lit | World 's smallest responsive 🔥 css framework | Theme library
kandi X-RAY | lit Summary
kandi X-RAY | lit Summary
a ridiculously small responsive css framework. I challenged myself to see how small I could go, but preserve everything Skeleton, Milligram, and other micro frameworks have to offer.
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Trending Discussions on lit
QUESTION
Is it possible to add an aggregate conditionally in Spark Scala?
I would like to DRY out the following code by conditionally adding collect_set
Example:
...ANSWER
Answered 2022-Mar-26 at 22:04You can store the aggreate columns in a sequence and alter the sequence as required:
QUESTION
Update: the root issue was a bug which was fixed in Spark 3.2.0.
Input df structures are identic in both runs, but outputs are different. Only the second run returns desired result (df6
). I know I can use aliases for dataframes which would return desired result.
The question. What is the underlying Spark mechanics in creating df3
? Spark reads df1.c1 == df2.c2
in the join
's on
clause, but it's evident that it does not pay attention to the dfs provided. What's under the hood there? How to anticipate such behaviour?
First run (incorrect df3
result):
ANSWER
Answered 2021-Sep-24 at 16:19Spark for some reason doesn't distinguish your c1
and c2
columns correctly. This is the fix for df3
to have your expected result:
QUESTION
Question in short
To have a proper input for pycosat, is there a way to speed up calculation from dnf to cnf, or to circumvent it altogether?
Question in detail
I have been watching this video from Raymond Hettinger about modern solvers. I downloaded the code, and implemented a solver for the game Towers in it. Below I share the code to do so.
Example Tower puzzle (solved):
...ANSWER
Answered 2022-Mar-19 at 22:23First, it's good to note the difference between equivalence and equisatisfiability. In general, converting an arbitrary boolean formula (say, something in DNF) to CNF can result in a exponential blow-up in size.
This blow-up is the issue with your from_dnf
approach: whenever you handle another product term, each of the literals in that product demands a new copy of the current cnf clause set (to which it will add itself in every clause). If you have n product terms of size k, the growth is O(k^n)
.
In your case n
is actually a function of k!
. What's kept as a product term is filtered to those satisfying the view constraint, but overall the runtime of your program is roughly in the region of O(k^f(k!))
. Even if f grows logarithmically, this is still O(k^(k lg k))
and not quite ideal!
Because you're asking "is this satisfiable?", you don't need an equivalent formula but merely an equisatisfiable one. This is some new formula that is satisfiable if and only if the original is, but which might not be satisfied by the same assignments.
For example, (a ∨ b)
and (a ∨ c) ∧ (¬b)
are each obviously satisfiable, so they are equisatisfiable. But setting b
true satisfies the first and falsifies the second, so they are not equivalent. Furthermore the first doesn't even have c
as a variable, again making it not equivalent to the second.
This relaxation is enough to replace this exponential blow-up with a linear-sized translation instead.
The critical idea is the use of extension variables. These are fresh variables (i.e., not already present in the formula) that allow us to abbreviate expressions, so we don't end up making multiple copies of them in the translation. Since the new variable is not present in the original, we'll no longer have an equivalent formula; but because the variable will be true if and only if the expression is, it will be equisatisfiable.
If we wanted to use x
as an abbreviation of y
, we'd state x ≡ y
. This is the same as x → y
and y → x
, which is the same as (¬x ∨ y) ∧ (¬y ∨ x)
, which is already in CNF.
Consider the abbreviation for a product term: x ≡ (a ∧ b)
. This is x → (a ∧ b)
and (a ∧ b) → x
, which works out to be three clauses: (¬x ∨ a) ∧ (¬x ∨ b) ∧ (¬a ∨ ¬b ∨ x)
. In general, abbreviating a product term of k literals with x
will produce k binary clauses expressing that x
implies each of them, and one (k+1)
-clause expressing that all together they imply x
. This is linear in k
.
To really see why this helps, try converting (a ∧ b ∧ c) ∨ (d ∧ e ∧ f) ∨ (g ∧ h ∧ i)
to an equivalent CNF with and without an extension variable for the first product term. Of course, we won't just stop with one term: if we abbreviate each term then the result is precisely a single CNF clause: (x ∨ y ∨ z)
where these each abbreviate a single product term. This is a lot smaller!
This approach can be used to turn any circuit into an equisatisfiable formula, linear in size and in CNF. This is called a Tseitin transformation. Your DNF formula is simply a circuit composed of a bunch of arbitrary fan-in AND gates, all feeding into a single arbitrary fan-in OR gate.
Best of all, although this formula is not equivalent due to additional variables, we can recover an assignment for the original formula by simply dropping the extension variables. It is sort of a 'best case' equisatisfiable formula, being a strict superset of the original.
To patch this into your code, I added:
QUESTION
The final result is sorted on column 'timestamp'. I have two scripts which only differ in one value provided to the column 'record_status' ('old' vs. 'older'). As data is sorted on column 'timestamp', the resulting order should be identic. However, the order is different. It looks like, in the first case, the sort is performed before the union, while it's placed after it.
Using orderBy
instead of sort
doesn't make any difference.
Why is it happening and how to prevent it? (I use Spark 3.0.2)
Script1 (full) - result after 4 runs (builds):
...ANSWER
Answered 2022-Mar-16 at 09:15As it turns out, this behavior is not caused by @incremental
. It can be observed in a regular transformation too:
QUESTION
Good morning everyone,
I have a text file containing multiple lines. I want to find a regular pattern inside it and print its position using grep.
For example:
...ANSWER
Answered 2022-Mar-12 at 12:19Awk suites this better:
QUESTION
I have a data frame like below in pyspark
ANSWER
Answered 2022-Feb-15 at 05:08Use the instr
function to determine whether the rust
column contains _
, and then use the when
function to process.
QUESTION
I'm trying to understand behaviour differences between pyspark.sql.currenttimestamp() and datetime.now()
If I create a Spark dataframe in DataBricks using these 2 mechanisms to create a timestamp column, everything works nicely as expected....
...ANSWER
Answered 2022-Feb-12 at 21:44current_timestamp()
returns a TimestampType column, the value of which is evaluated at query time as described in the docs. So that is 'computed' each time your callshow
.
Returns the current timestamp at the start of query evaluation as a TimestampType column. All calls of current_timestamp within the same query return the same value.
- Passing this column to a
lit
call doesn't change anything, if you check the source code you can seelit
simply returns the column you called it with.
return col if isinstance(col, Column) else _invoke_function("lit", col)
- If you cal
lit
with something else than a column, e.g. a datetime object then a new column is created with this literal value. The literal being the datetime object returned from datetime.now(). This is a static value representing the time the datetime.now function was called.
QUESTION
As per my business logic week start day is monday and week end day is sunday
I want to get week end date which is sunday based on week number , some year has 53 weeks , it is not working for 53rd week alone
Expected value for dsupp_trans_dt is 2021-01-03
but as per below code it is null
...ANSWER
Answered 2021-Aug-20 at 10:36The documentation for weekofyear
spark function has the answer:
Extracts the week number as an integer from a given date/timestamp/string. A week is considered to start on a Monday and week 1 is the first week with more than 3 days, as defined by ISO 8601.
It means that every year actually has 52 weeks plus n
days, where n < 7
.
For that reason, to_date
considers 53/2020
as an incorrect date and returns null
. For the same reason, to_date
considers 01/2020
as invalid date because 01/2020
is actually 53th
week of 2019
year.
QUESTION
I want to get raw string of css in npm module through vite.
According to vite manual,
https://vitejs.dev/guide/assets.html#importing-asset-as-string
It says we can get raw string by putting "?raw" at the end of identifier.
So I try this:
import style from "swiper/css/bundle?raw";
But this shows error like:
[vite] Internal server error: Missing "./css/bundle?raw" export in "swiper" package
If I use this:
import style from "swiper/css/bundle";
There are no error, but css is not just load as string but handled as bundle css.
This is not good, because I want to use this css in my lit-based web components.
Are there any way to get css as raw string through vite?
ANSWER
Answered 2022-Feb-05 at 11:04Evan You (Vite.js and Vue.js creator) has added the inline
toggle which fixes the problem of styles also being added to the main CSS bundle when importing.
QUESTION
I am parsing an EDI file in Azure Databricks. Rows in the input file are related to other rows based on the order in which they appear. What I need is a way to group related rows together.
...ANSWER
Answered 2022-Feb-01 at 13:54You can use conditional sum aggregation over a window ordered by sequence
like this:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install lit
Install lit.css with one of the following:
NPM: npm install --save @ajusa/lit
CSS3: <link rel="stylesheet" href="https://cdn.jsdelivr.net/npm/@ajusa/lit@latest/dist/lit.css" />
CSSNext: <link rel="stylesheet" href="https://cdn.jsdelivr.net/npm/@ajusa/lit@latest/src/lit.css" />
Read the Docs to see usage
Clone this repository (https://www.github.com/ajusa/lit)
Make sure you have npm installed
Run npm install in the root directory of lit
Once that is completed, run npm run build to build the minified version and the gzipped file.
If you are making changes live, use npm run watch. watch will build the minified css file in ./dist whenever there is a change in ./src/lit.css.
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