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I had a similar problem with another module.

The solution I found was to update both node (to v16) and npm (to v8).

For Node, I used brew (but nvm should be OK).

For npm, I used what the official doc says :

npm install -g npm@latest

It turns out that the css-loader has configuration options just for this under options.url!

Thank you Alexander Akait from the Webpack team for answering my question here.

It has the option to pass an object that contains a filter() predicate function that should determine whether a path should be processed:

To get Vue/TypeScript/ESLint/Prettier/Vetur working in VSCode, I followed the following steps:

1. Installed the Vue eslint plugin by running vue add @vue/cli-plugin-eslint. NOTE: If you have a client folder directory and a server folder directory, you must first cd to your client directory before using vue add.
2. Changed the .eslintrc.js in my Vue project. Please check this post for more information/alternatives. Basically, I made a new Vue + Typescript project and copied the eslint config to my real project. The boilerplate code didn't work completely at first so I modified it a bit:

No, JavaScript doesn't have a "stricter" mode that would have warned you of this. Some linters might (though ESLint doesn't seem to, at least with the demo page's default settings).

TypeScript would have, though (example), since window.parent isn't a string or Symbol, so doesn't make sense as the left-hand operand of in. Adopting TypeScript has costs, of course, but it does have benefits like this.

I found a book on the Papaja package. That link will bring you to the YAML section. I think this is what you were looking for.

First, there doesn't appear to be an association for APA 7, unless you have the development version of Papaja. That being said, there is a ticket on this in their main github.

If you set the output to apa6_docx, this "and &" error won't be there. (And even if it were, you could have deleted it.) You can save it as a PDF from there. I'm not sure if this is an option for you, but I thought I would mention it.

This is what it states about subsequent authors (and much more).

The source S3 bucket policy is attached to the source S3 bucket, so you'll need to log into the source account to edit that.

The next steps have to be done from the CLI. The wording is a bit ambiguous but the key phrase is "ensure you’re using the same IAM identity you specified in the source S3 bucket policy created in the preceding step." The IAM identity referenced in the example S3 bucket policy is arn:aws:iam::DEST-ACCOUNT-ID:role/DEST-ACCOUNT-USER so you need to be authenticated to the destination account for the CLI steps. The aws sts get-caller-identity command just returns the identity used to execute the command, so it's there to confirm that you're using the expected identity rather than being strictly required for setting up the datasync location.

It's not explicitly mentioned in the tutorial but of course the user in the destination account needs appropriate IAM permissions to create the datasync locations and task.

It may help to think of it this way: you need to allow a role in the destination account to access the bucket in the source account, then you're setting up the Datasync locations and tasks in the destination account. So anything related to Datasync config needs to happen in the destination account.

You seem to be trying to use [^\\\"] to mean not the string \" but it doesn't mean that, it means neither the char \ nor the char ". You need to have a single char to negate in that part of the FPAT regexp so the approach is to convert every \" in the input to a single char that can't be present in the input (I use \n below as that's usually RS but you can use any char that can't be in the record), then split the record into fields, and then restore the \"s before using each individual field:

Solution 1: awk

You can use a single awk command:

GCC and Clang report that S is trivially copyable in C++11 through C++23 standard modes. MSVC reports that S is not trivially copyable in C++14 through C++20 standard modes.

N3337 (~ C++11) and N4140 (~ C++14) say:

A trivially copyable class is a class that:

• has no non-trivial copy constructors,
• has no non-trivial move constructors,
• has no non-trivial copy assignment operators,
• has no non-trivial move assignment operators, and
• has a trivial destructor.

By this definition, S is trivially copyable.

N4659 (~ C++17) says:

A trivially copyable class is a class:

• where each copy constructor, move constructor, copy assignment operator, and move assignment operator is either deleted or trivial,
• that has at least one non-deleted copy constructor, move constructor, copy assignment operator, or move assignment operator, and
• that has a trivial, non-deleted destructor

By this definition, S is not trivially copyable.

N4860 (~ C++20) says:

A trivially copyable class is a class:

• that has at least one eligible copy constructor, move constructor, copy assignment operator, or move assignment operator,
• where each eligible copy constructor, move constructor, copy assignment operator, and move assignment operator is trivial, and
• that has a trivial, non-deleted destructor.

By this definition, S is not trivially copyable.

Thus, as published, S was trivally copyable in C++11 and C++14, but not in C++17 and C++20.

The change was adopted from DR 1734 in February 2016. Implementors generally treat DRs as though they apply to all prior language standards by convention. Thus, by the published standard for C++11 and C++14, S was trivially copyable, and by convention, newer compiler versions might choose to treat S as not trivially copyable in C++11 and C++14 modes. Thus, all compilers could be said to be correct for C++11 and C++14.

For C++17 and beyond, S is unambiguously not trivially copyable so GCC and Clang are incorrect. This is GCC bug #96288 and LLVM bug #39050