spaced-out | A three dimensional CSS3 Sidebar | Theme library

I want the arranged subviews of a stack view to become visible in a cascaded manner, but they're all appearing at the same time:

I'm looking for a way to extract evenly spaced elements in a vector. I'd like a general way to do this because I am trying to specify the values that I want in a plotly chart. I tried using pretty but that only seems to work with ggplot2.

I'm pretty much looking for an R version of this question that was answered for python.

Here's a sample set. This sample is a vector of 23 elements, a prime that cannot be factored.

I am using JQuery to create a custom slideshow-layout and I am working on code that will

1. Calculate the width of the screen
2. Subtract the width of the images
3. Set the left margin to 1/3 of the difference between the width of the screen and images

The images seem to line up but chop off for the last of the 3 images. I am trying to make this dynamic so that it will make a spaced-out layout for any amount of images. Am I going about this all wrong? Also, is the space between inline-block elements setting it off?

For a vulgarization graph, I am comparing different proportion for several overlapping groups (stupid example: man and woman and small / tall).

By default, obviously, all x ticks are evenly spaced-out.

For clearer visualization, man and woman should be close together while further from small and tall (which should be close also).

The following code gets the number of words:

Given a Python string, I want to wide-space occurrences of a given word substring inside the string sentence of a given range. I couldn't find an efficient and neat way to perform this algorithm.

I want to wide-space only words with indices within a given range of the sentence string, and the word must be exact (not surrounded by other word characters such as letters and digits). Punctuation and other symbols are ignored when counting word exactness.

So far, my function widespace(sentence, word, start = None, end = None): should wide-space a given word within a given range from start to end, but currently it looks quite inefficient and verbose. It also cannot detect exact word matches and ignore punctuation.

Expected results

1. All occurrences of the word will be affected if it is within range(start, end), that means, index greater or equal than start, strictly less than end.
2. The exact match ignores punctuation, but is case sensitive. For example, if you want to match "omg", it accepts "omg!", and "omg,", but it does not accept "omg" surrounded by other word characters, such as "zomg" or "omgf"
   • Word characters can include numbers, letters, hyphens, it is your preference.
3. widespace("Foo, Bar, Baz!", "Baz") becomes Foo, Bar, B a z!
   • The index is 10.
4. widespace("Foo, Foo, Foo!", "Foo") becomes F o o, F o o, F o o!
   • The indices are 0, 5, 10.
5. widespace("Foo, Foo, Foo!", "Foo", start = 0, end = 2) becomes
   F o o, Foo, Foo!
   • The indices are 0, 5, 10. Only the first one (index 0) gets affected.
6. widespace("Foo, Foo, Foo!", "Foo", start = 0, end = 5) becomes
   F o o, Foo, Foo! like the previous example
   • the indices are 0, 5, 10. Only the first one (index 0) gets affected since the second one exactly matches 5, which is out of range.
7. widespace("Foo, Foo, Foo!", "Foo", start = 0, end = 6) becomes
   F o o, F o o, Foo!
   • the indices are 0, 5, 10. Only the first two gets matched.
8. widespace("Mulliganaceous Mulligan, OMG", "Mulligan") should become
   Mulliganaceous M u l l i g a n, OMG"
   • "Mulliganaceous" is not an exact match. But "Mulligan," counts as one because it is not surrounded by other word characters.
   • I currently have M u l l i g a naceous M u l l i g a n

Current code

As of now, I got it working, but the code is quite long, possibly inefficient, and cannot deal with exact matches and punctuation marks.