d2 | BSD Licensed Open Source project whose purpose
kandi X-RAY | d2 Summary
kandi X-RAY | d2 Summary
D2 is a BSD Licensed Open Source project whose purpose is to provide a simple-to-use binary distribution of OpenSim, along with a few addon-ons and tools that make it easy to manage and maintain your virtual world. This project contains the code for some of the tools, along with the code for creating a packaged zip file out of an extended opensim tree. It does not contain the extended opensim tree itself. That is hosted in another project called diva-distribution. The binary packages produced by D2 can be found at
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of d2
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def map_structure(func, *structure, **kwargs):
"""Creates a new structure by applying `func` to each atom in `structure`.
Refer to [tf.nest](https://www.tensorflow.org/api_docs/python/tf/nest)
for the definition of a structure.
Applies `fun
def _kl_dirichlet_dirichlet(d1, d2, name=None):
"""Batchwise KL divergence KL(d1 || d2) with d1 and d2 Dirichlet.
Args:
d1: instance of a Dirichlet distribution object.
d2: instance of a Dirichlet distribution object.
name: (optional
def expand_dims(input: ragged_tensor.Ragged, axis, name=None): # pylint: disable=redefined-builtin
"""Inserts a dimension with shape 1 into a potentially ragged tensor's shape.
Given a potentially ragged tenor `input`, this operation inserts a
Community Discussions
Trending Discussions on d2
QUESTION
I only can separate date and time to one column.
How can i separate date and time to all columns?
...ANSWER
Answered 2021-Jun-15 at 15:28QUESTION
I have two google sheets in the same workbook and I am trying to import certain columns from one into the other sheet based on what hour of class was chosen. For example, I have the Date in column A, Name in B, Email in C, and Number in D and other stuff, then the Class in I.
Column A - Date Column B - Name Column C - Email Column D - Number ... Column I - Class
My goal is to import column B through D if column I has a certain class. I tried a using this if statemnt: =if('Confirmação'!I2 = A1,(=importrange("sheet_url","Confirmação!B2:D2")), "NOPE")
where A1 has the name of the class to look for, but it resulted in a #Error.
Then I tried a variety of query such as the following:
=QUERY({'Confirmação'!B2:D2,'Confirmação'!I2},"Where I = 'Terça 19h English 1'")
=QUERY({'Confirmação'!B2:D2, 'Confirmação'!I2},"Where 'Confirmação'!I = 'Terça 19h English 1'")
and also added the IfError: =iferror(QUERY('Confirmação'!B4:I4,"Where I = 'Terça 19h English 1'"),"Vaga")
Could someone correct my functions or help with a google script? Thank you! Very much appreciated! (Sorry about the Portugues-it's a project I am working on in Brazil)
...ANSWER
Answered 2021-Jun-15 at 17:44Instead of using a QUERY, you can use the =FILTER() function to solve your problem. Doing the following:
QUESTION
I have this situation on google sheets
I wanted to make a monthly report with sumifs
with 2 conditions like the image above. But all I got was errors.
Code I am using
=sumifs(D2:D13;D1:G1;C16;B2:B13;or(B2:B13="apple","cherry","watermelon"))
ANSWER
Answered 2021-Jun-12 at 06:30You may use combination of multiple sumifs
to solve your calculation since you won't know which will be the first row item that has market value
and sum of amount of other fruits will return 0, therefore the calculation will still give correct total.
QUESTION
Dataset looks like this : This is a sample dataset for number of employee login activity named - activity
I need to calculate few metrics, was able to do in python data frames, but new in mySQL.
what is the average number of employee active per day for month of jan 2018 by dept ( was able to do somewhat half of it, but results coming are not correct.
number of unique active employee (login >0) per month for jan 2018 for each dept_id (was able to do it)
month over month growth for all dept_id from dec-2017 to jan 2018 where at least one employee was active (login >0) - no idea how to do this in sql
fraction of users who were active in each dept_id for dec 2017 and were also active in the same dept_id for jan 2018
how many employee login in on 3 or more consecutive days in jan 2018
Any help would be appreciated.
Query written for case 1:
...ANSWER
Answered 2021-Jun-15 at 16:59Let me know if this works otherwise I will update the answer, I don't have MYSQL installed so wasn't able to check.
And the date is a keyword in oracle but not sure in MYSQL so use it in quotes like "date".
Case 1:
QUESTION
Situation: I have two dataframes df1 and df2, where df1 has a datetime index based on days, and df2 has two date columns 'wk start' and 'wk end' that are weekly ranges as well as one data column 'statistic' that stores data corresponding to the week range.
What I would like to do: Add to df1 a column for 'statistic' whereby I lookup each date (on a daily basis, i.e. each row) and try to find the corresponding 'statistic' depending on the week that this date falls into.
I believe the answer would require merging df2 into df1 but I'm lost as to how to proceed after that.
Appreciate any help you might provide! Thanks!
df1: (note: I skipped the rows between 2019-06-12 and 2019-06-16 to keep the example short.)
age date 2019-06-10 20 2019-06-11 21 2019-06-17 19 2019-06-18 18df2:
wk start wk end statistic 2019-06-10 2019-06-14 102 2019-06-17 2019-06-21 100 2019-06-24 2019-06-28 547 2019-07-02 2019-07-25 268Desired output:
age statistic date :--- :-------- 2019-06-10 20 102 2019-06-11 21 102 2019-06-17 19 100 2019-06-18 18 100code for the dataframes d1 and d2
...ANSWER
Answered 2021-Jun-15 at 09:37You could loop through the dataframe and subset the second dataframe as you go.
QUESTION
im currently having Issues with removing duplicates of a Card in a given CardArray. My current Code is attached. My Issue isnt removing duplicates themself, but how to put the Cards from the Set back into the CardArray, as that is required from the Task.
...ANSWER
Answered 2021-Jun-15 at 12:48Well your issue is due to you are not changing the size of arrayToHandle, when repeated elements are removed by Set cardSet take into account that the size of the new array is also changing, in this case from 7 to 6, [DJ] is removed, and when you're filling arrayToHandle with the new elements at the end you are not deleting the last position which is the problem you have to, try this:
QUESTION
I know there are some other questions (with answers) to this topic. But no of these was helpful for me.
I have a postfix server (postfix 3.4.14 on debian 10) with following configuration (only the interesting section):
...ANSWER
Answered 2021-Jun-15 at 08:30Here I'm wondering about the line [in s_client]
New, TLSv1/SSLv3, Cipher is ECDHE-RSA-AES256-GCM-SHA384
You're apparently using OpenSSL 1.0.2, where that's a basically useless relic. Back in the days when OpenSSL supported SSLv2 (mostly until 2010, although almost no one used it much after 2000), the ciphersuite values used for SSLv3 and up (including all TLS, but before 2014 OpenSSL didn't implement higher than TLS1.0) were structured differently than those used for SSLv2, so it was important to qualify the ciphersuite by the 'universe' it existed in. It has almost nothing to do with the protocol version actually used, which appears later in the session-param decode:
QUESTION
I wanted a ArrayFormula at C1 which gives the required result as shown.
Entry sheet:
(Column C is my required column)
Date Entered is the date when the Name is Assigned a group i.e. a, b, c, d, e, f
Criteria:
- The value of count is purely on basis of Date Entered (if john is assigned a on lowest date(10-Jun) then count value is 1, if rose is assigned a on 2nd lowest date(17-Jun) then count value is 2).
- The value of count does not change even when the data is sorted in any manner because Date Entered column values is always permanent & does not change.
- New entry date could be any date not necessarily highest date (If a new entry with name Rydu is assigned a on 9-Jun then the it's count value will become 1, then john's (10-Jun) will become 2 and so on)
Example:
After I sort the data in any random order say like this:
Random ordered sheet:
(Count value remains permanent)
And when I do New entries in between (Row 4th & 14th) and after last row (Row 17th):
Random Ordered sheet:
(Doesn't matter where I do)
={"AF Formula1"; ArrayFormula(IF(B2:B="", "", COUNTIFS(B$2:B, "="&B2:B, D$2:D, <"&D2:D)+1))}
={"AF Formula2";INDEX(IFERROR(1/(1/COUNTIFS(B2:B, B2:B, ROW(B2:B), "<="&ROW(B2:B)))))}
I tried to figure my own ArrayFormula but it's not working:
I got Formula for each cell:
=RANK($D2,FILTER($D$2:$D, $B$2:$B=$B2),1)
I figured out Filter doesn't work with ArrayFormula so I had to take a different approach.
I took help from my previous question answer (Arrayformula at H3) which was similar since in both cases each cell FILTER formula returns more than 1 value. (It was actually answered by player0)
Using the same technique I came up with this Formula which works absolutely fine :
=RANK($D2, ARRAYFORMULA(TRANSPOSE(SPLIT(VLOOKUP($B2, SUBSTITUTE(TRIM(SPLIT(FLATTEN(QUERY(QUERY({$B:$B&"×", $D:$D}, "SELECT MAX(Col2) WHERE Col2 IS NOT NULL GROUP BY Col2 PIVOT Col1", 1),, 9^9)), "×")), " ", ","), 2, 0), ","))), 1)
Now when I tried converting it to ArrayFormula: ($D2 to $D2:$D & $B2 to $B2:$B)
=ARRAYFORMULA(RANK($D2:$D,TRANSPOSE(SPLIT(VLOOKUP($B2:$B, SUBSTITUTE(TRIM(SPLIT(FLATTEN(QUERY(QUERY({$B:$B&"×", $D:$D}, "SELECT MAX(Col2) WHERE Col2 IS NOT NULL GROUP BY Col2 PIVOT Col1", 1),, 9^9)), "×")), " ", ","), 2, 0), ",")), 1))
It gives me an error "Did not find value '' in VLOOKUP evaluation", I figured out that the problem is only in VLOOKUP when I change $B2 to $B2:$B.
I'm sure VLOOKUP works with ArrayFormula, I fail to understand where my formula is going wrong! Please help me correct my ArrayFormula.
...ANSWER
Answered 2021-Jun-14 at 20:45I have answered you on the tab in your shared sheet called My Practice thusly:
You cannot split a two column array as you have attempted to do in cell CI2. That is why your formula does not work. You can only split a ONE column array.
I understand you are trying to learn, but attempting to use complicated formulas like that is going to make it harder I'm afraid.
QUESTION
I am having issues with my eBAY Scraper and can not work out why. Although it is pulling the data off fine, it misses SOME of the data OFF for the first row and then for each first row of every Loop and therefore the data is not in the correct row.
Q) Why is it missing the data at the start and then for each loop?
I think It may have something to do with the title extracting slower that the rest of the items, however I can not work it out as I am very limited with vba. I have attached a demo, for your viewing.
I am not looking for a full rewite of the code, just pointing in the right direction or a SLIGHT change to MY code. As I stated I and very limited in vba, I can understand my code, anything more advanced will be out of my depth.
Demo Download - Download Excel File
WebSite - Ebay.co.uk
Ebay Product Page - Prodcts Shown may vary browser to browser
I have colour coded it so you can see better
For some reason it misses out Price, Condition, Former Price & Discount for the first item on start and EVERY Loop. For every loop that it misses the items out the Price, Condition, Former Price & Discount become MORE out of line
1st Loop - Items are NOW 2 rows out of line
2nd Loop - Items are NOW 3 rows out of line
As I searched 3 pages (2 pages + 1 extra) and it looped 3 time it has missed the first row on each loop. I am 3 rows out. I think this may have too do with the Title of the item as it extracts a bit slower then the rest of the items
This is my code
...ANSWER
Answered 2021-Jun-14 at 19:47Make sure to skip the first element within your returned collection. Keeping to your code.
QUESTION
I have these data in my booked_tickets table:
1st Row: A1, A3, B2
2nd Row: C3, D2, A2
3rd Row: C1, A2, D1
When I tried to concatenate these data into one string, I get this: A1, A3, B2C3, D2, A2C1, A2, D1
What I wanted is: A1, A3, B2, C3, D2, A2, C1, A2, D1
How do I concatenate like that?
...ANSWER
Answered 2021-Jun-14 at 16:54I think you need to update this line
$updateBookedSeats = $updateBookedSeats.$row['selected_bus_seats'];
With additional ,
at end like:
$updateBookedSeats = $updateBookedSeats.$row['selected_bus_seats'].',';
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