bsie | Bootstrap IE6 Compatible Library | Theme library
kandi X-RAY | bsie Summary
kandi X-RAY | bsie Summary
bsie is a patch library for Bootstrap IE6 support, bootstrap is a good web UI library from twitter.com. At present, bsie support the most common feature of bootstrap on IE6, but not all ...
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QUESTION
I've been looking around the internet and I still can't find an answer. I have these set of codes which, of course, inserts data to an Access Database. It works fine, however, whenever we add a new data, it doesn't append but it replaces the previous data inserted (if I am making sense). I am not sure what could be wrong or missing.
Here's the full code:
...ANSWER
Answered 2021-May-26 at 15:22What you think is happening is almost certainly not happening. Many people don't know how local data files work in VS and are confused by the apparent behaviour.
When you add a data file to your project, it is stored in the project folder with the other source files. When you build your project, that source data file is copied to the output folder with your EXE and it is that copy that you work against while debugging. No changes are made to the original.
By default, the original source file is copied over the top of your test file every time you build your project. That means that any changes you made during previous tests will be lost. If you insert a record, quit the app, make a code change and then run the project again, the data you inserted will be lost, so inserting another record will look like it replaced the previous one.
The solution is generally to simply change that default behaviour of copying on every build. Select the data file in the Solution Explorer and set the Copy to output directory
property to Copy if newer
instead of Copy always
. That way, your test file will only be overwritten if you have made a change to the source file. You can then keep your changes across multiple debugging sessions. Simply delete the copy in the output folder and rebuild if you want to refresh it without changing the source file, or temporarily change that property back to Copy always
.
QUESTION
In my switch statement there's 3 options 2 are working properly and the third one shows what's I wrote in second instead of its own code.
I tried using case 1: , case 2: but it says that case 2: is not in the switch statement.
...ANSWER
Answered 2019-Feb-05 at 07:21the swith statement format is
QUESTION
Just practicing my positioning in HTML and CSS but I encounter this problem where I cannot change the position of the div for id=menu
and the source img doesn't display. I checked the syntax line-by-line, but I cannot spot the problem.
HTML:
...ANSWER
Answered 2017-Nov-22 at 04:13Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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