jo | candy shell for making HTML5 apps

by davebalmer CSS Version: 0.5.1 License: MIT

X-Ray Key Features Code Snippets(1)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | jo Summary

jo is a CSS library. jo has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Jo (0.5.0) is a thin (~16K) candy shell for making HTML5 apps. Jo works with: PhoneGap, Chrome, Safari, Opera, FireFox, iOS, Android, BlackBerry 10, Tizen, & Windows Phone 8+. Features include skinnable UI widgets, a clean event model and a light data layer.

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Quality

Security

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Support

jo has a medium active ecosystem.

It has 1214 star(s) with 187 fork(s). There are 42 watchers for this library.

It had no major release in the last 12 months.

There are 26 open issues and 45 have been closed. On average issues are closed in 344 days. There are 3 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of jo is 0.5.1

Quality

jo has no bugs reported.

Security

jo has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

jo is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

jo releases are available to install and integrate.

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jo Key Features

No Key Features are available at this moment for jo.

jo Examples and Code Snippets

Preprocess name .

python

Lines of Code : 63

License : No License

Copy

def preprocess_names(name, output_sep=' ', firstname_output_letters=1):
    """
    Function that outputs a person's name in the format 
     (all lowercase)
    
    >>> preprocess_names("Samuel Eto'o")
    'etoo s'
   
    >>> pre

Community Discussions

Trending Discussions on jo

Autofilling Django model form field with data from associated objects

Used for loop to print the row count of the array then data duplicates base on length of my array, how do I print only 1 line of data in Python?

Changing some values in df column based on another

Read below JSON data and fetch status name

R markdown can't knit

toggle menu button works on index page but not on other pages despite identical code- why?

How do I do a drag and drop using jQuery to move data between two or more divs and then trigger an update to the db on the drop?

Trying to overload operator<< in template class

Search in a string literal with a table field with peewee ORM

Error when inserting Hungarian text characters

QUESTION

Autofilling Django model form field with data from associated objects

Asked 2021-Jun-14 at 14:32

I have a model form that creates a new job entry, and on submission, I need an invisible field job_time_estimation to be set to a sum of 'service_stats_estimate_duration' values from ServiceItemStats objects associated with the JobEntry by a many-to-many relationship when submitting the form.

For example, if in my NewJobEntryForm I chose two existing ServiceItemStats objects that have service_stats_estimate_duration values 60 and 90, on submission, I want a value 150 to be saved in that JobEntry object's job_time_estimation attribute.

I tried doing this using aggregation by defining a save() method in the model but I am getting an error "name 'serviceItemStats' is not defined".

I am not sure if I am going about this the right way. Any help would be appreciated.

My code:

models.py:

...

ANSWER

Answered 2021-Jun-14 at 14:32

You can try this.

Source https://stackoverflow.com/questions/67971417

QUESTION

Used for loop to print the row count of the array then data duplicates base on length of my array, how do I print only 1 line of data in Python?

Asked 2021-Jun-13 at 04:38

How do I print only 1 copy of data? I am a complete beginner. This is Python code I did for Add data.

This is my current output:

...

ANSWER

Answered 2021-Jun-13 at 02:32

For each entry in zip(name, age, grade), you have another nested loop (for w). This causes the program to print multiple rows per entry. One way to solve it is to include w inside the zip; i.e., replacing

Source https://stackoverflow.com/questions/67954317

QUESTION

Changing some values in df column based on another

Asked 2021-Jun-13 at 04:04

I have a df with multiple columns and values. Say:

ID Name Cost 123 Jo $10 345 Bella $20 567 IgnoreMe $5000

I also have a defined list of names to ignore. In this example, it contains one value, but it can have more.

names_to_ignore = ['ignoreme']

The goal is to replace all cost values with null when Name is in the ignore list.

I tried:

...

ANSWER

Answered 2021-Jun-13 at 04:00

Try:

Source https://stackoverflow.com/questions/67954722

QUESTION

Read below JSON data and fetch status name

Asked 2021-Jun-09 at 12:57

I want to get the name of the status from JSON data. { "expand": "renderedFields,names,schema,operations,editmeta,changelog,versionedRepresentations", "id": "3876562", "self": "https://jira2.abc.com/rest/api/2/issue/3876562", "key": "DEVACDMY-35289", "fields": { "status": { "self": "https://jira2.abc.com/rest/api/2/status/3", "description": "", "iconUrl": "https://jira2.abc.com/images/icons/statuses/inprogress.png", "name": "In Progress", "id": "3", "statusCategory": { "self": "https://jira2.abc.com/rest/api/2/statuscategory/4", "id": 4, "key": "indeterminate", "colorName": "yellow", "name": "In Progress" } } } } I try this but it doesn't work.

...

ANSWER

Answered 2021-Jun-09 at 12:48

Looking at the json, it is not an array, it is simply a JsonObject and to get the string of the status name you need to traverse the same way.

To get the status name there is a hierarchy that you need to follow

JSONObject --> fields*(this is again a JSONObject)* --> status*(this is again a JSON object)* -> name (this is string)

Look at the following code

Source https://stackoverflow.com/questions/67904179

QUESTION

R markdown can't knit

Asked 2021-Jun-07 at 01:38

I finished a project in R markdown and all I have to do is knit it as a word document, but there's this message error that I can't understand where I have made the mistake.

Error in yaml::yaml.load(..., eval.expr = TRUE) : Scanner error: mapping values are not allowed in this context at line 4, column 22 Calls: ... parse_yaml_front_matter -> yaml_load -> Execution halted

I looked at line 4 and it's just the date of the project and line 22 is an empty line so they're not the issue. Can anyone translate what the error means? Is it one of the chunk codes or any other error? Please and thank you These are the first 22 lines of the code(the language used is my country's language, just information):

...

ANSWER

Answered 2021-Jun-07 at 01:38

Indentation and newlines are important in YAML, change your header to

Source https://stackoverflow.com/questions/67864668

QUESTION

toggle menu button works on index page but not on other pages despite identical code- why?

Asked 2021-Jun-06 at 10:06

Spending hours trying to fix issue I am having with toggle menu button. Works perfectly on small screen on index page- but not working on portfolio & contact page. Despite same code & files (jquery & bootstrap files attached in same order). Any suggestions? Here is the website link: https://www.jophilippa.com/

...

ANSWER

Answered 2021-Jun-06 at 10:06

By quick look at your website & source code, you are linking to your jquery files by relative paths, to be more specific i mean this block of code:

Source https://stackoverflow.com/questions/67857873

QUESTION

How do I do a drag and drop using jQuery to move data between two or more divs and then trigger an update to the db on the drop?

Asked 2021-Jun-04 at 20:02

How do I do a drag and drop using jQuery UI to move data between two or more divs?

I'm using jQuery and this is in conjunction with an asp.net core api.

This would essentially be like a calendar, being able to move entries between days.

The tutorials I've looked at don't cover exactly what I need to do. New Divs (or elements) will be created dynamically, and I've been unable to get the drap/drop to work in the dynamically created divs, even after applying droppable()/draggable() to the new elements.

I've included the html page below and css in a mock-up. The mock-up doesn't include any dynmaically-added elements to keep it simpler for now.

There are a series of divs in the mock-up that represent days. Each day contains event items that can be moved around to different days. If you imagine this when connected to a data source, where it says Monday, Tuesday etc will display the date.

But first of all, I need help with understanding how I get what I currently have to work without absolute positioning.

Index.html:

...

ANSWER

Answered 2021-Jun-04 at 20:02

Consider using Sortable.

The jQuery UI Sortable plugin makes selected elements sortable by dragging with the mouse.

Here is a basic example.

Source https://stackoverflow.com/questions/67826796

QUESTION

Trying to overload operator<< in template class

Asked 2021-May-28 at 14:51

(this is an old exam for my current course)

I'm trying to overload operator<< in a template class but when I compile the code and run the program i get this message:

...

ANSWER

Answered 2021-May-28 at 14:51

There are few problems with your code.

Missing Constructor

Source https://stackoverflow.com/questions/67740486

QUESTION

Search in a string literal with a table field with peewee ORM

Asked 2021-May-21 at 16:40

I am trying to find all the records for which a certain field matches the beginning of a string literal provided as a fixed parameter. The needle is a field from a table.

Example: Given a parameter 'John Doe', I would like to get all the records of the table user, for which the first_name field is a sub-string of the beginning of that 'John Doe' string (e.g. matching records would be those for which the first_name is 'John', or 'Jo', or 'Joh', etc.

It seems I can achieve this with the following SQL:

SELECT * FROM user WHERE 'John Doe' LIKE first_name || '%'

Now how to translate that to peewee? It's strange that I am able to actually obtain the correct SQL for this but for some reason peewee is returning an empty result while the same query is working when I enter it directly via SQLite command line.

User.select().where(SQL("'John Doe'").startswith(User.first_name))

When I check the sql() of this, it shows:

('SELECT "t1"."id", "t1"."first_name" FROM "user" AS "t1" WHERE ("John Doe" LIKE ("t1"."first_name" || ?))', ['%'])

But the result is empty. Same SQL in the command line returns the right record... What am I doing wrong?

...

ANSWER

Answered 2021-May-21 at 12:45

This is how I would write it:

Source https://stackoverflow.com/questions/67627121

QUESTION

Error when inserting Hungarian text characters

Asked 2021-May-20 at 11:19

I'm trying to insert this text via SQL query

...

ANSWER

Answered 2021-May-20 at 10:15

This is likely to be a collation issue with the Text column in the target table.

Consider the following, which uses a Text column created with the latin1_general_ci collation:

Source https://stackoverflow.com/questions/67617860

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install jo

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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