Docter | Get that restaurant github flavor at home in your editor

by alampros CSS Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | Docter Summary

Docter is a CSS library. Docter has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Get that restaurant github flavor at home in your editor.

Support

Quality

Security

License

Reuse

Support

Docter has a low active ecosystem.

It has 137 star(s) with 26 fork(s). There are 4 watchers for this library.

It had no major release in the last 6 months.

There are 4 open issues and 3 have been closed. On average issues are closed in 237 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Docter is current.

Quality

Docter has 0 bugs and 0 code smells.

Security

Docter has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Docter code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Docter does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

Docter releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

It has 274 lines of code, 5 functions and 3 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

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Docter Key Features

No Key Features are available at this moment for Docter.

Docter Examples and Code Snippets

No Code Snippets are available at this moment for Docter.

Community Discussions

Trending Discussions on Docter

Sorting dataframe with 1 column

QUESTION

Sorting dataframe with 1 column

Asked 2021-Dec-14 at 05:02

I have a data frame of names which has 1 column. I have tried multiple iterations of order() and have also converted it to a list and tried sort() in a few different ways, with no luck.

Below is dput() for reference:

...

ANSWER

Answered 2021-Dec-14 at 04:39

You need to specify which column is to be ordered/sorted even if the data frame contains only one column.

If you want to preserve the original order of names.ordered use order to create an index:

Source https://stackoverflow.com/questions/70343783

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Docter

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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