memoization | A library with memoize functions for .NET
kandi X-RAY | memoization Summary
kandi X-RAY | memoization Summary
A library with memoize functions for .NET.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of memoization
memoization Key Features
memoization Examples and Code Snippets
Community Discussions
Trending Discussions on memoization
QUESTION
I created a function to memoize context values and return them as render props in React to avoid re-rendering when values change that I do not care about. (which works so thats great!) However, I am having trouble typing it.
The goal is to have the children function have the same type as the return type of accessor.
The part I am having a lot of trouble with is typing this part:
...ANSWER
Answered 2022-Mar-22 at 00:45You can make it work by adding an explicit type signature to the accessor
prop function argument: ctx
~> ctx: ContextType
.
QUESTION
As the question states, I am trying to solve a leetcode problem. The solutions are available online but, I want to implement my own solution. I have built my logic. Logic is totally fine. However, I am unable to optimize the code as the time limit is exceeding for the large numbers.
Here's my code:
...ANSWER
Answered 2022-Mar-15 at 09:42Actually, you do not store a value, but NaN
to the array.
You need to return zero to get a numerical value for adding.
Further more, you assign in each call a new value, even if you already have this value in the array.
A good idea is to use only same types (object vs number) in the array and not mixed types, because you need a differen hndling for each type.
QUESTION
take
...ANSWER
Answered 2022-Mar-11 at 09:54The issue is that, by default, Dictionary
uses reference equality to check whether an object is in the dictionary. This means that it will only work if you pass it the same array instance. The following gets the value from the cache:
QUESTION
I was solving a recursive problem in haskell, although I could get the solution I would like to cache outputs of sub problems since has over lapping sub-problem property.
The question is, given a grid of dimension n*m
, and an integer k
, how many ways are there to reach the gird (n, m) from (1, 1) with not more than k change of direction?
Here is the code without of memoization
...ANSWER
Answered 2021-Dec-16 at 16:23In Haskell these kinds of things aren't the most trivial ones, indeed. You would really like to have some in-place mutations going on to save up on memory and time, so I don't see any better way than equipping the frightening ST
monad.
This could be done over various data structures, arrays, vectors, repa tensors. I chose HashTable
from hashtables because it is the simplest to use and is performant enough to make sense in my example.
First of all, introduction:
QUESTION
As a toy example, let's use the Fibonacci sequence:
...ANSWER
Answered 2022-Jan-02 at 14:24To describe something as "a callable with a memory attribute", you could define a protocol (Python 3.8+, or earlier versions with typing_extensions
):
QUESTION
I've written a program to benchmark two ways of finding "the longest Collatz chain for integers less than some bound".
The first way is with "backtrack memoization" which keeps track of the current chain from start till hash table collision (in a stack) and then pops all the values into the hash table (with incrementing chain length values).
The second way is with simpler memoization that only memoizes the starting value of the chain.
To my surprise and confusion, the algorithm that memoizes the entirety of the sub-chain up until the first collision is consistently slower than the algorithm which only memoizes the starting value.
I'm wondering if this is due to one of the following factors:
Is Python really slow with stacks? Enough that it offsets performance gains
Is my code/algorithm bad?
Is it simply the case that, statistically, as integers grow large, the time spent revisiting the non-memoized elements of previously calculated Collatz chains/sub-chains is asymptotically minimal, to the point that any overhead due to popping elements off a stack simply isn't worth the gains?
In short, I'm wondering if this unexpected result is due to the language, the code, or math (i.e. the statistics of Collatz).
...ANSWER
Answered 2021-Dec-25 at 03:18There is a tradeoff in your code. Without the backtrack memoization, dictionary lookups will miss about twice as many times as when you use it. For example, if maxNum = 1,000,000
then the number of missed dictionary lookups is
- without backtrack memoization: 5,226,259
- with backtrack memoization: 2,168,610
On the other hand, with backtrack memoization, you are constructing a much bigger dictionary since you are collecting lengths of chains not only for the target values, but also for any value that is encountered in the middle of a chain. Here is the final length of collatzDict
for maxNum = 1,000,000
:
- without backtrack memoization: 999,999
- with backtrack memoization: 2,168,611
There is a cost of writing to this dictionary that many more times, popping all these additional values from the stack, etc. It seems that in the end, this cost outweighs the benefits of reducing dictionary lookup misses. In my tests, the code with backtrack memoization run about 20% slower.
It is possible to optimize backtrack memoization, to keep the dictionary lookup misses low while reducing the cost of constructing the dictionary:
- Let the stack consist of tuples
(n, i)
wheren
is as in your code, andi
is the length of the chain traversed up to this point (i.e.i
is incremented at every iteration of thewhile
loop). Such a tuple is put on the stack only ifn < maxNum
. In addition, keep track of how long the whole chain gets before you find a value that is already in the dictionary (i.e. of the total number of iterations of thewhile
loop). - The information collected in this way will let you construct new dictionary entries from the tuples that were put on the stack.
The dictionary obtained in this way will be exactly the same as the one constructed without backtrack memoization, but it will be built in a more efficient way, since a key n
will be added when it is first encountered. For this reason, dictionary lookup misses will be still much lower than without backtrack memoization. Here are the numbers of misses I obtained for maxNum = 1,000,000
:
- without backtrack memoization: 5,226,259
- with backtrack memoization: 2,168,610
- with optimized backtrack memoization: 2,355,035
For larger values of maxNum
the optimized code should run faster than without backtrack memoization. In my tests it was about 25% faster for maxNum >= 1,000,000
.
QUESTION
I have a complex nested dictionary structured like this:
...ANSWER
Answered 2021-Nov-05 at 09:13I was able to get about 25 % faster by combining the three processes.
QUESTION
I am trying to wrap my head around memoization using c++, and I am trying to do an example with the "golom sequence"
...ANSWER
Answered 2021-Nov-01 at 14:29int golomS(int n, std::unordered_map golomb)
{
if(n == 1)
{
return 1;
}
if(!golomb[n])
{
golomb[n] = 1 + golomS(n - golomS(golomS(n - 1, golomb), golomb), golomb);
}
return golomb[n];
}
QUESTION
The question is: "You are climbing a staircase. It takes n steps to reach the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?"
The code of Top-down memoization approach is:
...ANSWER
Answered 2021-Nov-02 at 17:46The first return statement is inside an if
condition, and it returns a value when it's already computed, in order to not compute 2 or more times the same operation.
QUESTION
I try to use raiseUnder
(with polysemy 1.6.0) to introduce effects to use other interpreters, such that:
ANSWER
Answered 2021-Oct-25 at 19:27As mentioned by @Georgi Lyubenov, the issue was that my function f
, in runMemoizationState
, neededthe State
effect, once decoupled, it works:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install memoization
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page