contains data for different rivers and want to extract only the name and flow rates and insert those in a dictionary, with the name as the key and a list of the flowrates as the values. To do this I made a another list of each row that was divided better and worked from there. However, when I run the code I encounter an error on append dictionary line that simply states KeyError: 'Avon', which I don't understand so I haven't been able to find a solution.
...ANSWER
Answered 2022-Apr-03 at 08:03You will find the setdefault() function useful for this.
QUESTION
I would like to find all of the rivers within a certain bounding box. My final goal is subset them by name so I can choose which rivers to plot, but first I must know the names of the features in my extent! I'd prefer to use ggplot/tidyverse tools.
For example:
...ANSWER
Answered 2022-Mar-30 at 21:32Looks like you're pretty close. I added the missing step of turning the two diagonal points from xlim & ylim into an sf
object, and using their bounding box to subset the rivers.
QUESTION
I'm using Python to merge 4 headerless CSV's into one output file.
Each CSV has a unique number in the first column as shown in the 2 example CSV files below:
1.csv
...ANSWER
Answered 2022-Mar-21 at 01:46You could use dictionary to put all data as
QUESTION
A thief steals from you and gets a 20 meter head start. You could easily catch him on open ground, since you can run twice as fast and so catch up 5 meters for every 10 meters you travel. Once the theif reaches a time warp he is trying to get back to , you cant catch him and there are a bunch of rivers in the path: see Figure. There are N places (marked by black lines) shallow enough to cross, but you'll get 5 meters further behind for every 10 meters of river you cross. Assume the thief is too terrified to consider moving back towards the left side of the map. Given the starting and ending locations, and the positions of (both ends of) the N crossings, i want an algorithm to find whether it is possible for the thief to escape, i.e., to reach the end location before you catch up. i am struggling on how to approach this problem .. any ideas are highly appreciated ..thanks
...ANSWER
Answered 2022-Mar-10 at 14:44It's a bit unclear what exactly is needed here, but here's an outline of an approach to solve this problem:
You need to create an acyclic graph from the picture given with two sets of weights, one for you and one for the thief that represents how much time it takes each of you to travel that far (or alternatively, two acyclic graphs with the same shape but different weights):
Make nodes/vertexes out of: the starting and ending (timewarp) points, the entry points to every bridge and the exit points from every bridge.
Make edges that connect the entry point vertices of every bridge to their own exit point vertices. Set the thief's edge-weights to the length of the bridge and set yours to 1.5 times that.
Make edges from the starting point vertex to the entry points of every bridge that crosses the first river.
Make edges from the exit point vertices of every bridge over the first river to the entry point vertices of every bridge over the second river.
Repeat step 4 until you get to the last river.
Make edges from the exit point vertices of every bridge over the last river to the timewarp's vertex.
For every non-bridge edge, set the thief's weights equal to their length, and set your weights to half that.
Now, you can use A* search algorithm to determine how long it takes the their and you to get to the timewarp. Whoever would get there first wins.
For A* you need some kind of global maximum distance estimating function, if you cannot derive something for that, just use a maximum possible distance for every thing. If you do this, A* devolves into Djikstra's algorithm, which still works but is slower.
QUESTION
Creating procedural terrain I cannot get an evaporation matrix and find why my algorithm is wrong. How my program works:
- A user loads a map chunk.
- If it exists it loads its data.
- If it doesn't exist, it creates the chunk and returns the generated data.
Creation of chunk steps:
- Create a heightfield (Diamond Square algorithm).
- Create [0,3] rivers (and more chunks if river needs to continue on a different chunk).
- Calculate evaporation.
When generating the terrain I use the following constants:
...ANSWER
Answered 2022-Feb-23 at 10:52I found my mistake:
PHP considers 0 == null
but 0 !== null
, I corrected this on my script (for evaporation testing).
QUESTION
I want to generate a R markdown html document with plots and it should be possible to jump to a certain plot by search-function (in my example there are 3 plots and I want to jump in the html-doc to the plot, where the main is "rivers"). I think, the problem is, that main and axis labels of a plot are grafical elements, like the plot itself, and not text. So the search-function doesn't work.
Of course it would be possible to add manually text before each plot, but as all my plots are generated with a for-loop, I don_t know how to do it.
is there a possibilty to include text-output in this kind of for-loop or are there other ideas, how the main or axis labels of a plot can be suitable for search-function?
thanks in advance!
...ANSWER
Answered 2022-Feb-23 at 07:57You can combine a svg
device with a knitr hook:
QUESTION
I want to use purrr::map_* functions to extract info from multiple models involving linear regression method. I am first creating some random dataset. The dataset has three dependent variables, and one independent variable.
...ANSWER
Answered 2022-Jan-20 at 08:40The list_tidymodels
needs to be created with list()
and not with c()
.
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