Halve | Stylish Two-Column Jekyll Theme | Theme library

by TaylanTatli CSS Version: Current License: MIT

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kandi X-RAY | Halve Summary

Halve is a CSS library typically used in User Interface, Theme, Jekyll applications. Halve has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

This theme is Jekyll port of vangeltzo.com (by Vangelis Tzortzis). To learn how to install and use this theme check out the installation guide for more information. If you have a question, find a bug, or just want to say hi, please open an issue on GitHub.

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Halve has a low active ecosystem.

It has 287 star(s) with 360 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

There are 24 open issues and 23 have been closed. On average issues are closed in 3 days. There are 9 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of Halve is current.

Quality

Halve has no bugs reported.

Security

Halve has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

Halve is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

Halve releases are not available. You will need to build from source code and install.

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Community Discussions

Trending Discussions on Halve

When splitting strings in a list, Python only prints vertically

Rounding a rational number to the nearest integer, with half-up

My binary recursion function to find the max value

Binary search complexity analysis (Uneven Split)

Go missing returns are driving me crazy

Higher-order function

MergeSort in python

Segfault in C (during middle of for loops)

VBA: Copying a row, inserting it above with one cell's value changed

Error when trying to implement MERGE algorithm merging to sorted lists of integers in python?

QUESTION

When splitting strings in a list, Python only prints vertically

Asked 2021-Jun-12 at 16:48

I cut each string in my list in half. I would like to print each half separately, however, when I go to print the first half of the string "have" which is "ha," it prints every first letter in each of my halves. Does anyone know the reason for this?

...

ANSWER

Answered 2021-Jun-12 at 15:38

first[0] will print the first letter in the first half of your string. So if you have have and you cut this in half first = ha-second = ve. first[0] will give you h. So I assume you want to print ha - ve

Source https://stackoverflow.com/questions/67950339

QUESTION

Rounding a rational number to the nearest integer, with half-up

Asked 2021-Jun-12 at 10:03

Given a rational number, I need to get the nearest integer, with exact halves rounded up (that is, towards positive infinity). The results must be exact, which rules out float and Decimal, both of which have finite precision.

The following code works perfectly in all cases except for negative numbers:

...

ANSWER

Answered 2021-Jun-11 at 23:26

In roundhalfup, replace int(...) with math.floor(...):

Source https://stackoverflow.com/questions/67944241

QUESTION

My binary recursion function to find the max value

Asked 2021-Jun-11 at 02:00

I am still learning recursion principles and trying to write a function which returns max of all values in an array by recursive calls with lower and upper halves of the array.

I know i would need to find the mid point then split the list in two then recall the function to continue doing until each list is at length 1. I am just confused how to continue from there.

Any help is appreciated.

My function:

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ANSWER

Answered 2021-Jun-11 at 02:00

You were almost there, there were two mistake in code. The first is if condition if len(Left)> 1: and if len(Right)> 1: Those are not really needed. Infact they might even prevent you from reaching base case. The base case handles if the length of list reaches less than 1.

The other was merging the solution from left and right. From left sublist you know 6 is biggest number while in right sublist, you know that 8 is biggest number. These number will be retuned recursively calling bin_max(input_list). So you should then compare the output from left and right to get the biggest element in list.

Source https://stackoverflow.com/questions/67930278

QUESTION

Binary search complexity analysis (Uneven Split)

Asked 2021-Jun-09 at 06:30

Design a search algorithm that divides a sorted array into one third and two thirds instead of two halves as in binary search algorithm “BinSrch”. Analyze the time complexity of the algorithm.

I am done with writing the algorithm , need help with the complexity analysis part , could someone please explain what the recurrence relation will look like ?

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ANSWER

Answered 2021-Jun-09 at 06:30

If this were a regular binary search, the worst time complexity would be achieved if your desired element would be the last one remaining in the array after cutting half of the array each iteration. The answer to the question "how many times can I divide this array in half until it has 1 element left" is log(n) with a base of 2 - henceforth log2(n). That's why the time complexity for the regular bin search is log2(n).

The same logic can be applied for your case. You again need to prolong the search as much as possible, and that would happen if each iteration you go with the bigger part of the array - the 2/3rd part - because that would cause it to decrease in size slowest. So, how many times can you cut the remainder of the array to two-thirds until it has 1 element remaining? Again log(n) but this time with a base of 1.5 - log1.5(n).

Lastly, remember from logarithm rules that for known bases a,b: loga(n) = logb(n) * loga(b), so in our case log1.5(n) = log2(n) * log1.5(2) That 3rd part is a constant, so our efficiency is the same as the regular binary search efficiency, only multiplied by some constant - which keeps it a time complexity of log(n). Long story short, the base doesn't matter.

Source https://stackoverflow.com/questions/67894737

QUESTION

Go missing returns are driving me crazy

Asked 2021-Jun-08 at 12:59

I'm trying to learn Go and it's going very well except for the functions return statements, which I cannot for my life get a grasp on. In an exercise in a book it is proposed to construct a function that halves an int and return the halved int and if even or odd (the halved) with a bool. No problems with that, here is the relevant code.

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ANSWER

Answered 2021-Jun-08 at 12:33

There is no guarantee checker() gets more than zero arguments, in which case the loop body would be executed zero times, so no return statements would be reached.

So the compiler is rightful to complain about a missing return, as this condition is decided at runtime.

E.g. if you pass 0 arguments: checker(), it's valid and would cause problem if a return would not be demanded.

So simply add a return statement with reasonable return values, often the zero values of the result types:

Source https://stackoverflow.com/questions/67886478

QUESTION

Higher-order function

Asked 2021-Jun-04 at 17:48

I have an exercise about JavaScript. This exercise requires me to use higher-order functions. I have managed to specify some of the functions so far, but when I try to execute the code, the result does not seem to work properly. I have some images to give you an idea, hopefully, you can help me correct this.

The thread is: Write the function loop(loops, number, func), which runs the given function the given number of times. Also write the simple functions halve() and square().
This is my code:

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ANSWER

Answered 2021-Jun-04 at 15:28

Here's one way

Source https://stackoverflow.com/questions/67839766

QUESTION

MergeSort in python

Asked 2021-Jun-02 at 07:25

def get_random_array(n):
    return [random.randint(0, 10000) for _ in range(n)]

def test_sorting_algorithm(algorithm):
    for _ in range(100):
        A = get_random_array(random.randint(0, 1000))
        A_sorted = algorithm(A)
        assert A_sorted == sorted(A), "FAIL!"


def merge(A,l,m,r):

    i = l
    j = m+1
    new = []

    while i <= m and j <= r:
        if A[i] <= A[j]:
            new.append(A[i])
            i += 1
        else:
            new.append(A[j])
            j += 1

    while i <= m:
        new.append(A[i])
        i += 1
   
    while j <= r:
        new.append(A[j])
        j += 1

    return new


def mergeSort_rec(A, l, r): 


    if l < r:       
        m = (l+(r-1))//2  # Same as (l+r)//2, but avoids overflow for large l and h 
        # Sort first and second halves 
        mergeSort_rec(A, l, m) 
        mergeSort_rec(A, m+1, r)                                 
        merge(A, l, m, r) 

def mergeSort(B):
    A = B[:] # Copy the array just because we decided to return a sorted copy of the original array 
    mergeSort_rec(A, 0, len(A)-1)
    return A

A = get_random_array(10)

test_sorting_algorithm(mergeSort)

...

ANSWER

Answered 2021-Jun-02 at 07:25

This statement doesn't make sense:

Source https://stackoverflow.com/questions/67797134

QUESTION

Segfault in C (during middle of for loops)

Asked 2021-May-28 at 20:24

I'm trying to practice C by writing a memory-type card game. The game is compiled by gcc on ARMv8. The user enters a number "users_N" in the argument line and a board of cards is created size: 2N x 2N.

The program runs just fine when the number is 1 or 2. But if it's 3 or bigger, I get a segmentation fault when trying to initialize the board. I thought this meant it was a stack overflow, but I increased the stack size to unlimited on my SSH and the problem was not resolved. I don't think it's a problem with pointers or trying to access an array out-of-bounds either, as it runs just fine until after 10 cards are added to the array.

The print statements are just to determine exactly when the segfault occurs.See image of for loop segfault

EDIT: to add more context... I know it's a bit messy, sorry!

...

ANSWER

Answered 2021-May-26 at 03:28

Allocation of your board is wrong:

Source https://stackoverflow.com/questions/67697952

QUESTION

VBA: Copying a row, inserting it above with one cell's value changed

Asked 2021-May-26 at 15:33

I'm trying to find a way to copy the values of an identified row and insert it above with the same values except for one column. If possible, it would be great to find a way to change 2 cells in the identified row too. I'm completely new in trying to use VBA so I haven't gotten very far... currently I can insert a blank row, but with no contents. Hopefully to make it clearer, here are the steps I'm trying to complete.

In column C, work through each row and identify/action each one that contains "ITEM1_ITEM2"
Insert row above (or below?) the identified row containing all the same values, except for column C, which has the value changed to "ITEM2", and column H, which has its number value halved.
The identified row has its column C value changed to "ITEM1" and its column H value is halved as well.
Move on to the next identified row with "ITEM1_ITEM2" and complete the same.

Any help would be appreciated. I don't even need to complete all the steps... even just figuring out how to just copy/paste the cells in inserted row would help. Thanks!

...

ANSWER

Answered 2021-May-26 at 15:33

This would work:

Source https://stackoverflow.com/questions/67707319

QUESTION

Error when trying to implement MERGE algorithm merging to sorted lists of integers in python?

Asked 2021-May-23 at 12:39

I'm new to both algorithms AND programming.

As an intro to the MERGE algorithms the chapter introduces first the MERGE algorithm by itself. It merges and sorts an array consisting of 2 sorted sub-arrays.

I did the pseudocode on paper according to the book:

Source: "Introduction to Algorithms Third Edition" Thomas H. Cormen Charles E. Leiserson Ronald L. Rivest Clifford Stein

Since I am implementing it in python3 I had to change some lines given that indexing in python starts at 0 unlike in the pseudocode example of the book.

Keep in mind that the input is one array that contains 2 SORTED sub-arrays which are then merged and sorted, and returned. I kept the prints in my code, so you can see my checks...

...

ANSWER

Answered 2021-May-23 at 11:46

As r is the index of the last value in arr, you need to add one to it to make a range that also includes that final index:

Source https://stackoverflow.com/questions/67659246

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