administrator | a fork from Frozennode/Administrator | Authorization library

The solution lies in the federated identity pool's settings.

By default the identity pool will provide the IAM role that it's configured with. In other words, one of either the "unauthenticated role" or the "authenticated role" that it's set up with.

But it can be told instead to provide a role specified by the authentication provider. That's what will solve the problem here.

1. In the AWS console, in Cognito, open the relevant identity pool.
2. Click "Edit identity pool" (top right)
3. Expand "Authentication Providers"
4. Under Authenticated Role Selection, choose "Choose role from token".

That will allow Cognito to specify its own roles, and you will find that the users get the privileges of their group.

Okay, so you want an app registration to manage an App Service through Azure Resource Management API as itself with client credentials flow? In that case you don't need to assign any application permissions to your app. You need to create the app, and then go to e.g. the App Service resource's Access Control (IAM) tab, and add the needed role to your app there.

The reason that the app permissions tab there is grey is because the Azure Service Management app registration (which you can't edit) does not define any app permissions. When you define an app permission in the manifest, that becomes a permission that other applications could use to call your API, not Azure Resource Management API.

Unfortunately doing this directly by attempting to web scrape the search results using UrlFetchApp will not work. You can use third party tools to get the number of search results, however.

I tested this out using an exponential backoff method which sometimes is able to get past 429 errors when a fetch request is invoked by UrlFetchApp.

When using UrlFetchApp to either web scrape or to connect to an API, it can happen that the server denies the request on the grounds of too many requests - or HTTP Error 429.

Google Apps Script runs in the cloud, from a set of IP addresses in a pool that Google own. You can actually see all the IP ranges here. Most websites (especially large companies such as Google) have architecture in place to prevent the use of bots scraping their websites and slowing down traffic.

Sometimes it's possible to get past this error, using a mixture of exponential backoff and random time intervals as shown for the Binance API (Full Disclosure: this GitHub repository was written by me.)

I assume that either Google directly blocks the Apps Script IP pool, or there are simply too many people trying the same thing - because with the same techniques I was unable to get any response that didn't involve entering a captcha as we discussed in the comments above and can be seen in the log of the page string.

There are many third party APIs that you can use to do this, and I suggest searching for one that meets your needs.

I tested out one called Authoritas which returns search engine indexing for different keywords. The API is asynchornous, so can take up to a minute to get a response, so a Web App solution needs to be made.

The flow I used is as follows:

• Obtain API key from Authoritas (free)
• Create a new Apps Script project to make an API call:

According to Named Pipe Security and Access Rights,

In addition to the requested access rights, the DACL must allow the calling thread FILE_CREATE_PIPE_INSTANCE access to the named pipe.

you don't need to group by ag.name since it would be the aggregation for the group :

You will need to pass the fetch/ajax method in Swal.fire call.

Set property "Copy to output directory" with value "Copy always" on the file if it's included in the project.

This error appears when there is no "=" substring in url. When you split string around substring there is at least one element in resulting array of tokens, more if substring appears in main string. I would add check if len of url.split('=') is greater than "i" before using i-th element. As it's right now you blindly go for second value even if there is only one.