prime-factorization | Prime Factorization
kandi X-RAY | prime-factorization Summary
kandi X-RAY | prime-factorization Summary
Prime Factorization (2d space hit algorithm).
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QUESTION
Given a number n
and a list of divisors A
, how can I efficiently find all the combinations of divisors that, when multiplied, yield to the number?
e.g.
...ANSWER
Answered 2020-Oct-01 at 18:44Rather than using memoization, you can split the problem into a recursive portion to find all the unique combinations, and a portion to find the combinations of each arrangement. That should cut down your search space considerably and only permute the options that will actually work.
To accomplish this, A
should be sorted.
Part 1:
Do a DFS on the graph of possible factorizations that are available. Truncate the search down redundant branches by only selecting orderings in which each factor is greater than or equal to its predecessor. For example:
QUESTION
I have a code challenge that asks us to create 3 functions using the previous function. We are using "base python" so no imports. Versions without lambdas would be ideal, but both are welcome.
find_factors
functionis_prime
function - using thefind_factors
functionhcf
function - using theis_prime
function
The first two functions return the factors and prime numbers and the is_prime
function is using the find_factors
function as our instructor asked.
ANSWER
Answered 2020-May-17 at 15:00Let's say, your find_factors
return all the divisor of a number. Then, you can just check the all common divisor for both x
and y
, and take the max that would be the divisor. Technically, you don't need the is_prime
function.
For example,
If we have 12, and 4. Let's find the factors first. We will get them in a sorted manner from find_factors.
12 has factors: 1, 2, 3, 4, 6, 12
4 has factors: 1, 2, 4
possible solution set = [1, 2, 4] (the common ones only)
GCD or greatest common divisor will be only the maximum common number from both lists. So, the answer is 4.
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